How many rods of 12 rebar are in a ton?
Reinforcement is a set of interconnected elements that, when working together with concrete in reinforced concrete structures, perceive tensile stresses (although they can also be used to strengthen concrete in a compressed zone).
The main application of periodic profile reinforcing steel is in the construction of foundations and walls of buildings and structures made of monolithic concrete.
When carrying out concrete work, a significant investment of time and money requires the installation of a reinforced frame to reinforce structures made from reinforcing mesh.
To calculate the order volume, you need to know how many kg per meter of reinforcement and the number of linear meters of reinforcing steel.
The weight of a meter of reinforcement is presented in the table of the ratio of diameter and weight of 1 m. Knowing the weight of reinforcing steel according to GOST 5781-82, you can estimate the reinforcement coefficient of the structure (the ratio of the mass of the reinforcement to the volume of concrete) and determine how much material is needed for the foundation (per cube of concrete)
A linear meter of reinforcement is individual reinforcing bars of a smooth and periodic profile 1 meter long, the weight of which depends on the diameter of the reinforcing steel GOST 5781-82 (from a range of diameter sizes of periodic steel - 6, 8.10, 12, 14, 16, 18.20, 22, 25, 28, 32, 36, 40, 45, 50, 55, 60, 70, 80 mm).
How much does the reinforcing mesh weigh for screeding, performing plastering work, for making a reinforced concrete foundation frame (concrete + connected reinforcement bars), what is the weight of the reinforcing mesh for brickwork, depends on the size of the cards (length, width of the canvas), the size of the cell (square mm x mm ) and reinforcing wire diameter (mm).
Construction organizations use reinforcement produced in Ukraine, the weight of which meets the requirements of GOST, since domestic reinforcing steel is of sufficiently high quality and complies with all GOSTs and standards for rolled metal.
The weight of the reinforcement is selected depending on the types according to GOST, diameter sizes (see.
table - “Specific gravity of reinforcement in a linear meter”) and the scope of application of the periodic profile.
The weight of a linear meter of reinforcement depends on the shape of the surface of the periodic profile: corrugated or smooth on the outside. Protrusions in the form of ribs, corrugations on the surface of periodically profiled reinforcing steel bars or ribbed wire steel significantly improve adhesion to concrete and its characteristics.
The range of reinforcement, depending on the manufacturing technology of reinforcing steel for reinforced concrete structures, is divided into hot-rolled rod and cold-drawn wire steel.
The weight of 1 m of hot-rolled reinforcement does not depend on its basic mechanical characteristics, which are divided into six assortment classes depending on the strength of the metal and steel grade, with the symbol: AI, A-II, A-III, A-IV, AV, A- VI.
| Reinforcing steel class | Profile diameter, mm | Reinforcement steel grade |
| AI (A240) | 6-40 | St3kp, St3ps, St3sp |
| A-II (A300) | 10-40 40-80 | St5sp, St5ps 18G2S |
| Ac-II (Ac300) | 10-32 (36-40) | 10GT |
| A-III (A400) | 6-40 6-22 | 35GS, 25G2S 32G2Rps |
| A-IV (A600) | 10-32 (6-8)(36-40) | 80С 20ХГ2Ц |
| AV (A800) | (6-8) 10-32(36-40) | 23Х2Г2Т |
| A-VI (A1000) | 10-22 | 22Kh2G2AYu, 22Kh2G2R, 20Kh2G2SR |
For example, A3 construction reinforcement is used to strengthen concrete structures of prefabricated buildings and is widely used by construction companies in Kyiv. The actual weight of construction reinforcement consists of the mass of the reinforcement frames of the elements (foundation, walls, concrete floors) of a monolithic building, welded mesh, which are then filled with concrete mortar over the formwork.
The production of reinforcing steel in Ukraine is carried out using technologies developed in Soviet times in the field of metal processing, and, as a rule, on equipment inherited from the USSR, and that is why domestic manufacturers sell reinforcing steel at a fairly affordable price with good quality and compliance with GOST requirements .
Reinforcement 8, 10, 12, 14, 16, 18, 20, 22, 25 are the most popular in terms of the diameter of the periodic profile, sold by Ukrainian manufacturers. Imported analogues have a higher price.
Before being sold from metal warehouses, fittings in Ukraine undergo step-by-step quality control during the production process, which guarantees high quality that meets state standards GOST.
What is the weight of the reinforcement along its length?
The weight of the reinforcing steel required for purchase is calculated by multiplying the total length of all the bars in the bundle by the weight of a linear meter of reinforcement (see the table of mass 1 m and how many meters are in a ton of reinforcement). Conversion from meters to tons is carried out by multiplying the specific weight of the reinforcement (weight of 1 meter) by the number of linear meters.
Below is a table of reinforcement sections, the specific weight of 1 linear meter A1 (A240), A2 (A300), A3 (A400), A4 (A800), A5 (A800), A6 (A1000), the number of meters per ton to convert weight to total the length of all the rods in the package or coil.
The reinforcement in coils allows you to cut rods of any required length to size, which will reduce the amount of waste and eliminate the need to splice individual rods of standard length (6 or 12 meters).
Reinforcing steel weight table - How much does 1 m of reinforcement weigh?
| Diameter of fittings, mm | Weight of 1 meter of reinforcement, kg | Linear meters per ton | Maximum weight deviations in % |
| d 6 | 0,222 | 4504,5 | +9,0 -7,0 |
| d 8 | 0,395 | 2531,65 | +9,0 -7,0 |
| d 10 | 0,617 | 1620,75 | +5,0 -6,0 |
| d 12 | 0,888 | 1126,13 | +5,0 -6,0 |
| d 14 | 1,21 | 826,45 | +5,0 -6,0 |
| d 16 | 1,58 | 632,91 | +3,0 -5,0 |
| d 18 | 2 | 500 | +3,0 -5,0 |
| d 20 | 2,47 | 404,86 | +3,0 -5,0 |
| d 22 | 2,98 | 335,57 | +3,0 -5,0 |
| d 25 | 3,85 | 259,74 | +3,0 -5,0 |
| d 28 | 4,83 | 207,04 | +3,0 -5,0 |
| d 32 | 6,31 | 158,48 | +3,0 -4,0 |
| d 36 | 7,99 | 125,16 | +3,0 -4,0 |
| d 40 | 9,87 | 101,32 | -+3,0 -4,0 |
| d 45 | 12,48 | 80,13 | +3,0 -4,0 |
| d 50 | 15,41 | 64,89 | +2,0 -4,0 |
| d 55 | 18,65 | 53,62 | +2,0 -4,0 |
| d 60 | 22,19 | 45,07 | +2,0 -4,0 |
| d 70 | 30,21 | 33,1 | +2,0 -4,0 |
| d 80 | 39,46 | 25,34 | +2,0 -4,0 |
Calculation of the weight of reinforcement, welded mesh
If you don’t have a reinforcement calculation table or an online metal calculator at hand, then you can calculate the total weight of the reinforcing mesh yourself by determining the total length of the wire that makes up the welded mesh measuring 1 m2 and multiplying the number of meters by the specific weight of a linear meter of wire.
In the absence of a reference book, you can calculate the weight of a linear meter of reinforcement yourself, using a regular calculator. The volume of metal in 1 meter of steel cylinder is 1 m x (3.14 x D x D/4). In parentheses is the geometric area of a circle with diameter D. The weight of the rod is obtained by multiplying the volume by the specific weight of the reinforcement, which is equal to 7850 kg/m3.
Using this method, you can calculate how many kg are in a meter of reinforcement, and convert tons into meters.
For example, using a calculator, we will calculate the weight of 1 m of reinforcement with a diameter of 12 mm: Volume of metal - 1 m x (3.14 x 0.012 m x 0.012 m/4) = 0.00011304 m3,
Specific gravity - 0.00011304 m3 x 7850 kg/m3 = 0.887 kg. Approximately equal to the value in the table of reinforcement with theoretic weight.
