How much does 10 meters of reinforcement weigh - Table of weight and number of meters per ton!
Reinforcing bars are mainly used to strengthen concrete. A mesh is knitted from them, so it absorbs the tensile force that goes to the concrete. In the construction sector, rolled products with a section size of 10 millimeters are very often used. And, in order to create a reinforced frame or mesh, you need to know the exact weight of the 10 mm reinforcement. per meter In this article we will talk specifically about this steel product.
The weight of the reinforcement is always determined by the GOST 5781-82 standard, it says what the mass and other parameters should be. The fittings are available in two types:
- hot rolled;
- cold rolled.
The rolled product itself is created in the form of metal rods or rods.
Reinforcement 10 mm weight 1 meter
To estimate the cost of construction, or finished objects, you need to know the exact mass of reinforced structures. Find out how much 10 mm reinforcement weighs. can be done in a simple way: we sum up the length and multiply by the linear weight of our rolled metal.
In order to find out the mass of a linear meter, you need to check the table, which displays all the dimensions, their weight and the number of meters per ton.
Table of weight and number of meters per ton of reinforcement with a diameter of 10 mm.
The weight of 1 meter of reinforcement measuring ten millimeters is presented in the table of the ratio of diameter and weight of one meter. Knowing the weight of reinforcing steel according to GOST 5781-82, you can estimate the rolling coefficient (the ratio of the mass of reinforcement to the volume of concrete) and calculate how many metal rods are needed (per cube of concrete ).
How much does 10 mm reinforcement weigh? Table.
Name Section size Weight of 1 meter| Armature | 10 mm. | The weight of 1 m is equal to 0.617 kg. |
How many meters of 10 mm reinforcement. in a ton? Table.
Name Section size Number of meters per ton| Armature | 10 mm. | There are 1620 m in 1 ton . |
Having the above table at hand, you will always know the exact quantity and weight of this steel product with the required cross-sectional diameter. It won’t be difficult to calculate the cost before purchasing, thereby saving yourself from unnecessary costs.
How to make an independent calculation?
Without tabular data, the total weight of the reinforcing mesh or the weight of one linear meter can be calculated using an online calculator, or you can do it yourself. To do this, the length of the reinforcing mesh rods, for example, with an area of 1 m2, is multiplied by the specific weight of one linear meter of reinforcement rods. The volume of steel for 1 m of the metal cylinder under study is equal to 1 meter x (∏ x D2 x / 4).
The weight of the reinforcing bar will be equal to the derivative of the resulting volume and the specific gravity of the reinforcement, which is equal to 7850 kg/m3. This simplified technique allows you to calculate the mass in kilograms of one meter of reinforcing bars, as well as convert the weight into units of length (meters).
domstrousam.ru
Reinforcement 10 mm weight 1 meter table
Steel reinforcement bars take on tensile forces when working in a mass of concrete, which the concrete itself does not tolerate well.
Tension of a structure occurs mainly when a load is applied to the foundation, so the main area of application of reinforcement is the foundations of construction projects and the walls of monolithic concrete structures.
The reinforcement is tied into a reinforcing frame, the fastening of periodic profile rods and smooth steel rods is carried out by wire binding or (in some cases) welding. Therefore, to create a reinforced frame or one reinforcing mesh, you need to know the weight and dimensions of the rods.
For example, 10 mm reinforcement weighs 1 meter a little more than half a kilogram - more accurate data on all diameters in accordance with the weight and length of the rods can be found in the table below:
| Ø, mm | Weight 1 m, kg | How many linear meters in one ton | Error, % |
| 6 | 0,22 | 4504,5 | +9/-7 |
| 8 | 0,39 | 2531,7 | +9/-7 |
| 10 | 0,618 | 1620,8 | +5/-6 |
| 12 | 0,88 | 1126,1 | +5/-6 |
| 14 | 1,2 | 826,5 | +5/-6 |
| 16 | 1,6 | 632,9 | +3/-5 |
| 18 | 2,0 | 500,0 | +3/-5 |
| 20 | 2,5 | 404,9 | +3/-5 |
| 22 | 3,0 | 335,6 | +3/-5 |
| 25 | 3,9 | 259,7 | +3/-5 |
| 28 | 4,8 | 207,0 | +3/-5 |
| 32 | 6,3 | 158,5 | +3/-4 |
| 36 | 7,9 | 125,2 | +3/-4 |
| 40 | 9,9 | 101,3 | +3/-4 |
| 45 | 12,5 | 80,1 | +3/-4 |
| 50 | 15,4 | 64,9 | +2/-4 |
| 55 | 18,7 | 53,6 | +2/-4 |
| 60 | 22,2 | 45,1 | +2/-4 |
| 70 | 30,2 | 33,1 | +2/-4 |
| 80 | 39,5 | 25,3 | +2/-4 |
Reinforcement by weight is selected in accordance with GOST 5781-82, which regulates the sizes of rods, their diameter, profile and other standards. The production of reinforcing bars can be cold- or hot-rolled; the reinforcement itself is made in the form of rods or wire.
