How many bars of reinforcement 16 in a ton
How many bars of reinforcement 16 in a ton
Non-ferrous metals
- Aluminium, duralumin
- Copper, bronze, brass
- Tin
- Lead
- Zinc
The main value by which the amount of reinforcement is determined is its nominal diameter (d), regardless of whether the surface is smooth or with various types of corrugation. There is an option in which right and left entries are made on opposite sides of the rods to improve adhesion to concrete (used for high-strength steels).
The latter has the form of cylindrical rods with transverse protrusions formed along a helical line and two longitudinal ribs. Calculation of the number of meters of reinforcing bars in 1 ton. For foundations, reinforced concrete structures, and gas-block houses, round and periodic steel is used. This information is needed to determine the weight and cost of the structure, as well as for the correct organization of work during purchase and delivery to the construction site.
According to GOST 5781-82, hot-rolled reinforcement A240 - A1000 is produced (the letter A denotes the production method, and the number denotes the yield strength in MPa): In accordance with the standards, the cross-sectional areas of a periodic profile (non-circular) and having the shape of a circle of the same diameter are identical.
This problem arises due to the fact that the results of strength calculations for rods are presented in meters, but to buy them, data in tons is needed. The answer to the question, how many meters of reinforcement are in 1 ton, is of interest to both designers and builders.
Consequently, their masses per 1 meter are also equal.
How many bars of reinforcement 16 in a ton
see also
- HOW MUCH IS 12 MM REINFORCEMENT IN A TON? The weight of reinforcing steel according to GOST 5781-82 can be estimated by the reinforcement coefficient of the structure (the ratio of the mass of the reinforcement to the volume of concrete) and determined
- HOW MANY RODS ARE IN A TON OF REINFORCEMENT 14I recently got married and am now busy, so to speak, arranging my nest. But really, how many meters are there in 1 ton of 14 mm reinforcement? Want to
- HOW MANY RODS ARE IN A TON OF REINFORCEMENT
Source: https://trastmetal.ru/blog/skolko-prutkov-armatury-16-v-tonne
A12 mm fittings: characteristics, distinctive features, how much a linear meter weighs
Reinforcement refers to metal rods, rods or ropes of various shapes and cross-sections intended for construction work to fasten specialized structures. Reinforcement is indispensable in the manufacture of any types of devices made of reinforced concrete in order to enhance its strength.
According to its characteristics, it is divided into strength classes and comes in different diameters, which affects the effectiveness of its use in reinforced concrete building structures. This article will help answer the questions “How many meters are there in a ton of reinforcement?” and “How much does a meter of reinforcement weigh?”
In terms of labor costs in production, the presented rolled metal can be:
- light (with a diameter of up to 12 mm);
- heavy (with a diameter of 12 - 40 mm).
With a steel rod diameter of 12 mm, it is usually called reinforcement 12 ( A12 ) - this is the most popular rolled metal product in domestic construction.
Characteristics of A12 fittings
During the manufacturing process of A12, GOST 5781–82 is strictly observed, and according to its purpose it is classified into prestressed and non-prestressed . Based on the choice of production technology, the following types of fittings 12 are distinguished:
- cold drawn;
- hot rolled
Cold-drawn reinforcement A12 is necessary for the production of reinforced mesh; it is supplied in coils (rolls) of 6-12 meters and is a reinforcing wire.
Hot-rolled A12, being a high-quality type of rolled metal, is produced from steel with a rounded cross-section, and is used in the reinforcement of stressed and ordinary structures, imparts sufficient strength to reinforced concrete structures and prevents damage due to mechanical deformations.
Distinctive features of A12 fittings
These rolled metal products can be made from steel of different grades, which depends on its application and the requirements for its characteristics. Most often, products made from low-alloy structural steel are required. This is due to the fact that such products are easily subjected to arc welding.
The main purpose of A12 is the strengthening of reinforced concrete structures , as well as the formation of frame devices to resist increased loads. A diameter of 12 mm is the minimum for the construction of a strip foundation and its grillages, if you knit a reinforcement frame of four rods. Rentals by class are:
- smooth profile (without corrugation) - class A1;
- periodic profile (with transverse corrugation at an angle to the axis of the rod) - class A3.
This construction metal product is presented from the manufacturer in rods or coils . The scope of its application is very wide.
For the construction of the foundation, it is recommended to use hot-rolled reinforcement in the form of rods with oblique corrugation, the presence of which ensures optimal adhesion to concrete. This interaction of materials ensures the strength and durability of a reinforced concrete building structure.
The transverse arrangement of reinforced rods in the foundation prevents concrete cracking and reduces the force load on the resulting structure, and also protects it from deformation.
Advantages of A12 reinforcement , which are manifested in construction:
- high degree of strength;
- relatively high ductility;
- minimal susceptibility to corrosion;
- high resistance to thermal, chemical and mechanical influences;
- the ability to create various structural configurations by welding and mechanical connections;
- Possibility of use in stressed structures made of reinforced concrete.
There is currently a fairly large selection of grade steel on the construction raw materials market. Recently, there has been a gradual transition, using the example of Europe, to products made from A500C steel instead of the previously popular A400.
This fact, quite logically, is explained by the fact that while fully maintaining the quality characteristics of rolled products, its production cost is reduced by up to 10% due to savings in raw materials during construction operations.
For construction calculations, this amount of expenses is simply colossal.
A special feature of the production of rolled products from this steel grade is the absence of oxidation and, as a consequence, the absence of rust. At the same time, mechanical, chemical and thermal qualities remain at a very high level.
Replacement of steel grade A400 by grade A500C in rolled products makes it possible to reduce its concentration during concreting and, as a consequence, the consumption of A12 reinforcement. The technical characteristics of the steel used do not allow the welds of the finished structure to collapse.
All this leads to increased strength of floors, columns and walls of buildings.
Weight per linear meter of reinforcement 12
For construction work, it is customary to calculate the amount of reinforcement in linear meters, but it is sold mainly by weight.
It turns out that in order to buy the required amount of rolled metal and know exactly its cost, it is necessary to convert the calculated need in meters into weight units, that is, kilograms, tons, etc.
To do this, you can use the table presented . An alternative to the tabular data presented is to independently calculate the data based on the diameter size.
| Diameter, mm | Diameter, m | Weight of 1 meter, kg | Quantity m in 1t |
| 6 | 0.06 | 222 | 4504.5 |
| 8 | 0.08 | 395 | 2531.65 |
| 10 | 0.1 | 617 | 1620.75 |
| 12 | 0.12 | 888 | 1126.13 |
| 14 | 0.14 | 1210 | 826.45 |
| 16 | 0.16 | 1580 | 632.91 |
| 18 | 0.18 | 2000 | 500 |
| 20 | 0.2 | 2470 | 404.86 |
| 22 | 0.22 | 2980 | 335.57 |
| 25 | 0.25 | 3850 | 259.74 |
| 28 | 0.28 | 4830 | 207.04 |
| 32 | 0.32 | 6310 | 158.48 |
| 36 | 0.36 | 7990 | 125.16 |
| 40 | 0.4 | 9870 | 101.32 |
The weight of one meter of reinforced steel is shown in the table as the ratio of the diameter to its weight . Having information about the weight of reinforcing steel, it is possible to determine the coefficient of reinforcement of the structure (the ratio of the weight of rolled metal to the volume of concrete).
In order to calculate the need for reinforcement, you will need data on how many linear meters one ton of rolled metal contains. The number of meters in a ton is a value that depends on several factors. From the presented table it is clearly seen that the footage largely depends on the class of reinforcement.