If the length of the reinforcement is 12 m, then we substitute the required value of the rolled steel length into the formula and calculate the weight of the rods. To determine the weight of the mesh, you need to multiply the resulting mass of 1 m2 of mesh by the number of square meters in the welded reinforcement frame.
One more example. Let's calculate the weight of a 100x100x4 mesh with an area of 1 m2. The welded mesh consists of 18 welded reinforcing bars 1 m long. The total length of the rods will be 18x1=18 meters. The specific gravity of 4mm reinforcing wire is 0.092 kg/m. Then the mass of a linear meter of mesh with a height of 1 m will be 18x0.092 = 1.66 kg/m2 + 1% of the mass of welding materials.
Source: https://betfundament.com/skolko-hlystov-12-armatury-v-tonne/
How much does 1 meter of reinforcement 12 weigh?
Very often, reinforcement is used to strengthen a particular monolithic structure or casting. By definition, reinforcement is various kinds of rods and profiles consisting of metal structures of any type of metal.
In construction, this term is heard quite often, since the issue of strengthening the structure under construction is quite tough and acute. Basically, reinforcement is used as a means of connecting concrete mortar and its coupling between cast profiles of a building or structure.
Application of fittings
As a rule, the question of using one or another type of reinforcement is quite relevant, and often completely constant, among builders and engineers. The connection between these two specialties is quite simple. Each of them wants the structure they built to stand as long and as strong as possible. In addition, there are laws and regulations for this, established by the state construction standard.
To strengthen the structure under construction, reinforcing iron blanks of various strengths and thicknesses are used. Basically, their use is inextricably linked with the concept of reinforced concrete material. As a rule, a reinforced concrete element, be it a slab or a block, consists of some kind of frame - metal reinforcement, on which there is a shell of concrete mortar.
This type of building element can significantly increase the load per unit surface area. As a rule, such structures use metal of relatively soft density, such as an iron rod, channel and other workpieces.
But it happens that to strengthen the structure, denser and heavier material is used, for example, an angle, an I-beam or other rolled metals. According to their physical and construction characteristics, such reinforced concrete structures have a number of classifications, the basis of which is the strength class of reinforced concrete.
Thus, the following classes of reinforced concrete structures are distinguished:
- Hot rolling design.
- Manufactured concrete structures using thermal and chemical treatments.
- Durable.
- Thermally resistant design.
Certain characteristics assigned to the enormous strength and stability of reinforced concrete structures in construction depend on these classifications and a number of strengths.
For any building material, a distinctive characteristic is GOST, according to which manufacturers of reinforced concrete structural elements roll out the material. It is this standard that regulates the use of one or another type or strength class of reinforcement in concrete mortar.
Clutch nuances
As is clear, the mass of a given reinforcing bar 12 directly depends on what shape and what size it is. It is known that the plane of the rod reinforcement itself can have a smooth surface or have corrugation.
It is worth saying that the best adhesion to concrete mortar occurs due to the corrugated surface of the reinforcement, which is a kind of connecting link between the strength and hardness of the structure.
The entire range of reinforcing material varies depending on how and in what way it was produced. In other words, there are both hot-rolled and drawn rods. It is worth noting that the quality of hot-rolled reinforcement is much better than that of another system of reinforced concrete blocks. But reinforced concrete reinforcements produced by a cold roller have their own number of classifications and advantages in subclasses.
For the basis of correct adhesion of absolutely any reinforcement, it is necessary to know the weight and mass of the metal. It is on the basis of these parameters that one or another type of seam is formed, which is adapted to a given reinforcement. This can be either cold welding or ionic bonding of the metal.
Where is the reinforcement used?
The most common diameter in reinforcement for its use is a 12 mm layer. This diameter is considered the most convenient and optimal among similar reinforcement systems produced with similar diameters. It is also noteworthy that reinforcement with such a diameter is quite easy to bend and itself has a low mass. But when tied together, the reinforcement forms sufficient strength and hardness necessary to hold multi-ton structures.
Moreover, for the construction and erection of walls in cottages and private houses, according to the standard, a reinforced foundation must be used, which is reinforced with 12 mm reinforcement.
In this option, a strip foundation is used, which also provides for the installation of metal structures for pouring concrete.
To correctly calculate the cost of the required amount of reinforcement with a diameter of 12 millimeters, you need to know its weight over a length of one meter.
But such calculations are necessary only when the structure does not have a layout in the established order, or the process of replacing the reinforced foundation with a higher-quality layer of reinforced concrete occurs. All main characteristics of all structures must be recorded in the documentation for the construction of the facility.
How to calculate the weight of reinforcement?
In order to calculate the mass of the reinforcement used, you need to know some of the minimum parameters of a given metal structure, and these are:
For an accurate calculation, it is necessary to multiply the total length of the reinforcement used by its linear meter. Also, it is not difficult to calculate the cost of fittings. To do this, you need to know the price per meter of length of reinforcement with a diameter of 12 millimeters.
For ease of calculations, it is best to use a special table of reinforcement data, which is available in any specialized hardware store. These tables indicate the ratios of length, width and density of each reinforcing material, as well as their specific gravity calculated per cubic meter.
When purchasing a small quantity of reinforcement, its weight is indicated in kilograms. But if the purchase occurs in higher mass quantities, then tons are used to indicate weight. In any case, if you know the price of 1 meter of reinforcement with a diameter of 12 millimeters, you can easily calculate the cost of cash costs for the total length of the reinforcement.
Reinforcement weight
For the accuracy of construction work, as well as for calculating the funds spent on reinforcement, it is necessary to know its weight and other parameters.
Finding out the weight is quite simple: to do this, you need to add up the total weight of all the rods used for construction and divide the amount by the number of linear meters.
But linear meters have different price characteristics, which are also related to the parameters of the fittings, in particular the diameter. To do this, you need to use the calculation table of reinforcement parameters, which indicates that reinforcement with a diameter of 12 millimeters has a weight of 0.88 kilograms per length of one meter.
Obviously, to calculate the cost, it is necessary to know all the parameters of this type of reinforcement that are associated with the linear meter. So, in one ton of rods with a diameter of 12 millimeters there are 1126 meters of reinforcement.
Source: http://poznaibeton.ru/beton/ves-metra-armatury.html
Reinforcement weight, weight table (weight) per 1 meter of reinforcement
When carrying out construction and installation work, calculating the mass of metal products is extremely important, since it allows you to estimate the final parameters of the structures being built and determine the cost of the material (for this, the weight of the reinforcement is taken to be 10 mm per meter).
To carry out calculations, you can use special tables that indicate the parameters of the rods and their estimated weight, as well as popular online calculators, for the use of which you need to know the exact data on the technical characteristics of rolled metal.
Knowing the exact weight of rolled materials, you can save a lot by choosing the right vehicle to transport them. If you are not sure that you can make the calculations correctly, the Regional House of Metal company will help you find out the weight of 12 mm reinforcement per meter with extreme accuracy, since they will calculate it using a special formula. View available types of foundation reinforcement.