The weight of 1 meter of hot-rolled reinforcement does not depend on the operating parameters of the material, which are classified in six property ranges according to strength and steel grade. Designation of fittings classes: A I, A II, A III, A IV, A V, A VI
| Class | Ø | Brand |
| A I (A 240) | 6-40 mm | St3KP, St3PS, St3SP |
| A II (A 300) | 10-40 mm40-80 mm | St5SSP, St5PS18G2S |
| AC II (AC 300) | 10-32 mm36-40 mm | 10GT |
| A III (A 400) | 6-40 mm6-22 mm | 35GS, 25G2S32G2RPS |
| A IV (A 600) | 10-32 mm6-8 mm36-40 mm | 80С20ХГ2Ц |
| A V (A 800) | 6-8 mm10-32 mm36-40 mm | 23Х2Г2Т |
| A VI (A 1000) | 10-22 | 22Kh2G2AYu, 22Kh2G2R, 20Kh2G2SR |
Weight of linear and linear meter of reinforcement
In practice, the mass of construction reinforcing bars is the sum of the weight of all the reinforced frames of the foundation or concrete walls of the object plus the weight of the reinforcing mesh that is placed in the concrete solution in the formwork. The most popular diameters of reinforcing bars in industrial and individual construction are from 8 to 25 mm, the profile is periodic (corrugated reinforcement). Rods and smooth rods of larger diameter indicated in the table are used only in industrial construction.
Weight table for steel building reinforcement
The weight of reinforcement that needs to be purchased is calculated as follows: first, the length of all reinforcement bars in the package is summed up, the result is multiplied by the weight of 1 linear meter of reinforcement - these values are indicated in the table. Knowing the total length of the rods, you can get the total weight.
To do this, you need to multiply the specific gravity of the reinforcement products by the length of the reinforcement in linear meters.
The table shows the cross-sections of reinforcement bars in relation to 1 linear meter of reinforcement of classes A 1 (A 240), A 2 (A 300), A 3 (A 400), A 4 (A 800), A 5 (A 800), A 6 (A 1000), as well as the total footage of rods in 1 ton.
Without tabular data, the total weight of the reinforcing mesh or the weight of 1 linear meter can be calculated using an online calculator or independently. To do this, the length of the reinforcing mesh rods, for example, with an area of 1 m2, is multiplied by the specific weight of 1 linear meter of reinforcement rods.
The volume of steel for 1 meter of the metal cylinder under study is equal to 1 meter x (∏ x D2 x / 4). The weight of the reinforcing bar will be equal to the derivative of the resulting volume and the specific gravity of the reinforcement, which is 7,850 kg/m3.
This simplified technique allows you to calculate the mass in kilograms of 1 meter of reinforcing bars, as well as convert the mass into units of length (meters).
jsnip.ru
Weight of reinforcement, weight of linear meter of reinforcement
When constructing elements of country houses from monolithic concrete, significant costs are required for structural reinforcement . The weight of reinforcement in a structure is calculated by multiplying the total length of all rods by the weight of a linear meter of reinforcement. The weight of a meter of reinforcement is taken from the table. Knowing the weight of the reinforcement, you can estimate the percentage of reinforcement of the structure (the ratio of the weight of the reinforcement to the volume of concrete) and calculate the market value of the reinforcement, since the price of rolled metal is calculated per kg.
The weight of a linear meter of reinforcement depends on the diameter
| Diameter of fittings, mm | Cross-sectional area, cm2 | Reinforcement weight, kg/m | Steel grade |
| 3 | 0,071 | 0,055(0,051) | Ordinary and high-tensile wire |
| 4 | 0,126 | 0,098(0,090) | Ordinary and high-tensile wire |
| 5 | 0,196 | 0,154(0,139) | Ordinary and high-tensile wire |
| 6 | 0,283 | 0,222 | A-III, ordinary and high-tensile wire |
| 7 | 0,385 | 0,302 | A-III, ordinary and high-tensile wire |
| 8 | 0,503 | 0,395 | A-III, ordinary and high-tensile wire |
| 9 | 0,636 |
Source: https://sk-amigo.ru/raznoe/skolko-vesit-metr-10-armatury-tablica-vesa-i-kolichestva-metrov-tonne.html
Consumption of reinforcement per 1 cubic m of concrete
When working with concrete, you should pay special attention to the calculation of reinforcement. A lack of reinforcement reduces the strength of the entire structure, and its overuse entails unnecessary waste of money. In this article we will consider in detail the question of how much reinforcement is needed per cube of concrete.