How many meters are there in a ton of reinforcement 12?
In accordance with building regulations, the amount of reinforcement in a strip foundation as a percentage of the reinforced concrete element in the cross-section must be at least 0.1%. In an example it looks like this.
If the cross-sectional area of the strip foundation is 100*240=2400 square cm, then the estimated number of rolled rods for longitudinal reinforcement is found by multiplying the resulting volume of the foundation by 0.001, that is, 2400*0.001=2.4 square cm.
Next, you should resort to the reference data in the table from the manual on the reinforcement of reinforced concrete elements of monolithic buildings. Since we are interested in reinforcement with a diameter of 12, it is obvious that only 2 reinforced rods are needed for the calculated volume of the foundation. The calculation of the consumption of reinforced steel for a slab foundation is similar.
Source: https://plita.guru/raboty/armirovanie/skolko-vesit-armatura-12-mm-i-ee-osobennosti.html
Reinforcement weight 12 mm per meter table
Appearance of fittings.
When knitting frames, meshes, as well as when constructing a foundation, the main element is reinforcement. As for private construction, one of the most in demand here is rolled metal with a diameter of 12 millimeters. The favorable ratio of strength and affordable price allows you to use 12 mm reinforcement in the construction of a private house.
Why do you need to know the weight of rolled metal? This value will be needed to estimate the cost of construction work at different stages. Usually the weight is already calculated in the project for each structure where rolled metal A12, A3 or any other grade is used.
If you plan to do the construction calculations yourself or just want to understand this point in detail, then this material will answer all your questions.
After studying the article, the reader will be able to independently carry out calculations and find out the weight of reinforcement 12 mm, A3 or another brand.
Weight calculation
The calculation is performed in linear meters - special quantities usually used in construction work. The table also shows the weight of one linear meter. At the same time, reinforcement is sold by weight, and not by length. The builder's task is quite simple: find out how many meters are required for all structures, and then convert them into units of mass. Below is a detailed and simple table that will help you find out the weight of one linear meter. Weight calculation
In this table you need to find the required diameter (D), in this case it is 12 mm. The second column shows D - this data is not particularly needed, and converting 12 mm is quite simple (you need to divide 12 mm by 100, the result is 0.12 m).
The third column of the table is the most important - the mass m per kg is indicated here. A meter of rolled metal equals 12 millimeters to 0.888 kilograms. Also, as an example, you can take 10 mm rods, the weight of which is 0.617 kg.
The last column shows how many meters there are in one ton.
Calculator
Self-calculation
Now the reader knows how much one meter weighs. But in order to better understand the work, you need to understand the scheme by which the calculation is carried out. Having understood the essence, the builder will be able to calculate the weight of one linear meter of rods with a diameter of 12 or 10 mm.
To perform the calculation, you must proceed according to the following scheme:
The volume of one linear meter can be obtained using the following formula: 1m x (0.785 x D x D). Here the letter "D" represents the diameter of the circle. The total mass is multiplied with the specific gravity of the rods; in all cases it will be 7850 kg/m3.
To find out how much a meter weighs, you need to know the volume.
For example, you can independently calculate the mass of one meter of 10 mm reinforcement. The first step is to obtain the volume - 1m x (0.785 x 0.010 x 0.010) = 0.00010124 m3. The mass of rods is 10 mm – 00010124 m3 x 7850 = 0.616 kg. If you look at the table, one meter of reinforcement 10 weighs 0.617 kg. How much a meter of rods 14 or 16 weighs can be found using the same scheme.
Number of meters in one ton
A more detailed table, where the steel class is also present.
Above is the calculation for 10 mm. The number of meters per ton can also be calculated without using specialized tables. Here it is worth referring to the building regulations, which state that the strip base must contain at least 0.1% of rods in relation to the reinforced concrete structure. This formulation looks quite complicated.
To understand how this works, it’s worth looking at an example:
- A strip base is taken, the area of which is 2400 square cm.
- Next you will need a coefficient, for this formula it is 0.001.
- The resulting volume is multiplied with a coefficient - 2400 x 0.001 = 2.4 cm2.
- At the next stages, you won’t be able to do without reference information. Here you will need a manual that indicates the required number of rods.
For reinforcement with a diameter of 10 and 12 mm, two rods are sufficient.
What you need to know about A12 fittings
Rods are made from steel, the grade of which depends on the requirements for strength, wear and other parameters. Typically, builders choose rods made of low-alloy metal. It cannot be said that this is the most reliable and durable steel, but it does have an important advantage - low-alloy metal can be processed using arc welding.
Grade A12, like reinforcement with a diameter of 10 mm, is usually used to add strength to a structure made of reinforced concrete. Also, these rods are the main element in the construction of frame structures. In addition to this parameter, you also need to pay attention to rental, it differs by class:
- Periodic profile – A3. Class A3 fittings have transverse corrugation.
- Smooth profile – A1. Unlike A3, class A1 fittings come without corrugation.
You can purchase reinforcement, regardless of diameter or class A3, in coils or rods.
Source: http://jsnip.ru/stroitelnye-materialy/ves-armatury-12-mm-za-metr.html
Reinforcement: weight per linear meter, formulas and calculation examples
In the total cost of construction, a significant portion falls on the reinforcement of reinforced concrete structures. In retail sales, the price is per linear meter. However, when constructing a foundation, a large amount of reinforcement is required, so it is cheaper to purchase it at wholesale stores. And the wholesale price is indicated in rubles/ton of products. This means that linear meters must somehow be converted into tons.
State standards indicate the weight of one linear meter of reinforcement of a specific diameter. To calculate the required kilograms or tons, you need to multiply the weight of one meter by the total length of all rods of the same diameter. By weight, by the way, the percentage of reinforcement of a reinforced concrete structure is also determined (the ratio of the mass of metal and the volume of concrete).
How to use the table
The table shows:
- Reinforcement diameter
- Sectional area of the rod
- Weight of one linear meter
- Steel grade
First, in the “diameter of reinforcement” column, you find the product with which you are going to reinforce the structure, then, moving along the horizontal line of the table, you look for the weight of a linear meter.
Table - weight per linear meter of reinforcement
If you don't have a table at hand
Not everyone has the necessary GOST, but each of us studied at school. To independently calculate the weight of a linear meter, basic knowledge of mathematics and physics is sufficient. Everyone knows that mass is equal to the volume of a body multiplied by the specific gravity of the material. The volume is calculated using the formula:
V = F x L, where
- V – body volume, m3
- F – its cross-sectional area, m2
- L – body length, m
The cross section of the reinforcement is a circle. Its area is easy to calculate, knowing the diameter of the rod:
F = 3.14 x D2/ 4 = 0.785 x D2, where
- D – reinforcement diameter (in meters)
- 3.14 – the well-known constant value π (it is dimensionless)
As you can see, calculating the cross-sectional area and volume of the rod is not difficult. Now you can calculate the weight of a linear meter. This is also done simply, using the formula:
M = V xp, where
- p – specific gravity of steel. It is equal to 7850 kg/m3.
There is some inaccuracy in these calculations: the reinforcement is not a smooth rod, and we do not take into account the dimensions of the corrugations. But if you calculate the weight of a meter rod in this way and compare it with the tabular data, you will see that your result is not much different from them.