Rebar weight table
You can find out what mass the product has - reinforcement 12 weight 1 meter - from the tables that indicate:
- weight of one linear m of product;
- number of rolled meters in one ton;
- rolled diameter in millimeters;
- cross-sectional area of the rods in square centimeters;
- class of steel used in production.
| Assortment | Weight 1 meter | |
| Weight (theoretical), kg. | Limit deviations, % | |
| 6 | 0,222 | +9 / -7 |
| 8 | 0,395 | |
| 10 | 0,617 | +5 / -6 |
| 12 | 0,888 | |
| 14 | 1,21 | |
| 16 | 1,58 | +3 / -5 |
| 18 | 2,0 | |
| 20 | 2,470 | |
| 22 | 2,980 | |
| 25 | 3,850 | |
| 28 | 4,830 | |
| 32 | 6,310 | +3 / -4 |
| 36 | 7,990 | |
| 40 | 9,870 | |
| 45 | 12,480 | |
| 50 | 15,410 | +2 / -4 |
| 55 | 18,650 | |
| 60 | 22,190 | |
| 70 | 30,210 | |
| 80 | 39,460 |
In most cases, using a table, you will be able to find the desired value. If the table did not help determine the weight of 16 mm reinforcement per meter, you can resort to using an online size calculator to make calculations. To use it, you need to know the following parameters: rolled diameter, rod length and number.
The calculator will calculate the total mass for one rod, the total length of the rods, and the volume in cubic meters. There are also calculators that rely on reference data for calculations. To use them, you need to know the GOST according to which the rolled products are manufactured, the material of manufacture and the assortment (name of the rolled products).
There are also products for which this tool is not suitable, one of such products is masonry mesh, the page of which can be found here.
Weight of reinforcement
What to do if you don’t have an online calculator at hand, and you don’t really trust the data from tables on the Internet? It’s simple - you can determine the weight of 8 mm reinforcement per meter yourself using the most common calculator.
To find out the mass of a linear meter of rolled metal, you need to determine the total length of the rods, and then multiply the specific gravity of a linear meter of the product by the number of meters. The formula used for calculation is: 1 m x (3.14 x D x D/4). By performing the actions in brackets, we obtain the geometric area of a circle with a given diameter.
Did not you find what you were looking for? You may be interested in the page with pipeline valves, which can be found here: http://rdmetall.ru/truboprovodnaya-armatura/zatvory/.
Thus, we obtain the weight of a linear meter of reinforcement by multiplying the volume by the specific gravity of the product, equal to 7850 kilograms per cubic meter. An example of calculations for one m of a rod with a diameter of 8 millimeters.
Metal volume: 1 m x (3.14 x 0.008 m x 0.008 m/4) = 0.00005024. Specific gravity: 0.00005024 cubic meter x 7850 kilograms per cubic meter = 0.394384 kilograms.
You can substitute any value of D into the formula and obtain accurate data for any rolled metal, which will allow you to determine the cost of structures for construction.
Source: http://RDMetall.ru/armatura-dlya-fundamenta/ves-armatury/
How much does 10 meters of reinforcement weigh - Table of weight and number of meters per ton!
Reinforcing bars are mainly used to strengthen concrete. A mesh is knitted from them, so it absorbs the tensile force that goes to the concrete. In the construction sector, rolled products with a section size of 10 millimeters are very often used. And, in order to create a reinforced frame or mesh, you need to know the exact weight of the 10 mm reinforcement. per meter In this article we will talk specifically about this steel product.
The weight of the reinforcement is always determined by the GOST 5781-82 standard, it says what the mass and other parameters should be. The fittings are available in two types:
- hot rolled;
- cold rolled.
The rolled product itself is created in the form of metal rods or rods.
Reinforcement 10 mm weight 1 meter
To estimate the cost of construction, or finished objects, you need to know the exact mass of reinforced structures. Find out how much 10 mm reinforcement weighs. can be done in a simple way: we sum up the length and multiply by the linear weight of our rolled metal.
In order to find out the mass of a linear meter, you need to check the table, which displays all the dimensions, their weight and the number of meters per ton.
Table of weight and number of meters per ton of reinforcement with a diameter of 10 mm.
The weight of 1 meter of reinforcement measuring ten millimeters is presented in the table of the ratio of diameter and weight of one meter. Knowing the weight of reinforcing steel according to GOST 5781-82, you can estimate the rolling coefficient (the ratio of the mass of reinforcement to the volume of concrete) and calculate how many metal rods are needed (per cube of concrete ).
How much does 10 mm reinforcement weigh? Table.
Name Section size Weight of 1 meter| Armature | 10 mm. | The weight of 1 m is equal to 0.617 kg. |
How many meters of 10 mm reinforcement. in a ton? Table.
Name Section size Number of meters per ton| Armature | 10 mm. | There are 1620 m in 1 ton . |
Having the above table at hand, you will always know the exact quantity and weight of this steel product with the required cross-sectional diameter. It won’t be difficult to calculate the cost before purchasing, thereby saving yourself from unnecessary costs.
How to make an independent calculation?
Without tabular data, the total weight of the reinforcing mesh or the weight of one linear meter can be calculated using an online calculator, or you can do it yourself. To do this, the length of the reinforcing mesh rods, for example, with an area of 1 m2, is multiplied by the specific weight of one linear meter of reinforcement rods. The volume of steel for 1 m of the metal cylinder under study is equal to 1 meter x (∏ x D2 x / 4).
The weight of the reinforcing bar will be equal to the derivative of the resulting volume and the specific gravity of the reinforcement, which is equal to 7850 kg/m3. This simplified technique allows you to calculate the mass in kilograms of one meter of reinforcing bars, as well as convert the weight into units of length (meters).
domstrousam.ru
Reinforcement 10 mm weight 1 meter table
Steel reinforcement bars take on tensile forces when working in a mass of concrete, which the concrete itself does not tolerate well.
Tension of a structure occurs mainly when a load is applied to the foundation, so the main area of application of reinforcement is the foundations of construction projects and the walls of monolithic concrete structures.
The reinforcement is tied into a reinforcing frame, the fastening of periodic profile rods and smooth steel rods is carried out by wire binding or (in some cases) welding. Therefore, to create a reinforced frame or one reinforcing mesh, you need to know the weight and dimensions of the rods.
For example, 10 mm reinforcement weighs 1 meter a little more than half a kilogram - more accurate data on all diameters in accordance with the weight and length of the rods can be found in the table below:
| Ø, mm | Weight 1 m, kg | How many linear meters in one ton | Error, % |
| 6 | 0,22 | 4504,5 | +9/-7 |
| 8 | 0,39 | 2531,7 | +9/-7 |
| 10 | 0,618 | 1620,8 | +5/-6 |
| 12 | 0,88 | 1126,1 | +5/-6 |
| 14 | 1,2 | 826,5 | +5/-6 |
| 16 | 1,6 | 632,9 | +3/-5 |
| 18 | 2,0 | 500,0 | +3/-5 |
| 20 | 2,5 | 404,9 | +3/-5 |
| 22 | 3,0 | 335,6 | +3/-5 |
| 25 | 3,9 | 259,7 | +3/-5 |
| 28 | 4,8 | 207,0 | +3/-5 |
| 32 | 6,3 | 158,5 | +3/-4 |
| 36 | 7,9 | 125,2 | +3/-4 |
| 40 | 9,9 | 101,3 | +3/-4 |
| 45 | 12,5 | 80,1 | +3/-4 |
| 50 | 15,4 | 64,9 | +2/-4 |
| 55 | 18,7 | 53,6 | +2/-4 |
| 60 | 22,2 | 45,1 | +2/-4 |
| 70 | 30,2 | 33,1 | +2/-4 |
| 80 | 39,5 | 25,3 | +2/-4 |
Reinforcement by weight is selected in accordance with GOST 5781-82, which regulates the sizes of rods, their diameter, profile and other standards. The production of reinforcing bars can be cold- or hot-rolled; the reinforcement itself is made in the form of rods or wire.