What determines the consumption rate of reinforcement per 1 cubic meter of concrete?
Different types of structures use different amounts of reinforcement. The fittings themselves vary in class and weight. Based on the cross-sectional area of the reinforcement, you can find out the weight of 1 meter. You can read more about the classes and types of reinforcement in a special article: reinforcement, types, characteristics, selection, knitting, bending of reinforcement.
To calculate the amount of binder and reinforcement in 1 m³ of concrete volume, you will need the following information:
- Foundation type.
- Cross-sectional area of the rods and their class.
- Total weight of the building.
- Soil type.
There are several main types of concrete foundations: strip, slab and columnar. You can read more about choosing the type of foundation and the characteristics of each of them in the article: choosing the type of foundation, its calculation, foundation construction technologies. In the same article you can learn about calculating the weight of a building and how to take into account the type of soil when choosing the type and size of the foundation.
Reinforcement structure for the foundation.
Despite the large differences in possible foundation configurations, there are general recommendations. So, to build a small wooden house you will need reinforcement with a cross-section of no more than 10 mm. To create the foundation of a large brick house, you will need at least 14 mm in thickness.
The rods are installed in the foundation at an average interval of 20 cm from each other. The bundle contains 2 belts: upper and lower. By measuring the total length and depth of the foundation, you can accurately determine how many meters of reinforcement and, based on these numbers, calculate their total weight.
It should be taken into account that the reinforcement does not need to be deeply buried, since the main tension is created on the surface.
According to building codes, at least 8 kilograms of reinforcement are consumed per 1 cubic meter of concrete.
Calculation of reinforcement consumption per 1 cubic meter. for strip foundation
For example, consider a strip foundation with dimensions: 9 by 6 meters, strip width 40 cm and height 1 meter. Let's make an average standard calculation, which is quite suitable for soil not subject to severe heaving. The frame consists of rows: horizontal, vertical and transverse.
First, let's calculate the horizontal reinforcement. There is a distance of 30 cm between horizontal rows of reinforcement, and the rows themselves should be in concrete at a depth of 5 cm from the surface. This means that a foundation 1 meter high requires 4 rows of reinforcement.
If the foundation is up to 40 cm wide, then 2 reinforcing bars are placed in each row. The perimeter of our foundation is 30 meters. There are 4 rows along the entire perimeter of the foundation, and each has 2 rods. This means there are only 8 rods around the perimeter of the foundation. We find the total length of horizontal reinforcement 30*8=240 m.
That with a diameter of 12 mm (0.888 kg per meter of rod) it will be 240 * 0.888 = 213 kilograms.
Calculation of reinforcement consumption per cube of concrete. In this diagram, the reinforcement is laid in two rows of three rods each.
Indentations of the reinforcement from the edge of the concrete by 5 cm serve to create a protective layer of concrete around the reinforcement.
To fix the reinforcement at the required distance from the formwork before and during concrete pouring, special supports or clamps for the reinforcement are used.
You can read more about what a protective layer of concrete is and about the types of fasteners in a special article: fasteners for reinforcement, their types, characteristics, correct use.
Transverse reinforcement is needed to connect horizontal and vertical rows. For these purposes, reinforcement with a diameter of 6 mm (0.222 kg per kg) is used in increments of 30 cm. The length of each transverse rod in the horizontal plane is 30 cm. In the vertical plane - 90 cm.
We subtracted 5 cm from the width and height of the foundation on each side to create a protective layer of concrete. In one section we get 4 rods of 30 cm and 2 rods of 90 cm. It turns out that in one section there are 4 * 30 + 2 * 90 = 300 cm or 3 meters of reinforcement. The section pitch is 0.3 meters, knowing the length of the strip foundation, we find the total number of cross sections: 30/0.
3=100 pcs. Then the total length of the transverse reinforcement is 3*100=300 m. And the weight is 300*0.222=66.6 kg.
The total weight of the reinforced system will be 213 + 66.6 = 279.6 kg for a strip foundation 6 by 9 m, that is, with a volume of 12 cubic meters.
Thus, for the considered strip foundation per 1 cubic meter of concrete solution, the consumption of reinforcement is:
- with a diameter of 12 mm: 213/12 = 17.8 kg per 1 m cube of concrete,
- with a diameter of 6 mm: 66.6/12 = 5.6 kg per 1 m cube of concrete.