Calculation examples
As examples, let us consider calculating the weight of a linear meter of reinforcement with the most common diameters of 6 mm and 12 mm of class A III. This material has a periodic profile (longitudinal ribs and transverse protrusions are applied to its forming surface). Special steel is used to manufacture A3 reinforcement. Thanks to the complex surface, metal and concrete form a single monolith.
Reinforcement with a diameter of 6 and 12 mm is used in the construction of dachas, private houses - for reinforcing strip foundations.
- Let's calculate the weight of a linear meter of A3 reinforcement with a diameter of 6 mm:
- Sectional area F = 3.14 x 0.006 x 0.006/ 4 = 0.000028 m2
- Volume per linear meter V = 0.000028 m2 x 1m = 0.000028 m3
- Weight M = 0.000028 m3 x 7850 kg/m3 = 0.221 kg
- Let's calculate the weight of a linear meter of reinforcement with a diameter of 12 mm:
- Sectional area F = 3.14 x 0.012 x 0.012/ 4 = 0.000113 m2
- Volume per linear meter V = 0.000113 m2 x 1 m = 0.000113 m3
- Weight M = 0.000113 m3 x 7850 kg/m3 = 0.887 kg
According to the GOST table, weight is 1 linear. m of reinforcement 6 is 0.222 kg, reinforcement 12 is 0.888 kg. As you can see, the discrepancy in numbers is small. It must be admitted, however, that the data presented in the table also does not claim to be highly accurate. They were also calculated theoretically.
In fact, the actual weight of a linear meter may differ from the table by 0.2 - 3%, both plus and minus.
on how to calculate the weight of building reinforcement
The video shows examples of calculating the weight of reinforcement, and also shows the calculation process in an online calculator.
How to calculate the weight of reinforcement in the Masmat program. You can calculate the weight of a linear meter of reinforcement of 16 mm, 32 mm and any other diameter sizes.
Source: http://MegaBeaver.ru/materials/armatura/armatura-ves-pogonnogo-metra-formuly-i-primery-rascheta.html
Specific gravity and weight of 12 mm reinforcement based on the GOST table
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Hot-rolled round steel of smooth or periodic profile with a diameter of 12 (mm) and a length of 1000 (mm), has a mass of 0.888 (kg).
Correspondence table for reinforcement weights for different diameters
The standard weight of reinforcement of a particular diameter is regulated by GOST 5781-82 standards. The standard calculation table looks like this:
Table of correspondence of reinforcement weight depending on the diameter of the rods
This table is absolutely easy to use. In the first column we select the diameter of the rod in mm that will be used, in the second column we immediately see the weight of one linear meter of a rod of this type.
The third column shows us the number of linear meters of reinforcement in one ton.
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Calculation of reinforcement weight
There are several ways to calculate the mass of reinforcing bars required for construction.
The first and easiest way to find out how much a meter of reinforcement weighs is to use an electronic calculator for similar calculations.
To work with it, you only need to know the diameter of the rod with which we will work. All other calculation parameters are already included in the program.
The other two ways to find out how heavy a reinforcement meter is are somewhat more complicated. Let's look at them in order of increasing complexity.
Since in private construction reinforcement with a diameter of 12 mm and 14 mm is most often used, we will take these rods as the basis for the calculations.
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Example of calculating the weight of reinforcement (video)
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: Composition and purpose of Christmas tree fittings - piping diagram
Theoretical weight, weight of 1 linear meter of corrugated steel reinforcement A3 (A500C / S500)
| Diameter of fittings, mm | Weight of 1 linear meter of fittings, kg | Number of meters of reinforcement in 1 ton | Cross-sectional area of reinforcement, cm2 |
| 6 | 0,222 | 4504,5 | 0,283 |
| 8 | 0,395 | 2531,65 | 0,503 |
| 10 | 0,617 | 1620,75 | 0,785 |
| 12 | 0,888 | 1126,13 | 1,131 |
| 14 | 1,21 | 826,45 | 1,54 |
| 16 | 1,58 | 632,91 | 2,01 |
| 18 | 2 | 500 | 2,54 |
| 20 | 2,47 | 404,86 | 3,14 |
| 22 | 2,98 | 335,57 | 3,8 |
| 25 | 3,85 | 259,74 | 4,91 |
| 28 | 4,83 | 207,04 | 6,16 |
| 32 | 6,31 | 158,48 | 8,04 |
| 36 | 7,99 | 125,16 | 10,18 |
| 40 | 9,87 | 101,32 | 12,57 |
| 45 | 12,48 | 80,13 | 15 |
| 50 | 15,41 | 64,89 | 19,63 |
| 55 | 18,65 | 53,62 | 23,76 |
| 60 | 22,19 | 45,07 | 28,27 |
| 70 | 30,21 | 33,1 | 38,48 |
| 80 | 39,46 | 25,34 | 50,27 |
How much does A3 A500C / S500 corrugated steel reinforcement weigh? How to calculate the weight of reinforcement? How to convert linear meters to kilograms and tons? You will find the answers to these questions in the table above for calculating the weight of reinforcement depending on the diameter. Weight of reinforcement, theoretical weight of 1 linear meter of reinforcement, number of meters of reinforcement in 1 ton.
On the website of the Aksvil metal warehouse you can buy fittings in Minsk wholesale and retail.
Calculation based on standard weight
To calculate the mass of the required number of rods using this method, we use the table above. We are interested in the parameter, how much one linear meter weighs. In the calculations we will use rods with a diameter of 14 mm.
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Let's calculate the amount of reinforcement needed for construction (provided that we have the table at hand).
To calculate the weight of the amount of reinforcement we need, we should:
- Draw up a building construction plan taking into account the creation of a reinforcement mesh.
- Decide on the diameter of the rods.
- Calculate the amount of reinforcement used in meters.
- Multiply the mass of one meter of reinforcement of the required diameter by the number of rods used.
Example: 2322 meters of reinforcing bars with a diameter of 14 mm will be used for construction. The weight of a linear meter of such rods is 1.21 kg. We multiply 2322 * 1, kilogram 62 grams (grams can be neglected). For construction we will need 2 tons 809 kilograms of metal rods.
An example of calculating the weight of reinforcement in a special program
In the same simple way, you can calculate the number of rods of any diameter per ton, based on the data given in the table.
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Calculation by specific gravity
This method of calculation requires certain knowledge, skills and labor. It is based on a formula for calculating mass, which uses quantities such as the volume of a figure and its specific gravity. It is worth resorting to this method of calculating a linear meter of reinforcement only if you have neither an electronic calculator nor a table with GOST standards at hand.
We will try this method by calculating how much 12-diameter reinforcement weighs. First of all, let’s remember the weight formula from the physics course.
Metal reinforcement bars
Weight is equal to the volume of the figure multiplied by its density. The density, or specific gravity, of steel is 7850 kg/m3.
As for the volume, we will also have to calculate it ourselves, based on the fact that the reinforcing bar is a cylinder. Let's return to the school geometry course.
The volume of a cylinder is equal to its cross-sectional area multiplied by the height of the cylinder. The cross section of a cylinder is a circle. The area of a circle is calculated by the formula Pi (a constant value equal to 3.14) multiplied by the radius squared. The radius is equal to half the diameter.
We must know the diameter of the reinforcement based on the construction plan and calculations, or measure it ourselves.
Note: measuring the diameter yourself will lead to errors in calculations, since the reinforcement does not have a smooth outer surface.
Fragments of reinforcement bars of various diameters
In our case, the diameter is 12 mm or 0.012 m. Therefore, the radius is 6 mm or 0.006 m.
- We calculate the area of the circle: 3.14*0.0062 =0.00011304 m2.