The weight of 1 meter of hot-rolled reinforcement does not depend on the operating parameters of the material, which are classified in six property ranges according to strength and steel grade. Designation of fittings classes: A I, A II, A III, A IV, A V, A VI
| Class | Ø | Brand |
| A I (A 240) | 6-40 mm | St3KP, St3PS, St3SP |
| A II (A 300) | 10-40 mm40-80 mm | St5SSP, St5PS18G2S |
| AC II (AC 300) | 10-32 mm36-40 mm | 10GT |
| A III (A 400) | 6-40 mm6-22 mm | 35GS, 25G2S32G2RPS |
| A IV (A 600) | 10-32 mm6-8 mm36-40 mm | 80С20ХГ2Ц |
| A V (A 800) | 6-8 mm10-32 mm36-40 mm | 23Х2Г2Т |
| A VI (A 1000) | 10-22 | 22Kh2G2AYu, 22Kh2G2R, 20Kh2G2SR |
Weight of linear and linear meter of reinforcement
In practice, the mass of construction reinforcing bars is the sum of the weight of all the reinforced frames of the foundation or concrete walls of the object plus the weight of the reinforcing mesh that is placed in the concrete solution in the formwork. The most popular diameters of reinforcing bars in industrial and individual construction are from 8 to 25 mm, the profile is periodic (corrugated reinforcement). Rods and smooth rods of larger diameter indicated in the table are used only in industrial construction.
Weight table for steel building reinforcement
The weight of reinforcement that needs to be purchased is calculated as follows: first, the length of all reinforcement bars in the package is summed up, the result is multiplied by the weight of 1 linear meter of reinforcement - these values are indicated in the table. Knowing the total length of the rods, you can get the total weight.
To do this, you need to multiply the specific gravity of the reinforcement products by the length of the reinforcement in linear meters.
The table shows the cross-sections of reinforcement bars in relation to 1 linear meter of reinforcement of classes A 1 (A 240), A 2 (A 300), A 3 (A 400), A 4 (A 800), A 5 (A 800), A 6 (A 1000), as well as the total footage of rods in 1 ton.
Without tabular data, the total weight of the reinforcing mesh or the weight of 1 linear meter can be calculated using an online calculator or independently. To do this, the length of the reinforcing mesh rods, for example, with an area of 1 m2, is multiplied by the specific weight of 1 linear meter of reinforcement rods.
The volume of steel for 1 meter of the metal cylinder under study is equal to 1 meter x (∏ x D2 x / 4). The weight of the reinforcing bar will be equal to the derivative of the resulting volume and the specific gravity of the reinforcement, which is 7,850 kg/m3.
This simplified technique allows you to calculate the mass in kilograms of 1 meter of reinforcing bars, as well as convert the mass into units of length (meters).
jsnip.ru
Weight of reinforcement, weight of linear meter of reinforcement
When constructing elements of country houses from monolithic concrete, significant costs are required for structural reinforcement . The weight of reinforcement in a structure is calculated by multiplying the total length of all rods by the weight of a linear meter of reinforcement. The weight of a meter of reinforcement is taken from the table. Knowing the weight of the reinforcement, you can estimate the percentage of reinforcement of the structure (the ratio of the weight of the reinforcement to the volume of concrete) and calculate the market value of the reinforcement, since the price of rolled metal is calculated per kg.
The weight of a linear meter of reinforcement depends on the diameter
| Diameter of fittings, mm | Cross-sectional area, cm2 | Reinforcement weight, kg/m | Steel grade |
| 3 | 0,071 | 0,055(0,051) | Ordinary and high-tensile wire |
| 4 | 0,126 | 0,098(0,090) | Ordinary and high-tensile wire |
| 5 | 0,196 | 0,154(0,139) | Ordinary and high-tensile wire |
| 6 | 0,283 | 0,222 | A-III, ordinary and high-tensile wire |
| 7 | 0,385 | 0,302 | A-III, ordinary and high-tensile wire |
| 8 | 0,503 | 0,395 | A-III, ordinary and high-tensile wire |
| 9 | 0,636 |
Source: https://sk-amigo.ru/raznoe/skolko-vesit-metr-10-armatury-tablica-vesa-i-kolichestva-metrov-tonne.html
Weight of 1 meter of reinforcement - formula and table
During the construction process, an important parameter is the weight of the steel reinforcement, which is taken into account when designing the building. To calculate the mass of a batch of reinforcing bars, you need to know their diameter, mass per linear meter and total length.
Calculation of the weight of smooth and corrugated reinforcement: options
The mass of a linear meter of reinforcing bar can be determined in three ways: using the GOST 5781-82 , which determines the range of this metal product, using a formula and using an online calculator.
Determining the mass of reinforcing steel from the table
The table shows values calculated using nominal diameters and an average steel density of 7850 kg/m3. The nominal diameter of a grooved rod is equal to the nominal diameter of a rod with a smooth surface of the same profile number. This means that the table shows the masses per linear meter of a certain profile number, suitable for both smooth and grooved reinforcement products.
Weight table, kg, 1 linear meter of reinforcement with smooth and corrugated surface of classes A1 and A3
| Profile number (nominal rod diameter) | Theoretical mass 1 m, kg | Profile number (nominal rod diameter) | Theoretical mass 1 m, kg | Profile number (nominal rod diameter) | Theoretical mass 1 m, kg |
| 6 | 0,222 | 20 | 2,47 | 45 | 12,48 |
| 8 | 0,395 | 22 | 2,98 | 50 | 15,41 |
| 10 | 0,617 | 25 | 3,85 | 55 | 18,65 |
| 12 | 0,888 | 28 | 4,83 | 60 | 22,19 |
| 14 | 1,21 | 32 | 6,31 | 70 | 30,21 |
| 16 | 1,58 | 36 | 7,99 | 80 | 39,46 |
| 18 | 2,00 | 40 | 9,87 |
To determine the mass of a batch of metal products, the mass of 1 linear meter is multiplied by the total footage.
Calculation by formula
M = π *( D 2 /4)* ρ , in which:
M – mass of 1 m, kg,
D – nominal diameter, m,
ρ – density equal to 7850 kg/m3.
Calculation using an online calculator
Determining the weight of reinforcement (kg) by diameter and total length using an online calculator is the simplest and most convenient option.
Source: https://TreydMetall.ru/info/ves-1-metra-armatury-formula-i-tablica
Reinforcement weight table per 1 meter
Why might the weight of 1 meter of 12 mm reinforcement be required? For example, when pouring the foundation for a private house, builders can tell you the amount of reinforcement in meters, but at metal warehouses, as a rule, reinforcement is sold and the price per ton is indicated. In this case, knowing the weight of one meter, you can calculate how much reinforcement you will need in tons.
For greater convenience, we have provided a second table, which indicates how many meters of reinforcement are contained in one ton for each diameter.
Here's an example of a calculation:
You need 750 meters of 12mm a500c reinforcement (read: decoding of a500c reinforcement).
We look at the line in the first table corresponding to 12 mm reinforcement; the weight of 1 meter is 0.888 kg.
In total we get 750 * 0.888 = 666 kg.
Weight of 1 meter reinforcement table
Reinforcement diameter (mm) Weight kg/meter| 5,5 | 0,187 |
| 6 | 0,222 |
| 8 | 0,395 |
| 10 | 0,617 |
| 12 | 0,888 |
| 14 | 1,210 |
| 16 | 1,580 |
| 18 | 2,000 |
| 20 | 2,470 |
| 22 | 2,980 |
| 25 | 3,850 |
| 28 | 4,830 |
| 32 | 6,310 |
| 36 | 7,990 |
| 40 | 9,870 |
| 45 | 12,480 |
| 50 | 15,410 |
In industrial construction, a huge amount of reinforcement is used, which is most often supplied in tons. To perform the necessary calculations, you need to know the total length of the existing reinforcement; this can be easily done using the table below.
Calculation example:
You know that you have 25 tons of 10mm reinforcement.
Using the table, we find the number of meters in a ton corresponding to 10 mm reinforcement: 1620 meters.
Total total length of the reinforcement: 25 * 1620 = 40500 meters.