Composite reinforcement is on average 4 times lighter than steel, therefore, to calculate its consumption, you can divide the weight of the reinforcement by four times.
Approximate indicators of reinforcement consumption per 1 cubic meter of concrete for different types of foundation:
- for a columnar foundation - 10 kg per 1 cubic m of concrete ;
- for a strip foundation - 20 kg per 1 cubic m of concrete ;
- for a slab foundation - 50 kg per 1 cubic meter of concrete.
In order to calculate how much reinforcement is needed per 1 cubic meter of concrete more accurately, you should make an accurate calculation of the reinforcement for the foundation. To do this, you can use more detailed materials on the page: calculation of reinforcement.
Source: https://dompodrobno.ru/rashod_armatury_na_kub_betona/
How much does 1 meter of reinforcement 12 weigh?
Very often, reinforcement is used to strengthen a particular monolithic structure or casting. By definition, reinforcement is various kinds of rods and profiles consisting of metal structures of any type of metal.
In construction, this term is heard quite often, since the issue of strengthening the structure under construction is quite tough and acute. Basically, reinforcement is used as a means of connecting concrete mortar and its coupling between cast profiles of a building or structure.
Application of fittings
As a rule, the question of using one or another type of reinforcement is quite relevant, and often completely constant, among builders and engineers. The connection between these two specialties is quite simple. Each of them wants the structure they built to stand as long and as strong as possible. In addition, there are laws and regulations for this, established by the state construction standard.
To strengthen the structure under construction, reinforcing iron blanks of various strengths and thicknesses are used. Basically, their use is inextricably linked with the concept of reinforced concrete material. As a rule, a reinforced concrete element, be it a slab or a block, consists of some kind of frame - metal reinforcement, on which there is a shell of concrete mortar.
This type of building element can significantly increase the load per unit surface area. As a rule, such structures use metal of relatively soft density, such as an iron rod, channel and other workpieces.
But it happens that to strengthen the structure, denser and heavier material is used, for example, an angle, an I-beam or other rolled metals. According to their physical and construction characteristics, such reinforced concrete structures have a number of classifications, the basis of which is the strength class of reinforced concrete.
Thus, the following classes of reinforced concrete structures are distinguished:
- Hot rolling design.
- Manufactured concrete structures using thermal and chemical treatments.
- Durable.
- Thermally resistant design.
Certain characteristics assigned to the enormous strength and stability of reinforced concrete structures in construction depend on these classifications and a number of strengths.
For any building material, a distinctive characteristic is GOST, according to which manufacturers of reinforced concrete structural elements roll out the material. It is this standard that regulates the use of one or another type or strength class of reinforcement in concrete mortar.
Clutch nuances
As is clear, the mass of a given reinforcing bar 12 directly depends on what shape and what size it is. It is known that the plane of the rod reinforcement itself can have a smooth surface or have corrugation.
It is worth saying that the best adhesion to concrete mortar occurs due to the corrugated surface of the reinforcement, which is a kind of connecting link between the strength and hardness of the structure.
The entire range of reinforcing material varies depending on how and in what way it was produced. In other words, there are both hot-rolled and drawn rods. It is worth noting that the quality of hot-rolled reinforcement is much better than that of another system of reinforced concrete blocks. But reinforced concrete reinforcements produced by a cold roller have their own number of classifications and advantages in subclasses.
For the basis of correct adhesion of absolutely any reinforcement, it is necessary to know the weight and mass of the metal. It is on the basis of these parameters that one or another type of seam is formed, which is adapted to a given reinforcement. This can be either cold welding or ionic bonding of the metal.
Where is the reinforcement used?
The most common diameter in reinforcement for its use is a 12 mm layer. This diameter is considered the most convenient and optimal among similar reinforcement systems produced with similar diameters. It is also noteworthy that reinforcement with such a diameter is quite easy to bend and itself has a low mass. But when tied together, the reinforcement forms sufficient strength and hardness necessary to hold multi-ton structures.
Moreover, for the construction and erection of walls in cottages and private houses, according to the standard, a reinforced foundation must be used, which is reinforced with 12 mm reinforcement.
In this option, a strip foundation is used, which also provides for the installation of metal structures for pouring concrete.
To correctly calculate the cost of the required amount of reinforcement with a diameter of 12 millimeters, you need to know its weight over a length of one meter.
But such calculations are necessary only when the structure does not have a layout in the established order, or the process of replacing the reinforced foundation with a higher-quality layer of reinforced concrete occurs. All main characteristics of all structures must be recorded in the documentation for the construction of the facility.