- We calculate the volume of one meter of reinforcement: 0.00011304*1=0.00011304 m3
- We calculate the weight of one linear meter: 0.00011304 m3*7850 kg/m3=0.887 kg.
Checking the table, we see that the data obtained coincides with the state data.
If you need to calculate the mass of not one meter, but a specific reinforcing bar, the area of the circle will need to be multiplied by the length of the rod. Otherwise, the calculation algorithm will not change.
Scope of application and calculation of the weight of reinforcement 10 mm per meter
One of the most popular in construction is a rod with a diameter of 10 millimeters. Such reinforcement, like rods of other thicknesses, is produced by hot-rolled or cold-rolled methods. These are metal rods of medium thickness with a high degree of strength.
10 mm reinforcement is used to create lightweight buildings: private houses, garages, where strip foundation pouring is used
Calculating the total weight of reinforcement 10 is quite simple: just sum up the total length and multiply it by the mass of a linear meter of material. The necessary data can be found in the general table.
The general characteristics of fittings 10 are as follows:
- rod diameter – 10 mm;
- there are 1622 m of rolled products in one ton;
- weight of 1 meter of 10 mm reinforcement – 616.5 g;
- the permissible error when calculating weight is +6%;
- steel classes used in the production of this type of rolled metal: At-400, At-500S, At-600, At-600K, At-800K, At-1000, At-1000K, At-1200.
With the given parameters, you can easily find out the required quantity and weight of building material. It’s quite easy to do an independent calculation using the formula you’ve already written; it will look like this:
1m*(3.14*0.01m*0.01m/4)*7850 kg/m³=0.617 kg. A similar indicator of the weight of 1 meter of reinforcement 10 is contained in the table of the ratio of diameter and weight of one meter.
10 mm reinforcement is classified as an easily processed material, since the rod is easily bent or subjected to any other necessary deformation
How many meters of twelve-millimeter reinforcement in one ton
The tables, developed taking into account GOST for fittings, provide the following data on the number of meters contained in a ton of rolled metal:
Number of meters of reinforcement per ton
- diameter 5 millimeters - 5347 meters;
- 6 mm – 4504 m;
- 8 – 2531;
- 10 – 1620;
- 12 – 1126;
- 14 – 826;
- 16 – 633.
From the excerpt of the table values it is clear that one ton contains 1126 meters of reinforcement with a cross-section of 12 mm. Standardized indicators are aimed at facilitating the process of calculating the number of reinforcing bars required to create various types of foundations or other structures.
: Types of reinforcement - classification according to main characteristics
Advantages of 12 mm reinforcement
Twelve-millimeter metal products have a number of advantages, manifested in the following areas:
Laying reinforcement in the future foundation
- high level of strength of frames made using reinforcing bars;
- sufficient plasticity of the material;
- minimal risk of corrosion damage;
- high degree of resistance to influences such as chemical, thermal, mechanical;
- wide possibilities for various frame configurations;
- use in stressed reinforced concrete structures.
The results of calculations carried out using tables, formulas and calculators are average values, since in reality reinforcing bars do not have a perfectly round cross-section. The data obtained will be sufficient to determine the required quantity of rolled metal.
An important point in calculations is the fact that the calculated and actual weight of 12 mm reinforcement may differ from each other. Despite the careful control of GOST, metal rods are made from different types of steel and with different surfaces, and therefore the deviation of values varies in the range of 0.2–3%.
Classification of fittings GOST R-52544-2006
Source: https://tpspribor.ru/izdeliya-iz-metalla/massa-armatury-12-mm.html
Reinforcement weight. Weight per linear meter of reinforcement GOST 5781-82
Reinforcement is a set of interconnected elements that, when working together with concrete in reinforced concrete structures, perceive tensile stresses (although they can also be used to strengthen concrete in a compressed zone).
The main application of periodic profile reinforcing steel is in the construction of foundations and walls of buildings and structures made of monolithic concrete. When carrying out concrete work, a significant investment of time and money requires the installation of a reinforced frame to reinforce structures made from reinforcing mesh. To calculate the order volume, you need to know how many kg per meter of reinforcement and the number of linear meters of reinforcing steel.
The weight of a meter of reinforcement is presented in the table of the ratio of diameter and weight of 1 m. Knowing the weight of reinforcing steel according to GOST 5781-82, you can estimate the reinforcement coefficient of the structure (the ratio of the mass of the reinforcement to the volume of concrete) and determine how much material is needed for the foundation (per cube of concrete)
A linear meter of reinforcement is individual reinforcing bars of a smooth and periodic profile 1 meter long, the weight of which depends on the diameter of the reinforcing steel GOST 5781-82 (from a range of diameter sizes of periodic steel - 6, 8.10, 12, 14, 16, 18.20, 22, 25, 28, 32, 36, 40, 45, 50, 55, 60, 70, 80 mm - see RANGE OF FITTINGS).
How much does the reinforcing mesh weigh for screeding, performing plastering work, for making a reinforced concrete foundation frame (concrete + connected reinforcement bars), what is the weight of the reinforcing mesh for brickwork, depends on the size of the cards (length, width of the canvas), the size of the cell (square mm x mm ) and reinforcing wire diameter (mm).
Construction organizations use reinforcement produced in Ukraine, the weight of which meets the requirements of GOST, since domestic reinforcing steel is of sufficiently high quality and complies with all GOSTs and standards for rolled metal.
The weight of the reinforcement is selected depending on the types according to GOST, diameter sizes (see.
table - “Specific gravity of reinforcement in a linear meter”) and the scope of application of the periodic profile.
The weight of a linear meter of reinforcement depends on the shape of the surface of the periodic profile: corrugated or smooth on the outside. Protrusions in the form of ribs, corrugations on the surface of periodically profiled reinforcing steel bars or ribbed wire steel significantly improve adhesion to concrete and its characteristics.
The range of reinforcement, depending on the manufacturing technology of reinforcing steel for reinforced concrete structures, is divided into hot-rolled rod (A1 - A240, A2 - A300, A3 - A400, A500, A600, A800, A1000) and cold-drawn wire steel (VR-1).
The weight of 1 m of hot-rolled reinforcement does not depend on its basic mechanical characteristics, which are divided into six assortment classes depending on the strength of the metal and steel grade, with the symbol: AI, A-II, A-III, A-IV, AV, A- VI.
| Reinforcing steel class | Profile diameter, mm | Reinforcement steel grade |
| AI (A240) | 6-40 | St3kp, St3ps, St3sp |
| A-II (A300) | 10-40 40-80 | St5sp, St5ps 18G2S |
| Ac-II (Ac300) | 10-32 (36-40) | 10GT |
| A-III (A400) | 6-40 6-22 | 35GS, 25G2S 32G2Rps |
| A-IV (A600) | 10-32 (6-8) (36-40) | 80С 20ХГ2Ц |
| AV (A800) | (6-8) 10-32 (36-40) | 23Х2Г2Т |
| A-VI (A1000) | 10-22 | 22Kh2G2AYu, 22Kh2G2R,20Kh2G2SR |
For example, A3 construction reinforcement is used to strengthen concrete structures of prefabricated buildings and is widely used by construction companies in Kyiv. The actual weight of construction reinforcement consists of the mass of the reinforcement frames of the elements (foundation, walls, concrete floors) of a monolithic building, welded mesh, which are then filled with concrete mortar over the formwork.