How many meters in 1 ton of reinforcement table
Diameter of reinforcement (mm) Meters per ton| 5,5 | 5347 |
| 6 | 4504 |
| 8 | 2531 |
| 10 | 1620 |
| 12 | 1126 |
| 14 | 826 |
| 16 | 633 |
| 18 | 500 |
| 20 | 405 |
| 22 | 335 |
| 25 | 260 |
| 28 | 207 |
| 32 | 158 |
Source: http://stroitelnyj-portal.ru/materialy-instrumenty/ves-armaturyi-tablitsa-za-1-metr.html
Reinforcement: weight per linear meter, formulas and calculation examples
In the total cost of construction, a significant portion falls on the reinforcement of reinforced concrete structures. In retail sales, the price is per linear meter. However, when constructing a foundation, a large amount of reinforcement is required, so it is cheaper to purchase it at wholesale stores. And the wholesale price is indicated in rubles/ton of products. This means that linear meters must somehow be converted into tons.
State standards indicate the weight of one linear meter of reinforcement of a specific diameter. To calculate the required kilograms or tons, you need to multiply the weight of one meter by the total length of all rods of the same diameter. By weight, by the way, the percentage of reinforcement of a reinforced concrete structure is also determined (the ratio of the mass of metal and the volume of concrete).
How to use the table
The table shows:
- Reinforcement diameter
- Sectional area of the rod
- Weight of one linear meter
- Steel grade
First, in the “diameter of reinforcement” column, you find the product with which you are going to reinforce the structure, then, moving along the horizontal line of the table, you look for the weight of a linear meter.
Table - weight per linear meter of reinforcement
If you don't have a table at hand
Not everyone has the necessary GOST, but each of us studied at school. To independently calculate the weight of a linear meter, basic knowledge of mathematics and physics is sufficient. Everyone knows that mass is equal to the volume of a body multiplied by the specific gravity of the material. The volume is calculated using the formula:
V = F x L, where
- V – body volume, m3
- F – its cross-sectional area, m2
- L – body length, m
The cross section of the reinforcement is a circle. Its area is easy to calculate, knowing the diameter of the rod:
F = 3.14 x D2/ 4 = 0.785 x D2, where
- D – reinforcement diameter (in meters)
- 3.14 – the well-known constant value π (it is dimensionless)
As you can see, calculating the cross-sectional area and volume of the rod is not difficult. Now you can calculate the weight of a linear meter. This is also done simply, using the formula:
M = V xp, where
- p – specific gravity of steel. It is equal to 7850 kg/m3.
There is some inaccuracy in these calculations: the reinforcement is not a smooth rod, and we do not take into account the dimensions of the corrugations. But if you calculate the weight of a meter rod in this way and compare it with the tabular data, you will see that your result is not much different from them.
Calculation examples
As examples, let us consider calculating the weight of a linear meter of reinforcement with the most common diameters of 6 mm and 12 mm of class A III. This material has a periodic profile (longitudinal ribs and transverse protrusions are applied to its forming surface). Special steel is used to manufacture A3 reinforcement. Thanks to the complex surface, metal and concrete form a single monolith.
Reinforcement with a diameter of 6 and 12 mm is used in the construction of dachas, private houses - for reinforcing strip foundations.
- Let's calculate the weight of a linear meter of A3 reinforcement with a diameter of 6 mm:
- Sectional area F = 3.14 x 0.006 x 0.006/ 4 = 0.000028 m2
- Volume per linear meter V = 0.000028 m2 x 1m = 0.000028 m3
- Weight M = 0.000028 m3 x 7850 kg/m3 = 0.221 kg
- Let's calculate the weight of a linear meter of reinforcement with a diameter of 12 mm:
- Sectional area F = 3.14 x 0.012 x 0.012/ 4 = 0.000113 m2
- Volume per linear meter V = 0.000113 m2 x 1 m = 0.000113 m3
- Weight M = 0.000113 m3 x 7850 kg/m3 = 0.887 kg
According to the GOST table, weight is 1 linear. m of reinforcement 6 is 0.222 kg, reinforcement 12 is 0.888 kg. As you can see, the discrepancy in numbers is small. It must be admitted, however, that the data presented in the table also does not claim to be highly accurate. They were also calculated theoretically.
In fact, the actual weight of a linear meter may differ from the table by 0.2 - 3%, both plus and minus.
on how to calculate the weight of building reinforcement
The video shows examples of calculating the weight of reinforcement, and also shows the calculation process in an online calculator.
How to calculate the weight of reinforcement in the Masmat program. You can calculate the weight of a linear meter of reinforcement of 16 mm, 32 mm and any other diameter sizes.
Source: http://MegaBeaver.ru/materials/armatura/armatura-ves-pogonnogo-metra-formuly-i-primery-rascheta.html
Reinforcement meter weight 12
If I understand correctly, then you are not interested in the weight of 12 mm reinforcement in general, but most likely the weight of one meter of reinforcement. This question could be asked in the Yandex PS a little differently: the weight of a meter of reinforcement is 12 mm, the weight of a linear meter of reinforcement is 12 mm, the conditional weight of reinforcement is 12 mm, the specific or theoretical weight of reinforcement is 12 mm, the calculated weight of reinforcement is 12 mm, and so on.
Despite the fact that these questions are formulated slightly differently, in general we are talking about the same thing. In fact, you want to calculate how much the 12 mm diameter reinforcement that you have in stock weighs, or the 12 mm reinforcement that you want to buy, but for some reason, it is not convenient for you to weigh the 12 mm reinforcement on a scale and it is more convenient to turn to reinforcement weight table. Such a table of reinforcement weights is in GOST for reinforcement.
From the reinforcement weight table, you need to find out the theoretical weight of one linear meter of reinforcement with a diameter of 12 mm.
Weight of reinforcement 12 mm diameter #8212; according to GOST
We did some not very complicated work for you, so that you do not need to download a free table of reinforcement weights or download the entire range of reinforcement, and we found the exact value of the mass of one linear meter of 12 mm reinforcement.
REINFORCEMENT WEIGHT 12 mm #8212; is 0.89 kg per linear meter.
How to use the value you found now: the weight of reinforcement 12 mm in diameter?
In fact, using the table for calculating the weight of reinforcement is very simple and convenient, although it looks somewhat #171;intimidating#187; at first glance. There are quite detailed tables of the weight of linear meta reinforcement . taking into account different types of fittings according to GOST (there are actually three of them). I'll show you with an example. So, for example, you want to buy 25 meters of reinforcement with a diameter of 12 mm.
Perhaps you need to reinforce the foundation for a fence or solve some other construction problem. When selling 12 mm reinforcement, the seller usually sets the price of the reinforcement in tons; it is in tonnage that he buys it at the factory. He sells you 12 mm reinforcement in meters, in linear meters, of which you need exactly 25 m. That is, the price of 12 mm reinforcement per ton does not tell you anything at all.
In order to somehow convert the number of linear meters of 12 mm reinforcement you have into categories close to: price per ton of 12 mm reinforcement, you need to calculate how much your 25 meters of reinforcement with a diameter of 12 mm weigh. We find line #8212 in the table for calculating the weight of reinforcement; the weight of a linear meter of 12 mm reinforcement (we have already done this for you #8212; see above), opposite shows the weight value of a meter of 12 mm reinforcement in kilograms #8212; 0.89 kg.
Now, knowing the weight of one meter of 12 mm reinforcement, we must multiply it by the number of meters #8212; 0.89 x 25 = 22.25 kg. That is, your 25 linear meters weigh exactly 22.25 kg. This is the THEORETICAL WEIGHT OF A METER OF REINFORCEMENT 12 mm in diameter.
Reinforcement weight 12 mm theoretical and actual
But the actual weight of the reinforcement 12 mm in diameter and its theoretical weight #8212; these are two different quantities. Unfortunately, the actual actual weight of the reinforcement never exactly coincides with the calculated theoretical weight of a linear meter of reinforcement specified in GOST. There are several reasons for this of a purely technical nature, features of the production of fittings, tolerances within a certain standard, and so on.