How to calculate the weight of reinforcement?
In order to calculate the mass of the reinforcement used, you need to know some of the minimum parameters of a given metal structure, and these are:
For an accurate calculation, it is necessary to multiply the total length of the reinforcement used by its linear meter. Also, it is not difficult to calculate the cost of fittings. To do this, you need to know the price per meter of length of reinforcement with a diameter of 12 millimeters.
For ease of calculations, it is best to use a special table of reinforcement data, which is available in any specialized hardware store. These tables indicate the ratios of length, width and density of each reinforcing material, as well as their specific gravity calculated per cubic meter.
When purchasing a small quantity of reinforcement, its weight is indicated in kilograms. But if the purchase occurs in higher mass quantities, then tons are used to indicate weight. In any case, if you know the price of 1 meter of reinforcement with a diameter of 12 millimeters, you can easily calculate the cost of cash costs for the total length of the reinforcement.
Reinforcement weight
For the accuracy of construction work, as well as for calculating the funds spent on reinforcement, it is necessary to know its weight and other parameters.
Finding out the weight is quite simple: to do this, you need to add up the total weight of all the rods used for construction and divide the amount by the number of linear meters.
But linear meters have different price characteristics, which are also related to the parameters of the fittings, in particular the diameter. To do this, you need to use the calculation table of reinforcement parameters, which indicates that reinforcement with a diameter of 12 millimeters has a weight of 0.88 kilograms per length of one meter.
Obviously, to calculate the cost, it is necessary to know all the parameters of this type of reinforcement that are associated with the linear meter. So, in one ton of rods with a diameter of 12 millimeters there are 1126 meters of reinforcement.
Source: http://poznaibeton.ru/beton/ves-metra-armatury.html
How many rods of 12 rebar are in a ton?
Reinforcement is a set of interconnected elements that, when working together with concrete in reinforced concrete structures, perceive tensile stresses (although they can also be used to strengthen concrete in a compressed zone).
The main application of periodic profile reinforcing steel is in the construction of foundations and walls of buildings and structures made of monolithic concrete.
When carrying out concrete work, a significant investment of time and money requires the installation of a reinforced frame to reinforce structures made from reinforcing mesh.
To calculate the order volume, you need to know how many kg per meter of reinforcement and the number of linear meters of reinforcing steel.
The weight of a meter of reinforcement is presented in the table of the ratio of diameter and weight of 1 m. Knowing the weight of reinforcing steel according to GOST 5781-82, you can estimate the reinforcement coefficient of the structure (the ratio of the mass of the reinforcement to the volume of concrete) and determine how much material is needed for the foundation (per cube of concrete)
A linear meter of reinforcement is individual reinforcing bars of a smooth and periodic profile 1 meter long, the weight of which depends on the diameter of the reinforcing steel GOST 5781-82 (from a range of diameter sizes of periodic steel - 6, 8.10, 12, 14, 16, 18.20, 22, 25, 28, 32, 36, 40, 45, 50, 55, 60, 70, 80 mm).
How much does the reinforcing mesh weigh for screeding, performing plastering work, for making a reinforced concrete foundation frame (concrete + connected reinforcement bars), what is the weight of the reinforcing mesh for brickwork, depends on the size of the cards (length, width of the canvas), the size of the cell (square mm x mm ) and reinforcing wire diameter (mm).
Construction organizations use reinforcement produced in Ukraine, the weight of which meets the requirements of GOST, since domestic reinforcing steel is of sufficiently high quality and complies with all GOSTs and standards for rolled metal.
The weight of the reinforcement is selected depending on the types according to GOST, diameter sizes (see.
table - “Specific gravity of reinforcement in a linear meter”) and the scope of application of the periodic profile.
The weight of a linear meter of reinforcement depends on the shape of the surface of the periodic profile: corrugated or smooth on the outside. Protrusions in the form of ribs, corrugations on the surface of periodically profiled reinforcing steel bars or ribbed wire steel significantly improve adhesion to concrete and its characteristics.
The range of reinforcement, depending on the manufacturing technology of reinforcing steel for reinforced concrete structures, is divided into hot-rolled rod and cold-drawn wire steel.