The production of reinforcing steel in Ukraine is carried out using technologies developed in Soviet times in the field of metal processing, and, as a rule, on equipment inherited from the USSR, and that is why domestic manufacturers sell reinforcing steel at a fairly affordable price with good quality and compliance with GOST requirements .
Reinforcement 8, 10, 12, 14, 16, 18, 20, 22, 25 are the most popular in terms of the diameter of the periodic profile, sold by Ukrainian manufacturers. Imported analogues have a higher price.
Before being sold from metal warehouses, fittings in Ukraine undergo step-by-step quality control during the production process, which guarantees high quality that meets state standards GOST.
What is the weight of the reinforcement along its length?
The weight of the reinforcing steel required for purchase is calculated by multiplying the total length of all the bars in the bundle by the weight of a linear meter of reinforcement (see the table of mass 1 m and how many meters are in a ton of reinforcement). Conversion from meters to tons is carried out by multiplying the specific weight of the reinforcement (weight of 1 meter) by the number of linear meters.
Below is a table of reinforcement sections, the specific weight of 1 linear meter A1 (A240), A2 (A300), A3 (A400), A4 (A800), A5 (A800), A6 (A1000), the number of meters per ton to convert weight to total the length of all the rods in the package or coil.
The reinforcement in coils allows you to cut rods of any required length to size, which will reduce the amount of waste and eliminate the need to splice individual rods of standard length (6 or 12 meters).
Table of weight of reinforcing steel. How much does 1m of reinforcement weigh?
| Diameter of fittings, mm | Weight of 1 meter of reinforcement, kg | Linear meters per ton | Maximum weight deviations in % |
| d 6 | 0,222 | 4504,5 | +9,0 -7,0 |
| d 8 | 0,395 | 2531,65 | +9,0 -7,0 |
| d 10 | 0,617 | 1620,75 | +5,0 -6,0 |
| d 12 | 0,888 | 1126,13 | +5,0 -6,0 |
| d 14 | 1,21 | 826,45 | +5,0 -6,0 |
| d 16 | 1,58 | 632,91 | +3,0 -5,0 |
| d 18 | 2 | 500 | +3,0 -5,0 |
| d 20 | 2,47 | 404,86 | +3,0 -5,0 |
| d 22 | 2,98 | 335,57 | +3,0 -5,0 |
| d 25 | 3,85 | 259,74 | +3,0 -5,0 |
| d 28 | 4,83 | 207,04 | +3,0 -5,0 |
| d 32 | 6,31 | 158,48 | +3,0 -4,0 |
| d 36 | 7,99 | 125,16 | +3,0 -4,0 |
| d 40 | 9,87 | 101,32 | -+3,0 -4,0 |
| d 45 | 12,48 | 80,13 | +3,0 -4,0 |
| d 50 | 15,41 | 64,89 | +2,0 -4,0 |
| d 55 | 18,65 | 53,62 | +2,0 -4,0 |
| d 60 | 22,19 | 45,07 | +2,0 -4,0 |
| d 70 | 30,21 | 33,1 | +2,0 -4,0 |
| d 80 | 39,46 | 25,34 | +2,0 -4,0 |
Calculation of the weight of reinforcement, welded mesh
If you don’t have a reinforcement calculation table or an online metal calculator at hand, then you can calculate the total weight of the reinforcing mesh yourself by determining the total length of the wire that makes up the welded mesh measuring 1 m2 and multiplying the number of meters by the specific weight of a linear meter of wire.
In the absence of a reference book, you can calculate the weight of a linear meter of reinforcement yourself, using a regular calculator. The volume of metal in 1 meter of a steel cylinder is 1 m x (3.14 x D x D/4) . In parentheses is the geometric area of a circle with diameter D. The weight of the rod is obtained by multiplying the volume by the specific weight of the reinforcement, which is equal to 7850 kg/m3.
Using this method, you can calculate how many kg are in a meter of reinforcement, and convert tons into meters.
For example, using a calculator, we will calculate the weight of 1 m of reinforcement with a diameter of 12 mm: Volume of metal - 1 m x (3.14 x 0.012 m x 0.012 m/4) = 0.00011304 m3,
Specific gravity - 0.00011304 m3 x 7850 kg/m3 = 0.887 kg. Approximately equal to the value in the table of reinforcement with theoretic weight.
If the length of the reinforcement is 12 m, then we substitute the required value of the rolled steel length into the formula and calculate the weight of the rods. To determine the weight of the mesh, you need to multiply the resulting mass of 1 m2 of mesh by the number of square meters in the welded reinforcement frame.
One more example. Let's calculate the weight of a 100x100x4 mesh with an area of 1 m2. The welded mesh consists of 18 welded reinforcing bars 1 m long. The total length of the rods will be 18x1=18 meters. The specific gravity of 4mm reinforcing wire is 0.092 kg/m. Then the mass of a linear meter of mesh with a height of 1 m will be 18x0.092 = 1.66 kg/m2 + 1% of the mass of welding materials.
Source: https://sbk.ltd.ua/ru/sortament-ves-metalloprokata/136-ves-pogonnogo-metra-armatury-gost-5781-82.html
Reinforcement weight table per 1 meter
Why might the weight of 1 meter of 12 mm reinforcement be required? For example, when pouring the foundation for a private house, builders can tell you the amount of reinforcement in meters, but at metal warehouses, as a rule, reinforcement is sold and the price per ton is indicated. In this case, knowing the weight of one meter, you can calculate how much reinforcement you will need in tons.
For greater convenience, we have provided a second table, which indicates how many meters of reinforcement are contained in one ton for each diameter.
Here's an example of a calculation:
You need 750 meters of 12mm a500c reinforcement (read: decoding of a500c reinforcement).
We look at the line in the first table corresponding to 12 mm reinforcement; the weight of 1 meter is 0.888 kg.
In total we get 750 * 0.888 = 666 kg.
Weight of 1 meter reinforcement table
Reinforcement diameter (mm) Weight kg/meter| 5,5 | 0,187 |
| 6 | 0,222 |
| 8 | 0,395 |
| 10 | 0,617 |
| 12 | 0,888 |
| 14 | 1,210 |
| 16 | 1,580 |
| 18 | 2,000 |
| 20 | 2,470 |
| 22 | 2,980 |
| 25 | 3,850 |
| 28 | 4,830 |
| 32 | 6,310 |
| 36 | 7,990 |
| 40 | 9,870 |
| 45 | 12,480 |
| 50 | 15,410 |
In industrial construction, a huge amount of reinforcement is used, which is most often supplied in tons. To perform the necessary calculations, you need to know the total length of the existing reinforcement; this can be easily done using the table below.
Calculation example:
You know that you have 25 tons of 10mm reinforcement.
Using the table, we find the number of meters in a ton corresponding to 10 mm reinforcement: 1620 meters.
Total total length of the reinforcement: 25 * 1620 = 40500 meters.
How many meters in 1 ton of reinforcement table
Diameter of reinforcement (mm) Meters per ton| 5,5 | 5347 |
| 6 | 4504 |
| 8 | 2531 |
| 10 | 1620 |
| 12 | 1126 |
| 14 | 826 |
| 16 | 633 |
| 18 | 500 |
| 20 | 405 |
| 22 | 335 |
| 25 | 260 |
| 28 | 207 |
| 32 | 158 |
Source: http://stroitelnyj-portal.ru/materialy-instrumenty/ves-armaturyi-tablitsa-za-1-metr.html
Reinforcement 12: Calculation, weight, price
Calculation of the amount of reinforcement. Cost of one meter. Characteristics and GOSTs.