Therefore, when selling and purchasing 12 mm fittings, preference is ALWAYS GIVEN to the actual weight obtained when weighed on a scale. Not a single trading organization or company selling fittings will agree with the weight estimate obtained by calculation.
I won’t even mention the specifics of obtaining additional profit when selling fittings with a diameter of 12 mm, due to #171;fine-tuning the scales#187;. This is a separate topic. However, it is reasonable to practice CHECKING THE ACTUAL WEIGHT of 12 mm reinforcement by comparing the scale readings with the calculated or conditional weight of the reinforcement.
This allows you to avoid GROSS MISTAKES and significant overweighting of 12 mm fittings by an unscrupulous seller. You should always check the weight indicated by the seller of the fittings by #171;quick estimate#187; according to tabular data.
Source: https://armaturasila.ru/ves-armatury/ves-metra-armatury-12.html
Reinforcement weight 12 mm per meter table
Appearance of fittings.
When knitting frames, meshes, as well as when constructing a foundation, the main element is reinforcement. As for private construction, one of the most in demand here is rolled metal with a diameter of 12 millimeters. The favorable ratio of strength and affordable price allows you to use 12 mm reinforcement in the construction of a private house.
Why do you need to know the weight of rolled metal? This value will be needed to estimate the cost of construction work at different stages. Usually the weight is already calculated in the project for each structure where rolled metal A12, A3 or any other grade is used.
If you plan to do the construction calculations yourself or just want to understand this point in detail, then this material will answer all your questions.
After studying the article, the reader will be able to independently carry out calculations and find out the weight of reinforcement 12 mm, A3 or another brand.
Weight calculation
The calculation is performed in linear meters - special quantities usually used in construction work. The table also shows the weight of one linear meter. At the same time, reinforcement is sold by weight, and not by length. The builder's task is quite simple: find out how many meters are required for all structures, and then convert them into units of mass. Below is a detailed and simple table that will help you find out the weight of one linear meter. Weight calculation
In this table you need to find the required diameter (D), in this case it is 12 mm. The second column shows D - this data is not particularly needed, and converting 12 mm is quite simple (you need to divide 12 mm by 100, the result is 0.12 m).
The third column of the table is the most important - the mass m per kg is indicated here. A meter of rolled metal equals 12 millimeters to 0.888 kilograms. Also, as an example, you can take 10 mm rods, the weight of which is 0.617 kg.
The last column shows how many meters there are in one ton.
Calculator
Self-calculation
Now the reader knows how much one meter weighs. But in order to better understand the work, you need to understand the scheme by which the calculation is carried out. Having understood the essence, the builder will be able to calculate the weight of one linear meter of rods with a diameter of 12 or 10 mm.
To perform the calculation, you must proceed according to the following scheme:
The volume of one linear meter can be obtained using the following formula: 1m x (0.785 x D x D). Here the letter "D" represents the diameter of the circle. The total mass is multiplied with the specific gravity of the rods; in all cases it will be 7850 kg/m3.
To find out how much a meter weighs, you need to know the volume.
For example, you can independently calculate the mass of one meter of 10 mm reinforcement. The first step is to obtain the volume - 1m x (0.785 x 0.010 x 0.010) = 0.00010124 m3. The mass of rods is 10 mm – 00010124 m3 x 7850 = 0.616 kg. If you look at the table, one meter of reinforcement 10 weighs 0.617 kg. How much a meter of rods 14 or 16 weighs can be found using the same scheme.
Number of meters in one ton
A more detailed table, where the steel class is also present.
Above is the calculation for 10 mm. The number of meters per ton can also be calculated without using specialized tables. Here it is worth referring to the building regulations, which state that the strip base must contain at least 0.1% of rods in relation to the reinforced concrete structure. This formulation looks quite complicated.
To understand how this works, it’s worth looking at an example:
- A strip base is taken, the area of which is 2400 square cm.
- Next you will need a coefficient, for this formula it is 0.001.
- The resulting volume is multiplied with a coefficient - 2400 x 0.001 = 2.4 cm2.
- At the next stages, you won’t be able to do without reference information. Here you will need a manual that indicates the required number of rods.
For reinforcement with a diameter of 10 and 12 mm, two rods are sufficient.
What you need to know about A12 fittings
Rods are made from steel, the grade of which depends on the requirements for strength, wear and other parameters. Typically, builders choose rods made of low-alloy metal. It cannot be said that this is the most reliable and durable steel, but it does have an important advantage - low-alloy metal can be processed using arc welding.
Grade A12, like reinforcement with a diameter of 10 mm, is usually used to add strength to a structure made of reinforced concrete. Also, these rods are the main element in the construction of frame structures. In addition to this parameter, you also need to pay attention to rental, it differs by class:
- Periodic profile – A3. Class A3 fittings have transverse corrugation.
- Smooth profile – A1. Unlike A3, class A1 fittings come without corrugation.
You can purchase reinforcement, regardless of diameter or class A3, in coils or rods.
Source: http://jsnip.ru/stroitelnye-materialy/ves-armatury-12-mm-za-metr.html
Reinforcement weight table
Reinforcement is an integral part of any construction process when it comes to high-strength concrete structures. Reinforcement is used both in the construction of foundations and in the construction of heavy loaded floors.
You can also often find less massive structures in partitions and in certain types of finishing work.
The reinforcement, or more precisely the steel from which it is made, is subject to special requirements, which are standardized by GOST, and each reinforcing steel is used strictly depending on the load prescribed by the standards and external conditions.
Reinforcement parameters and weight
Each enterprise that deals with steel rolling complies with certain technical conditions that the fittings must comply with. First of all, this concerns weight. The reinforcement weight table can be used for various purposes - both to calculate transport costs and to calculate the load that the reinforced structure will exert. The table shows the main parameters for the most common types of reinforcing bars.
The weight of reinforcing steel is calculated by multiplying the total length of all rods by the weight of one linear meter; this is why such tables exist.
How many meters are there in a kilogram and how many kilograms are in a meter?
Naturally, whenever this table is needed, it will not be at hand. Therefore, in order to accurately calculate how many kilograms are in a meter of reinforcement, you need to proceed from the volume of the material. Calculating the weight of reinforcement along its length can only be done when we know its diameter exactly.
For an accurate calculation, we use a simple formula - 1m*(3.14*D*D/4). Thus, by calculating the volume of the reinforcement, you can easily find out its weight. To do this, you need to know the specific gravity of steel, which, according to reference books, is 7,850 kg/m³. Length by weight is calculated in the same way. Knowing the specific gravity of steel and the diameter of the reinforcement, you can easily operate with both the length and weight of the rod.
Application of reinforcing steel
Reinforcement, in principle, is a system of interconnected rods, which, when interacting with the concrete mixture, give the final product sufficient strength and rigidity. Reinforcement systems take on all the tensile, bending and compressive loads that a reinforced concrete structure must withstand.
Basically, periodic reinforcing steel is used in the construction of foundations, and is also often used in the construction of buildings by constructing walls by pouring permanent wall formwork with concrete mixture. For such construction, special types of concrete are used, but the requirements for reinforcing steel are the same. They are approved according to GOST 5781-82, and are observed by all metallurgical enterprises.
Dependence of the weight of reinforcement on various factors
As we have already found out, it is necessary to know the weight of the reinforcement during calculations that are carried out to determine the load that the reinforced structure will exert on other elements, or on the soil, if the calculations concern the construction of foundations. Also, construction engineers calculate the reinforcement coefficient of a structure based on the weight of the reinforcement and its volume, so parameters such as:
- Diameter of fittings.
- Weight per linear meter of reinforcement.