The weight of 1 m of hot-rolled reinforcement does not depend on its basic mechanical characteristics, which are divided into six assortment classes depending on the strength of the metal and steel grade, with the symbol: AI, A-II, A-III, A-IV, AV, A- VI.
| Reinforcing steel class | Profile diameter, mm | Reinforcement steel grade |
| AI (A240) | 6-40 | St3kp, St3ps, St3sp |
| A-II (A300) | 10-40 40-80 | St5sp, St5ps 18G2S |
| Ac-II (Ac300) | 10-32 (36-40) | 10GT |
| A-III (A400) | 6-40 6-22 | 35GS, 25G2S 32G2Rps |
| A-IV (A600) | 10-32 (6-8)(36-40) | 80С 20ХГ2Ц |
| AV (A800) | (6-8) 10-32(36-40) | 23Х2Г2Т |
| A-VI (A1000) | 10-22 | 22Kh2G2AYu, 22Kh2G2R, 20Kh2G2SR |
For example, A3 construction reinforcement is used to strengthen concrete structures of prefabricated buildings and is widely used by construction companies in Kyiv. The actual weight of construction reinforcement consists of the mass of the reinforcement frames of the elements (foundation, walls, concrete floors) of a monolithic building, welded mesh, which are then filled with concrete mortar over the formwork.
The production of reinforcing steel in Ukraine is carried out using technologies developed in Soviet times in the field of metal processing, and, as a rule, on equipment inherited from the USSR, and that is why domestic manufacturers sell reinforcing steel at a fairly affordable price with good quality and compliance with GOST requirements .
Reinforcement 8, 10, 12, 14, 16, 18, 20, 22, 25 are the most popular in terms of the diameter of the periodic profile, sold by Ukrainian manufacturers. Imported analogues have a higher price.
Before being sold from metal warehouses, fittings in Ukraine undergo step-by-step quality control during the production process, which guarantees high quality that meets state standards GOST.
What is the weight of the reinforcement along its length?
The weight of the reinforcing steel required for purchase is calculated by multiplying the total length of all the bars in the bundle by the weight of a linear meter of reinforcement (see the table of mass 1 m and how many meters are in a ton of reinforcement). Conversion from meters to tons is carried out by multiplying the specific weight of the reinforcement (weight of 1 meter) by the number of linear meters.
Below is a table of reinforcement sections, the specific weight of 1 linear meter A1 (A240), A2 (A300), A3 (A400), A4 (A800), A5 (A800), A6 (A1000), the number of meters per ton to convert weight to total the length of all the rods in the package or coil.
The reinforcement in coils allows you to cut rods of any required length to size, which will reduce the amount of waste and eliminate the need to splice individual rods of standard length (6 or 12 meters).
Reinforcing steel weight table - How much does 1 m of reinforcement weigh?
| Diameter of fittings, mm | Weight of 1 meter of reinforcement, kg | Linear meters per ton | Maximum weight deviations in % |
| d 6 | 0,222 | 4504,5 | +9,0 -7,0 |
| d 8 | 0,395 | 2531,65 | +9,0 -7,0 |
| d 10 | 0,617 | 1620,75 | +5,0 -6,0 |
| d 12 | 0,888 | 1126,13 | +5,0 -6,0 |
| d 14 | 1,21 | 826,45 | +5,0 -6,0 |
| d 16 | 1,58 | 632,91 | +3,0 -5,0 |
| d 18 | 2 | 500 | +3,0 -5,0 |
| d 20 | 2,47 | 404,86 | +3,0 -5,0 |
| d 22 | 2,98 | 335,57 | +3,0 -5,0 |
| d 25 | 3,85 | 259,74 | +3,0 -5,0 |
| d 28 | 4,83 | 207,04 | +3,0 -5,0 |
| d 32 | 6,31 | 158,48 | +3,0 -4,0 |
| d 36 | 7,99 | 125,16 | +3,0 -4,0 |
| d 40 | 9,87 | 101,32 | -+3,0 -4,0 |
| d 45 | 12,48 | 80,13 | +3,0 -4,0 |
| d 50 | 15,41 | 64,89 | +2,0 -4,0 |
| d 55 | 18,65 | 53,62 | +2,0 -4,0 |
| d 60 | 22,19 | 45,07 | +2,0 -4,0 |
| d 70 | 30,21 | 33,1 | +2,0 -4,0 |
| d 80 | 39,46 | 25,34 | +2,0 -4,0 |
Calculation of the weight of reinforcement, welded mesh
If you don’t have a reinforcement calculation table or an online metal calculator at hand, then you can calculate the total weight of the reinforcing mesh yourself by determining the total length of the wire that makes up the welded mesh measuring 1 m2 and multiplying the number of meters by the specific weight of a linear meter of wire.
In the absence of a reference book, you can calculate the weight of a linear meter of reinforcement yourself, using a regular calculator. The volume of metal in 1 meter of steel cylinder is 1 m x (3.14 x D x D/4). In parentheses is the geometric area of a circle with diameter D. The weight of the rod is obtained by multiplying the volume by the specific weight of the reinforcement, which is equal to 7850 kg/m3.