The choice of diameter of rod reinforcement for reinforced concrete structures depends on the load and operating conditions of the object. Starting from 12 millimeters and above, rods are used for load-bearing supports, walls, foundations, building frames, floors, highways, and bridges with significant loads. It is reinforcement 12 that is most in demand in construction. This is due to its high-quality physical characteristics and favorable price.
Steel grades for 12 mm GOST bars
Production is based on the hot-rolled method of producing shaped metal products. According to their technical properties, products are divided into prestressed and non-tensioned. Prestressed ones make it possible to achieve high bending strength, which is important in structures with pronounced lateral pressure. This type of rod is most often made from the following grades of carbon and low-alloy steel:
- st3, 32G2Rps, 25G2S, 35 GS.
Requirements for steel and assortment for rods d=12 are regulated by: GOST 10884-94, GOST 5781-82. In a concrete structure, reinforcement 12 enhances the strength properties of the finished building.
At the same time, the rods themselves take certain loads and protect the frozen block, for example, a foundation, from concrete cracking during its hardening and operation. This is the main purpose of using rods.
And this type is advantageous due to its high-quality physical characteristics, suitable for the loads of low-rise residential buildings, and an attractive price (compared to higher and more expensive brands).
Features of a periodic profile
Rods of this parameter are produced with a smooth or corrugated surface. Continuous profile rods (corrugated) have undeniable advantages when protrusions are located in a spiral or along the axis of the rod. In the marking, the designation of the diameter of such rods means the average data of 2 values:
- Internal (implies the diameter of the rod body only);
- External (indicates the size of the entire diameter, with protrusions).
Parameters: diameters, area, weight, length
Rods of 12 millimeters have a rod body d (internal) of 11.3 mm; d external 13.7 mm. The cross-sectional area is 1.131 cm2. The weight of 1 meter of profile is 0.888 kg. 1 ton contains 1126.13 m of product.
Slicing and packaging
Production is possible in 2 ways: hot-rolled and cold-formed. Rods are produced from ferrous rolled products using the hot-rolled method, and from non-ferrous metals - using the cold-rolling method. The price of the rods depends on this parameter, regardless of the method of cutting rolled metal:
- Rods of measured length;
- Profile of unmeasured length in packs.
12 mm reinforcement is packaged in bundles, the range of rod lengths is 6-12 meters. However, by agreement, it is possible to cut the rods into segments of any length from 3 to 25 m. Standardly, 1 rod of reinforcement is cut to a length of 11.75 m. From here you can calculate its weight, which at this length will be 10.43 kg. At the same time, a ton of profile contains 1126 meters.
Reinforcement calculation 12
To calculate how many meters of rods are needed, the total mass is divided by the weight of one meter. It is important to know that rods have theoretical and actual weights, which differ due to the fact that the values are standardized within certain tolerance ranges. That is why the weight when releasing products may differ slightly, up or down from that stated in GOST 5781-82 for one linear meter and the entire order as a whole.
In order to find out the actual weight of the released rods, a control weighing of the total tonnage of the batch is carried out directly during loading. It should be noted that the maximum deviations that regulate weight are also indicated in the standards. If 12 mm reinforcement is weighed, these deviations can range from -6% to +5% according to GOST 5781-82.
Smooth profile
Smooth rods for construction are produced by the hot-rolled method, hardness class A1. Products are cut, as agreed with the customer, either standardly or to custom lengths. This type of profile has no protrusions or ribs. Welded steel reinforcement has the ability to be welded efficiently without loss of tensile and bending strength. This also applies to corrugated products.
Price of fittings dn=12 mm
The price of rod reinforcement is indicated per linear meter and per ton; more often, the manufacturer indicates the cost per ton based on the finished length of the segments. In this case, the customer can receive cuts of any length. Knowing how much 1 ton will cost and the number of meters in it, you can calculate what the price is for 1 meter of rods.
In the Moscow region, 1 meter of reinforcement with a nominal diameter of 12 costs from 24 rubles (periodic profile).
Smooth profile, price per 1 meter:
- From 29 rubles (retail);
- From 28 rub. small wholesale;
- From 27 rub. large wholesale
The price of reinforcement per ton is from 25,900 rubles (grade A500/35GS) with a standard cut of 11.7 m. With a rod length of 6 meters - from 26 thousand rubles. subject to the purchase of a wholesale batch of 20 tons.
The cost of one meter with a rod length of 3 m is 28 rubles. The lowest price per meter is 21.5 rubles. with standard cutting 11.7 m (A3, A500C). Reinforcement with a nominal diameter of 12 millimeters is used mainly for reinforcing high-grade concrete.
Source: https://the-master.ru/armatura/armirovannaya-stal-12-mm
ANSWER: 0 meters. (0 rods per millimeter)
The reinforcement is manufactured in accordance with GOST 5781-82 “Hot-rolled steel for the reinforcement of reinforced concrete structures. Technical conditions" and GOST R 52544-2006 "Rolled welded reinforcement of periodic profile of classes A500C and B500C for reinforcement of reinforced concrete structures. Technical specifications"
Depending on the mechanical properties, reinforcing steel is divided into classes A-I (A240), A-II (A300), A-III (A400), A-IV (A600), A-V (A800), A-VI (A1000 ). In the designation A500C and B500C, the letter A means hot-rolled or thermomechanically strengthened reinforcing bars, the letter B means cold-deformed reinforcing bars, and the letter C means weldable.
The number in the designation shows the rounded value of the yield strength in N/mm 2. The yield strength is a mechanical characteristic of a material that characterizes the stress at which strain continues to increase without increasing the load.
What else to read on the site:
Equal-flange steel angle weight calculator. Angle meter weight table. Number of meters of angle in a ton. Dimensions of the metal corner.
Weight calculator for steel unequal angle. Table weight per linear meter of corner. Number of meters of angle in a ton. Metal corner, unequal dimensions.
domatut.rf is a site for professional builders and those who build with their own hands. Articles about the procedure for registration, composition and maintenance of as-built documentation in construction. Examples of correct completion of work logs and acts. Articles about the design and technology of construction and installation works. Calculators for calculating the amount of materials and other useful information for professional builders and those who build with their own hands.
Reinforcement weight calculator
Reinforcement weight calculator. Weight of a meter of reinforcement. Number of meters of reinforcement per ton. Reinforcement diameters table.
Source: https://postroifundament.ru/massa-pogonnogo-metra-armatury.html
Weight per linear meter of reinforcement
Posted by admin on 07/10/2012
Reinforcement photo
The weight of a linear meter of reinforcement may be different for different reinforcement. What determines the weight of a meter of reinforcement? The weight of one linear meter of reinforcement depends primarily on the DIAMETER OF THE REINFORCEMENT and for each of the possible options for the diameter of the reinforcement according to GOST, the value of the weight of one linear meter will be a constant value - a constant.
Why are we discussing the LINEAR meter of reinforcement?
The length of the reinforcement is measured in meters, and the length is indicated in linear meters.
When performing construction work and manufacturing metal structures, it is convenient to move from estimating the amount of reinforcement in tons to a more applied system - estimating the amount of reinforcement in meters. And any materials whose main characteristic is the length of the rolled product are usually called MOLDING in construction.
The unit of measurement for any objects with length as their main characteristic (long objects, products and materials) is in mathematics the LINEAR METER. Likewise, with reinforcement, it is most convenient for us to estimate its quantity in linear meters.
And in most tables for calculating the weight of reinforcement, the information is provided precisely on the basis of what you can directly measure with a tape measure - how many linear meters of reinforcement you have available.