- Volume of fittings.
- The ratio of the volume of reinforcement to the volume of concrete.
- Reinforcing steel grade.
Vital to know in engineering calculations.
Reinforcing steel grade
The weight of any reinforcement is presented in the table that we have posted on the page, and the weight of a linear meter of reinforcement depends on its diameter. GOST clearly defines the standard size of diameters, which we presented in the table. This table also shows the class of steel from which the reinforcement itself is made.
The weight of a linear meter of reinforcement depends not only on the diameter, but also on the shape of the surface of the reinforcing rod or reinforcing wire. The profile can be either smooth or corrugated. The corrugated profile of the reinforcement is necessary in order to improve the adhesion of steel to the concrete mixture, as well as to give additional strength to the reinforcing rod or wire. Depending on the production technology of reinforcing steel, it is divided into three types:
- hot rolled;
- cold rolled;
- cold drawn wire.
It is noteworthy that the mass of a linear meter of hot-rolled steel does not depend on the basic mechanical characteristics it possesses. These characteristics are called steel classes and are designated by the letter A and a digital index.
Imported steel brands are similar in performance, but have slightly different markings and a higher price, so they are used extremely rarely.
Source: https://stroydetali.com/tablica-vesov-armatury_/
Reinforcement weight: table of specific gravity of 1 linear meter depending on diameter
20.05.2017
Reinforced concrete today is the most common material used in the construction of multi-story buildings, roads, tunnels, bridges and any other objects. Reinforcement is an important component of such structures - non-reinforced concrete, although it can withstand significant compressive loads, practically does not work in bending and tension, collapsing under relatively small loads.
But the use of metal rods - regular or prestressed - eliminates this drawback. Often builders find themselves in situations where they need to know the weight of reinforcement in order to calculate the required amount of material for construction. A table of reinforcement weights will help them with this.
You will find it below in the article, in the reinforcement table, the value of the mass of metal rods of all diameters is presented.
What does the mass of rods depend on?
Of course, first of all, the mass of the rod depends on the thickness. The larger the diameter, the greater the weight. Today, in construction, metal rods with a diameter of 6 to 80 millimeters are most often used.
The weight of 1 m of reinforcement, the thinnest, weighs only 222 grams, while for the thickest this figure is 39.46 kilograms. As you can see, the difference is huge.
Therefore, knowing the weight of the reinforcement will also not be superfluous when calculating the pressure of the structure on the foundation - several unaccounted tons of load can have a detrimental effect on the reliability and durability of any building.
How much does the fittings weigh?
In order to find out the reinforcement weight, the easiest and most convenient way is to use the special table presented below.
Rebar weight table
Diameter, mmWeight of 1 meter of reinforcement, kgLinear meters in ton| 6 | 0,222 | 4504,5 |
| 8 | 0,395 | 2531,65 |
| 10 | 0,617 | 1620,75 |
| 12 | 0,888 | 1126,13 |
| 14 | 1,21 | 826,45 |
| 16 | 1,58 | 632,91 |
| 18 | 2 | 500 |
| 20 | 2,47 | 404,86 |
| 22 | 2,98 | 335,57 |
| 25 | 3,85 | 259,74 |
| 28 | 4,83 | 207,04 |
| 32 | 6,31 | 158,48 |
| 36 | 7,99 | 125,16 |
| 40 | 9,87 | 101,32 |
| 45 | 12,48 | 80,13 |
| 50 | 15,41 | 64,89 |
| 55 | 18,65 | 53,62 |
| 60 | 22,19 | 45,07 |
| 70 | 30,21 | 33,1 |
| 80 | 39,46 | 25,34 |
All data indicated in this table fully comply with the current GOST. The error can be a maximum of a few percent - such errors will not cause significant trouble and will certainly not cause damage to the structure.
Having a table at hand, you can quickly calculate the weight of reinforcement, for example, with a diameter of 32 mm. Find the corresponding diameter in the first column and immediately find out that its mass is 6.32 kg per 1 m, and a ton includes 158.48 meters.
Why do you need to know the weight?
Professional builders often have a question: what is the weight of a linear meter of reinforcement. Why do they need this? The fact is that when purchasing rods for the construction of large structures, it is not purchased individually, as in individual construction, but in tons.
But it’s difficult to calculate how long a certain mass of material will last if you don’t know how much a meter of reinforcement weighs. Knowing the total mass and specific gravity of the reinforcement, 1 meter, you can make simple calculations in a matter of seconds, obtaining the total length of the metal rods.
To do this, we take the entire mass of the necessary rods and divide them by the weight of 1 linear meter.
Calculation example
To reinforce the beams, 2.5 tons of 25-diameter rods are required. We take the value of the mass of 1 meter from the table, equal to 3.85 kg. Next, we convert tons to kilograms, multiply by 1000, it will be 2500 kg, and divide by 3.85, we get 649 meters of material.
The standard length of a metal rod is 11.7 m, to find out the required number of rods, divide 649 by 11.7, we get 55.5 pieces. In this way, you can count the number of rods with any cross-section.
This will help, especially in private construction, to check that the correct amount of material has been delivered to you.
The opposite situation may also occur. The specialist knows how much material he needs, and also knows the optimal diameter. Having found out the theoretical weight of a meter of reinforcement, he just needs to multiply this number by the total length of the required metal rods to determine how much material is needed for construction.
Source: https://VseoArmature.ru/raschet/ves-armatury
Reinforcement weight. Weight per linear meter of reinforcement GOST 5781-82
Reinforcement is a set of interconnected elements that, when working together with concrete in reinforced concrete structures, perceive tensile stresses (although they can also be used to strengthen concrete in a compressed zone).
The main application of periodic profile reinforcing steel is in the construction of foundations and walls of buildings and structures made of monolithic concrete. When carrying out concrete work, a significant investment of time and money requires the installation of a reinforced frame to reinforce structures made from reinforcing mesh. To calculate the order volume, you need to know how many kg per meter of reinforcement and the number of linear meters of reinforcing steel.
The weight of a meter of reinforcement is presented in the table of the ratio of diameter and weight of 1 m. Knowing the weight of reinforcing steel according to GOST 5781-82, you can estimate the reinforcement coefficient of the structure (the ratio of the mass of the reinforcement to the volume of concrete) and determine how much material is needed for the foundation (per cube of concrete)
A linear meter of reinforcement is individual reinforcing bars of a smooth and periodic profile 1 meter long, the weight of which depends on the diameter of the reinforcing steel GOST 5781-82 (from a range of diameter sizes of periodic steel - 6, 8.10, 12, 14, 16, 18.20, 22, 25, 28, 32, 36, 40, 45, 50, 55, 60, 70, 80 mm - see RANGE OF FITTINGS).
How much does the reinforcing mesh weigh for screeding, performing plastering work, for making a reinforced concrete foundation frame (concrete + connected reinforcement bars), what is the weight of the reinforcing mesh for brickwork, depends on the size of the cards (length, width of the canvas), the size of the cell (square mm x mm ) and reinforcing wire diameter (mm).
Construction organizations use reinforcement produced in Ukraine, the weight of which meets the requirements of GOST, since domestic reinforcing steel is of sufficiently high quality and complies with all GOSTs and standards for rolled metal.
The weight of the reinforcement is selected depending on the types according to GOST, diameter sizes (see.
table - “Specific gravity of reinforcement in a linear meter”) and the scope of application of the periodic profile.
The weight of a linear meter of reinforcement depends on the shape of the surface of the periodic profile: corrugated or smooth on the outside. Protrusions in the form of ribs, corrugations on the surface of periodically profiled reinforcing steel bars or ribbed wire steel significantly improve adhesion to concrete and its characteristics.