Using this method, you can calculate how many kg are in a meter of reinforcement, and convert tons into meters.
For example, using a calculator, we will calculate the weight of 1 m of reinforcement with a diameter of 12 mm: Volume of metal - 1 m x (3.14 x 0.012 m x 0.012 m/4) = 0.00011304 m3,
Specific gravity - 0.00011304 m3 x 7850 kg/m3 = 0.887 kg. Approximately equal to the value in the table of reinforcement with theoretic weight.
If the length of the reinforcement is 12 m, then we substitute the required value of the rolled steel length into the formula and calculate the weight of the rods. To determine the weight of the mesh, you need to multiply the resulting mass of 1 m2 of mesh by the number of square meters in the welded reinforcement frame.
One more example. Let's calculate the weight of a 100x100x4 mesh with an area of 1 m2. The welded mesh consists of 18 welded reinforcing bars 1 m long. The total length of the rods will be 18x1=18 meters. The specific gravity of 4mm reinforcing wire is 0.092 kg/m. Then the mass of a linear meter of mesh with a height of 1 m will be 18x0.092 = 1.66 kg/m2 + 1% of the mass of welding materials.
Source: https://betfundament.com/skolko-hlystov-12-armatury-v-tonne/
A12 mm fittings: characteristics, distinctive features, how much a linear meter weighs
Reinforcement refers to metal rods, rods or ropes of various shapes and cross-sections intended for construction work to fasten specialized structures. Reinforcement is indispensable in the manufacture of any types of devices made of reinforced concrete in order to enhance its strength.
According to its characteristics, it is divided into strength classes and comes in different diameters, which affects the effectiveness of its use in reinforced concrete building structures. This article will help answer the questions “How many meters are there in a ton of reinforcement?” and “How much does a meter of reinforcement weigh?”
In terms of labor costs in production, the presented rolled metal can be:
- light (with a diameter of up to 12 mm);
- heavy (with a diameter of 12 - 40 mm).
With a steel rod diameter of 12 mm, it is usually called reinforcement 12 ( A12 ) - this is the most popular rolled metal product in domestic construction.
Characteristics of A12 fittings
During the manufacturing process of A12, GOST 5781–82 is strictly observed, and according to its purpose it is classified into prestressed and non-prestressed . Based on the choice of production technology, the following types of fittings 12 are distinguished:
- cold drawn;
- hot rolled
Cold-drawn reinforcement A12 is necessary for the production of reinforced mesh; it is supplied in coils (rolls) of 6-12 meters and is a reinforcing wire.
Hot-rolled A12, being a high-quality type of rolled metal, is produced from steel with a rounded cross-section, and is used in the reinforcement of stressed and ordinary structures, imparts sufficient strength to reinforced concrete structures and prevents damage due to mechanical deformations.
Distinctive features of A12 fittings
These rolled metal products can be made from steel of different grades, which depends on its application and the requirements for its characteristics. Most often, products made from low-alloy structural steel are required. This is due to the fact that such products are easily subjected to arc welding.
The main purpose of A12 is the strengthening of reinforced concrete structures , as well as the formation of frame devices to resist increased loads. A diameter of 12 mm is the minimum for the construction of a strip foundation and its grillages, if you knit a reinforcement frame of four rods. Rentals by class are:
- smooth profile (without corrugation) - class A1;
- periodic profile (with transverse corrugation at an angle to the axis of the rod) - class A3.
This construction metal product is presented from the manufacturer in rods or coils . The scope of its application is very wide.
For the construction of the foundation, it is recommended to use hot-rolled reinforcement in the form of rods with oblique corrugation, the presence of which ensures optimal adhesion to concrete. This interaction of materials ensures the strength and durability of a reinforced concrete building structure.
The transverse arrangement of reinforced rods in the foundation prevents concrete cracking and reduces the force load on the resulting structure, and also protects it from deformation.
Advantages of A12 reinforcement , which are manifested in construction:
- high degree of strength;
- relatively high ductility;
- minimal susceptibility to corrosion;
- high resistance to thermal, chemical and mechanical influences;
- the ability to create various structural configurations by welding and mechanical connections;
- Possibility of use in stressed structures made of reinforced concrete.
There is currently a fairly large selection of grade steel on the construction raw materials market. Recently, there has been a gradual transition, using the example of Europe, to products made from A500C steel instead of the previously popular A400.