How to measure the diameter of reinforcement?
But directly measuring the diameter of reinforcement or reinforcing bar is quite difficult. If we had a classic round rod, there would be no problems. But reinforcement is NOT a SMOOTH rod , but a product that has its own specific shape and relief.
By measuring the diameter of the reinforcement in different sections of the rod, we get quite different values. In practice, the diameter of the reinforcement is not measured, but is taken from the accompanying documents, which indicate the NOMINAL or CONDITIONAL DIAMETER OF THE REINFORCEMENT .
What is the NOMINAL DIAMETER of the fittings?
Reinforcement diameter photo
What the nominal diameter of reinforcement is is explained in the reference book on rolled metal: the diameter of the reinforcement roughly corresponds to the diameter of a round rod with the same cross-section. DO NOT HESITATE TO OPEN THE PICTURE - explanatory notes will be visible there.
How to use the table for calculating the weight of reinforcement?
Calculation of reinforcement weight photo
In fact, using the table for calculating the weight of reinforcement is very simple and convenient. There are quite detailed tables of the weight of linear reinforcement , taking into account different types of reinforcement according to GOST (out of three in fact). I'll show you with an example. So, for example, you want to buy 25 meters of reinforcement with a diameter of 16 mm. Perhaps you need to reinforce the foundation for a fence or solve some other construction problem.
When selling reinforcement, the seller usually sets the price of the reinforcement in tons; it is in tonnage that he buys it at the factory. He sells you reinforcement in meters, in linear meters, of which you need exactly 25 m. That is, the price of reinforcement per ton tells you absolutely nothing.
In order to somehow convert the number of linear meters of reinforcement you have into “categories close to: price per ton,” you need to calculate how much your 25 meters of reinforcement with a diameter of 16 mm weigh. We find a line in the table for calculating the weight of reinforcement - the weight of a linear meter of reinforcement is 16 mm, on the contrary in the second column the value of the weight of the meter in kilograms is indicated - 1.580 kg.
Now, knowing the weight of one meter, we must multiply it by the number of meters - 1.580 x 25 = 39.5 kg. That is, your 25 linear meters weigh exactly 39.5 kg. THIS IS THE THEORETICAL WEIGHT OF A METER OF REINFORCEMENT!!!
Does the theoretical weight of the reinforcement coincide with the real one and is it necessary to weigh the reinforcement?
In fact, the theoretical weight of the reinforcement is a fairly accurate guide. Weighing the reinforcement on a scale will show a slightly different weight than the theoretical one - this is normal. But if the weight value obtained after weighing is very different , you need to deal with the scales or with your calculations, checking both.
| Profile number(nominal diameter) | Weight, kg/m |
| Weight of a linear meter of reinforcement with a diameter of 6 mm | 0,222 |
| Weight of a linear meter of reinforcement with a diameter of 8 mm | 0,395 |
| Weight of a linear meter of reinforcement with a diameter of 10 mm | 0,617 |
| Weight of a linear meter of reinforcement with a diameter of 12 mm | 0,888 |
| Weight per linear meter of reinforcement with a diameter of 14 mm | 1,210 |
| Weight per linear meter of reinforcement with a diameter of 16 mm | 1,580 |
| Weight per linear meter of reinforcement with a diameter of 18 mm | 2,000 |
| Weight of a linear meter of reinforcement with a diameter of 20 mm | 2,470 |
| Weight of a linear meter of reinforcement with a diameter of 22 mm | 2,980 |
| Weight of a linear meter of reinforcement with a diameter of 25 mm | 3,850 |
| Weight per linear meter of reinforcement with a diameter of 28 mm | 4,830 |
| Weight of a linear meter of reinforcement with a diameter of 32 mm | 6,310 |
| Weight per linear meter of reinforcement with a diameter of 36 mm | 7,990 |
| Weight of a linear meter of reinforcement with a diameter of 40 mm | 9,870 |
| Weight of a linear meter of reinforcement with a diameter of 45 mm | 12,480 |
| Weight of a linear meter of reinforcement with a diameter of 50 mm | 15,410 |
(Nobody rated)
Source: http://4ypakabra.ru/ves-pogonnogo-metra-armaturyi/
Reinforcement - table of weight and number of meters in 1 ton
Today we will talk about how much the reinforcement weighs, and the maximum length of a metal rod. Mostly about how many meters are in a ton of reinforcement, but other diameters will also be considered.
Weight of reinforcement, how many meters in 1 ton?
During construction, it is necessary to have an accurate idea of how much weight the entire reinforced structure has as a whole. There are a number of reasons for this:
- This makes it possible to withstand reinforcement technology.
- Guarantees the necessary reliability of the structure.
- It is more convenient to calculate the total cost of the structure.
The greatest attention is paid to a rod with a diameter of 12 mm, because this is the minimum diameter that can be used when creating structures for strip foundations. And of course, we should not forget about the significant factor that during construction, it is very important to know exactly how many meters of reinforcement will be required for one ton of planned products.
How much does the reinforcement weigh and the amount of reinforcement per ton, table:
The weight of a meter of reinforcement is presented in the table of the ratio of diameter and weight of 1 m. Knowing the weight of reinforcing steel according to GOST 5781-82, you can estimate the reinforcement coefficient of the structure (the ratio of the mass of the reinforcement to the volume of concrete) and determine how much material is needed for the foundation (per cube of concrete)
A linear meter of reinforcement is individual reinforcing bars of a smooth and periodic profile 1 meter long, the weight of which depends on the diameter of the reinforcing steel GOST 5781-82 (from a range of diameter sizes of periodic steel - 6, 8.10, 12, 14, 16, 18.20, 22, 25, 28, 32, 36, 40, 45, 50, 55, 60, 70, 80 mm).
| Reinforcement size (nominal bar diameter) | Weight of 1 m of reinforcement, theoretical, kg | Number of meters of reinforcement in 1 ton, m. |
| 4 | 0,099 | 10101,010 |
| 5 | 0,154 | 6493,506 |
| 6 | 0,222 | 4504,504 |
| 8 | 0,395 | 2531,645 |
| 10 | 0,617 | 1620,745 |
| 12 | 0,888 | 1126,126 |
| 14 | 1,210 | 826,446 |
| 16 | 1,580 | 632,911 |
| 18 | 2,000 | 500,000 |
| 20 | 2,470 | 404,858 |
| 22 | 2,980 | 335,570 |
| 25 | 3,850 | 259,740 |
| 28 | 4,830 | 207,037 |
| 32 | 6,310 | 158,478 |
| 36 | 7,990 | 125,156 |
| 40 | 9,870 | 101,317 |
| 45 | 12,480 | 80,128 |
| 50 | 15,410 | 64,892 |
| 55 | 18,650 | 53,619 |
| 60 | 22,190 | 45,065 |
| 70 | 30,210 | 33,101 |
| 80 | 39,460 | 25,342 |
Source: https://DomStrouSam.ru/skolko-metrov-armaturyi-v-tonne-tablitsa-vseh-razmerov-i-massa/
How many rods of 12 rebar are in a ton?
Reinforcement is a set of interconnected elements that, when working together with concrete in reinforced concrete structures, perceive tensile stresses (although they can also be used to strengthen concrete in a compressed zone).
The main application of periodic profile reinforcing steel is in the construction of foundations and walls of buildings and structures made of monolithic concrete.
When carrying out concrete work, a significant investment of time and money requires the installation of a reinforced frame to reinforce structures made from reinforcing mesh.