The range of reinforcement, depending on the manufacturing technology of reinforcing steel for reinforced concrete structures, is divided into hot-rolled rod (A1 - A240, A2 - A300, A3 - A400, A500, A600, A800, A1000) and cold-drawn wire steel (VR-1).
The weight of 1 m of hot-rolled reinforcement does not depend on its basic mechanical characteristics, which are divided into six assortment classes depending on the strength of the metal and steel grade, with the symbol: AI, A-II, A-III, A-IV, AV, A- VI.
| Reinforcing steel class | Profile diameter, mm | Reinforcement steel grade |
| AI (A240) | 6-40 | St3kp, St3ps, St3sp |
| A-II (A300) | 10-40 40-80 | St5sp, St5ps 18G2S |
| Ac-II (Ac300) | 10-32 (36-40) | 10GT |
| A-III (A400) | 6-40 6-22 | 35GS, 25G2S 32G2Rps |
| A-IV (A600) | 10-32 (6-8) (36-40) | 80С 20ХГ2Ц |
| AV (A800) | (6-8) 10-32 (36-40) | 23Х2Г2Т |
| A-VI (A1000) | 10-22 | 22Kh2G2AYu, 22Kh2G2R,20Kh2G2SR |
For example, A3 construction reinforcement is used to strengthen concrete structures of prefabricated buildings and is widely used by construction companies in Kyiv. The actual weight of construction reinforcement consists of the mass of the reinforcement frames of the elements (foundation, walls, concrete floors) of a monolithic building, welded mesh, which are then filled with concrete mortar over the formwork.
The production of reinforcing steel in Ukraine is carried out using technologies developed in Soviet times in the field of metal processing, and, as a rule, on equipment inherited from the USSR, and that is why domestic manufacturers sell reinforcing steel at a fairly affordable price with good quality and compliance with GOST requirements .
Reinforcement 8, 10, 12, 14, 16, 18, 20, 22, 25 are the most popular in terms of the diameter of the periodic profile, sold by Ukrainian manufacturers. Imported analogues have a higher price.
Before being sold from metal warehouses, fittings in Ukraine undergo step-by-step quality control during the production process, which guarantees high quality that meets state standards GOST.
Table of weight of reinforcing steel. How much does 1m of reinforcement weigh?
| Diameter of fittings, mm | Weight of 1 meter of reinforcement, kg | Linear meters per ton | Maximum weight deviations in % |
| d 6 | 0,222 | 4504,5 | +9,0 -7,0 |
| d 8 | 0,395 | 2531,65 | +9,0 -7,0 |
| d 10 | 0,617 | 1620,75 | +5,0 -6,0 |
| d 12 | 0,888 | 1126,13 | +5,0 -6,0 |
| d 14 | 1,21 | 826,45 | +5,0 -6,0 |
| d 16 | 1,58 | 632,91 | +3,0 -5,0 |
| d 18 | 2 | 500 | +3,0 -5,0 |
| d 20 | 2,47 | 404,86 | +3,0 -5,0 |
| d 22 | 2,98 | 335,57 | +3,0 -5,0 |
| d 25 | 3,85 | 259,74 | +3,0 -5,0 |
| d 28 | 4,83 | 207,04 | +3,0 -5,0 |
| d 32 | 6,31 | 158,48 | +3,0 -4,0 |
| d 36 | 7,99 | 125,16 | +3,0 -4,0 |
| d 40 | 9,87 | 101,32 | -+3,0 -4,0 |
| d 45 | 12,48 | 80,13 | +3,0 -4,0 |
| d 50 | 15,41 | 64,89 | +2,0 -4,0 |
| d 55 | 18,65 | 53,62 | +2,0 -4,0 |
| d 60 | 22,19 | 45,07 | +2,0 -4,0 |
| d 70 | 30,21 | 33,1 | +2,0 -4,0 |
| d 80 | 39,46 | 25,34 | +2,0 -4,0 |
Calculation of the weight of reinforcement, welded mesh
If you don’t have a reinforcement calculation table or an online metal calculator at hand, then you can calculate the total weight of the reinforcing mesh yourself by determining the total length of the wire that makes up the welded mesh measuring 1 m2 and multiplying the number of meters by the specific weight of a linear meter of wire.
In the absence of a reference book, you can calculate the weight of a linear meter of reinforcement yourself, using a regular calculator. The volume of metal in 1 meter of a steel cylinder is 1 m x (3.14 x D x D/4) . In parentheses is the geometric area of a circle with diameter D. The weight of the rod is obtained by multiplying the volume by the specific weight of the reinforcement, which is equal to 7850 kg/m3.
Using this method, you can calculate how many kg are in a meter of reinforcement, and convert tons into meters.
For example, using a calculator, we will calculate the weight of 1 m of reinforcement with a diameter of 12 mm: Volume of metal - 1 m x (3.14 x 0.012 m x 0.012 m/4) = 0.00011304 m3,
Specific gravity - 0.00011304 m3 x 7850 kg/m3 = 0.887 kg. Approximately equal to the value in the table of reinforcement with theoretic weight.
If the length of the reinforcement is 12 m, then we substitute the required value of the rolled steel length into the formula and calculate the weight of the rods. To determine the weight of the mesh, you need to multiply the resulting mass of 1 m2 of mesh by the number of square meters in the welded reinforcement frame.
One more example. Let's calculate the weight of a 100x100x4 mesh with an area of 1 m2. The welded mesh consists of 18 welded reinforcing bars 1 m long. The total length of the rods will be 18x1=18 meters. The specific gravity of 4mm reinforcing wire is 0.092 kg/m. Then the mass of a linear meter of mesh with a height of 1 m will be 18x0.092 = 1.66 kg/m2 + 1% of the mass of welding materials.
Source: https://sbk.ltd.ua/ru/sortament-ves-metalloprokata/136-ves-pogonnogo-metra-armatury-gost-5781-82.html
How much does 1 meter of 14 reinforcement weigh?
When using rebar to strengthen foundations or other structures, an important question arises: how much does the rebar weigh? This is necessary in order to calculate the required volume of materials, since reinforcing bars are usually sold by weight.
How to calculate the weight of reinforcement?
“Weight classes” are best described in relation to their diameter. For clarity, we present them in the table.
Knowing the weight of 1 meter of reinforcement, you can determine the required quantity. For example, when strengthening the foundation, the required amount of reinforcement per meter is calculated, comparing it with the corresponding diameter, you can calculate the required quantity to order.
In addition, having knowledge of the weight of a meter of reinforcement makes it possible to estimate:
- reinforcement coefficient (weight of reinforcement divided by volume of poured concrete);
- required material for 1 cubic meter of foundation concrete.
How much does the reinforcement weigh in linear meters?
Here the weight according to GOST depends directly on the diameter, since each 1 m rod of different diameter will have a different weight. For example, you use d 20 material, which requires 200 meters in length. The weight of fittings in this category is 2.47 kg per meter, so you need to order 200x2.47 = 494 (kg). In addition, the weight, based on linear meters, depends on the nature of the profile surface: will it be corrugated or smooth.
The weight of a meter of mesh reinforcement for the frame of a reinforced concrete foundation, screed or plastering work, brickwork will depend on the size of the fabric, the cell, as well as on the diameter of the wire itself.
How much does a meter of reinforcement weigh based on length? For purchase, the calculation is carried out taking into account the total length of the rods that are in the pack and the weight of a linear meter (according to the table). In order to convert from meters to tons, the specific gravity is multiplied by the number of linear meters.
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Weight per linear meter of reinforcement, table
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Answers from forum users and experts to the question: How much does a meter of reinforcement weigh?
I can help you with this question because it was also the case that I was transporting fittings in the trunk. A meter of reinforcement weighs about 2 kilograms. but the point is not the weight, but how you fold it into the trunk, because you can take 5 meters if you fold it poorly, but you can take 10 meters. So when you fold, stack one on top of the other
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