To calculate the order volume, you need to know how many kg per meter of reinforcement and the number of linear meters of reinforcing steel.
The weight of a meter of reinforcement is presented in the table of the ratio of diameter and weight of 1 m. Knowing the weight of reinforcing steel according to GOST 5781-82, you can estimate the reinforcement coefficient of the structure (the ratio of the mass of the reinforcement to the volume of concrete) and determine how much material is needed for the foundation (per cube of concrete)
A linear meter of reinforcement is individual reinforcing bars of a smooth and periodic profile 1 meter long, the weight of which depends on the diameter of the reinforcing steel GOST 5781-82 (from a range of diameter sizes of periodic steel - 6, 8.10, 12, 14, 16, 18.20, 22, 25, 28, 32, 36, 40, 45, 50, 55, 60, 70, 80 mm).
How much does the reinforcing mesh weigh for screeding, performing plastering work, for making a reinforced concrete foundation frame (concrete + connected reinforcement bars), what is the weight of the reinforcing mesh for brickwork, depends on the size of the cards (length, width of the canvas), the size of the cell (square mm x mm ) and reinforcing wire diameter (mm).
Construction organizations use reinforcement produced in Ukraine, the weight of which meets the requirements of GOST, since domestic reinforcing steel is of sufficiently high quality and complies with all GOSTs and standards for rolled metal.
The weight of the reinforcement is selected depending on the types according to GOST, diameter sizes (see.
table - “Specific gravity of reinforcement in a linear meter”) and the scope of application of the periodic profile.
The weight of a linear meter of reinforcement depends on the shape of the surface of the periodic profile: corrugated or smooth on the outside. Protrusions in the form of ribs, corrugations on the surface of periodically profiled reinforcing steel bars or ribbed wire steel significantly improve adhesion to concrete and its characteristics.
The range of reinforcement, depending on the manufacturing technology of reinforcing steel for reinforced concrete structures, is divided into hot-rolled rod and cold-drawn wire steel.
The weight of 1 m of hot-rolled reinforcement does not depend on its basic mechanical characteristics, which are divided into six assortment classes depending on the strength of the metal and steel grade, with the symbol: AI, A-II, A-III, A-IV, AV, A- VI.
| Reinforcing steel class | Profile diameter, mm | Reinforcement steel grade |
| AI (A240) | 6-40 | St3kp, St3ps, St3sp |
| A-II (A300) | 10-40 40-80 | St5sp, St5ps 18G2S |
| Ac-II (Ac300) | 10-32 (36-40) | 10GT |
| A-III (A400) | 6-40 6-22 | 35GS, 25G2S 32G2Rps |
| A-IV (A600) | 10-32 (6-8)(36-40) | 80С 20ХГ2Ц |
| AV (A800) | (6-8) 10-32(36-40) | 23Х2Г2Т |
| A-VI (A1000) | 10-22 | 22Kh2G2AYu, 22Kh2G2R, 20Kh2G2SR |
For example, A3 construction reinforcement is used to strengthen concrete structures of prefabricated buildings and is widely used by construction companies in Kyiv. The actual weight of construction reinforcement consists of the mass of the reinforcement frames of the elements (foundation, walls, concrete floors) of a monolithic building, welded mesh, which are then filled with concrete mortar over the formwork.
The production of reinforcing steel in Ukraine is carried out using technologies developed in Soviet times in the field of metal processing, and, as a rule, on equipment inherited from the USSR, and that is why domestic manufacturers sell reinforcing steel at a fairly affordable price with good quality and compliance with GOST requirements .
Reinforcement 8, 10, 12, 14, 16, 18, 20, 22, 25 are the most popular in terms of the diameter of the periodic profile, sold by Ukrainian manufacturers. Imported analogues have a higher price.
Before being sold from metal warehouses, fittings in Ukraine undergo step-by-step quality control during the production process, which guarantees high quality that meets state standards GOST.
Reinforcing steel weight table - How much does 1 m of reinforcement weigh?
| Diameter of fittings, mm | Weight of 1 meter of reinforcement, kg | Linear meters per ton | Maximum weight deviations in % |
| d 6 | 0,222 | 4504,5 | +9,0 -7,0 |
| d 8 | 0,395 | 2531,65 | +9,0 -7,0 |
| d 10 | 0,617 | 1620,75 | +5,0 -6,0 |
| d 12 | 0,888 | 1126,13 | +5,0 -6,0 |
| d 14 | 1,21 | 826,45 | +5,0 -6,0 |
| d 16 | 1,58 | 632,91 | +3,0 -5,0 |
| d 18 | 2 | 500 | +3,0 -5,0 |
| d 20 | 2,47 | 404,86 | +3,0 -5,0 |
| d 22 | 2,98 | 335,57 | +3,0 -5,0 |
| d 25 | 3,85 | 259,74 | +3,0 -5,0 |
| d 28 | 4,83 | 207,04 | +3,0 -5,0 |
| d 32 | 6,31 | 158,48 | +3,0 -4,0 |
| d 36 | 7,99 | 125,16 | +3,0 -4,0 |
| d 40 | 9,87 | 101,32 | -+3,0 -4,0 |
| d 45 | 12,48 | 80,13 | +3,0 -4,0 |
| d 50 | 15,41 | 64,89 | +2,0 -4,0 |
| d 55 | 18,65 | 53,62 | +2,0 -4,0 |
| d 60 | 22,19 | 45,07 | +2,0 -4,0 |
| d 70 | 30,21 | 33,1 | +2,0 -4,0 |
| d 80 | 39,46 | 25,34 | +2,0 -4,0 |
Calculation of the weight of reinforcement, welded mesh
If you don’t have a reinforcement calculation table or an online metal calculator at hand, then you can calculate the total weight of the reinforcing mesh yourself by determining the total length of the wire that makes up the welded mesh measuring 1 m2 and multiplying the number of meters by the specific weight of a linear meter of wire.
In the absence of a reference book, you can calculate the weight of a linear meter of reinforcement yourself, using a regular calculator. The volume of metal in 1 meter of steel cylinder is 1 m x (3.14 x D x D/4). In parentheses is the geometric area of a circle with diameter D. The weight of the rod is obtained by multiplying the volume by the specific weight of the reinforcement, which is equal to 7850 kg/m3.
Using this method, you can calculate how many kg are in a meter of reinforcement, and convert tons into meters.
For example, using a calculator, we will calculate the weight of 1 m of reinforcement with a diameter of 12 mm: Volume of metal - 1 m x (3.14 x 0.012 m x 0.012 m/4) = 0.00011304 m3,
Specific gravity - 0.00011304 m3 x 7850 kg/m3 = 0.887 kg. Approximately equal to the value in the table of reinforcement with theoretic weight.
If the length of the reinforcement is 12 m, then we substitute the required value of the rolled steel length into the formula and calculate the weight of the rods. To determine the weight of the mesh, you need to multiply the resulting mass of 1 m2 of mesh by the number of square meters in the welded reinforcement frame.
One more example. Let's calculate the weight of a 100x100x4 mesh with an area of 1 m2. The welded mesh consists of 18 welded reinforcing bars 1 m long. The total length of the rods will be 18x1=18 meters. The specific gravity of 4mm reinforcing wire is 0.092 kg/m. Then the mass of a linear meter of mesh with a height of 1 m will be 18x0.092 = 1.66 kg/m2 + 1% of the mass of welding materials.
Source: https://betfundament.com/skolko-hlystov-12-armatury-v-tonne/