This fact, quite logically, is explained by the fact that while fully maintaining the quality characteristics of rolled products, its production cost is reduced by up to 10% due to savings in raw materials during construction operations.
For construction calculations, this amount of expenses is simply colossal.
A special feature of the production of rolled products from this steel grade is the absence of oxidation and, as a consequence, the absence of rust. At the same time, mechanical, chemical and thermal qualities remain at a very high level.
Replacement of steel grade A400 by grade A500C in rolled products makes it possible to reduce its concentration during concreting and, as a consequence, the consumption of A12 reinforcement. The technical characteristics of the steel used do not allow the welds of the finished structure to collapse.
All this leads to increased strength of floors, columns and walls of buildings.
Weight per linear meter of reinforcement 12
For construction work, it is customary to calculate the amount of reinforcement in linear meters, but it is sold mainly by weight.
It turns out that in order to buy the required amount of rolled metal and know exactly its cost, it is necessary to convert the calculated need in meters into weight units, that is, kilograms, tons, etc.
To do this, you can use the table presented . An alternative to the tabular data presented is to independently calculate the data based on the diameter size.
| Diameter, mm | Diameter, m | Weight of 1 meter, kg | Quantity m in 1t |
| 6 | 0.06 | 222 | 4504.5 |
| 8 | 0.08 | 395 | 2531.65 |
| 10 | 0.1 | 617 | 1620.75 |
| 12 | 0.12 | 888 | 1126.13 |
| 14 | 0.14 | 1210 | 826.45 |
| 16 | 0.16 | 1580 | 632.91 |
| 18 | 0.18 | 2000 | 500 |
| 20 | 0.2 | 2470 | 404.86 |
| 22 | 0.22 | 2980 | 335.57 |
| 25 | 0.25 | 3850 | 259.74 |
| 28 | 0.28 | 4830 | 207.04 |
| 32 | 0.32 | 6310 | 158.48 |
| 36 | 0.36 | 7990 | 125.16 |
| 40 | 0.4 | 9870 | 101.32 |
The weight of one meter of reinforced steel is shown in the table as the ratio of the diameter to its weight . Having information about the weight of reinforcing steel, it is possible to determine the coefficient of reinforcement of the structure (the ratio of the weight of rolled metal to the volume of concrete).
In order to calculate the need for reinforcement, you will need data on how many linear meters one ton of rolled metal contains. The number of meters in a ton is a value that depends on several factors. From the presented table it is clearly seen that the footage largely depends on the class of reinforcement.
How many meters are there in a ton of reinforcement 12?
In accordance with building regulations, the amount of reinforcement in a strip foundation as a percentage of the reinforced concrete element in the cross-section must be at least 0.1%. In an example it looks like this.
If the cross-sectional area of the strip foundation is 100*240=2400 square cm, then the estimated number of rolled rods for longitudinal reinforcement is found by multiplying the resulting volume of the foundation by 0.001, that is, 2400*0.001=2.4 square cm.
Next, you should resort to the reference data in the table from the manual on the reinforcement of reinforced concrete elements of monolithic buildings. Since we are interested in reinforcement with a diameter of 12, it is obvious that only 2 reinforced rods are needed for the calculated volume of the foundation. The calculation of the consumption of reinforced steel for a slab foundation is similar.
Source: https://plita.guru/raboty/armirovanie/skolko-vesit-armatura-12-mm-i-ee-osobennosti.html
Weight table for plastic fittings
Today on the market you can find both outdated steel reinforcement with a diameter of 6 to 80 mm, and new modern composite reinforcement made from the following materials: basalt plastic and fiberglass.
Metal products are highly susceptible to corrosion, rust and other chemical processes; they are heavy and not always convenient to transport.
But composite reinforcement is not subject to either physical or chemical influences, it is quite durable and much less is required compared to steel reinforcement.
As a result, the cost of construction where non-metallic reinforcement is used is significantly reduced (you can compare the price of plastic reinforcement with the price of metal reinforcement here). Therefore, using ASC for the construction of concrete structures is reasonable and profitable.
Many people know that when calculating the required amount of material for reinforcing concrete buildings and structures, it is necessary to use the equality of loads applied to all reinforcing elements. Replacing conventional steel reinforcement with a new composite material involves selecting a profile of fiberglass or basalt-plastic reinforcement. The profile must be of such a diameter that its strength is equal to the strength of conventional steel reinforcement of a given diameter.
Table of correspondence between the diameters of plastic reinforcement and steel reinforcement of class A3 (A400C) when replacing:
| Steel reinforcement A3 (A400C), diameter | Plastic fittings, diameter |
| 6 mm | 4 mm |
| 8 mm | 6 mm |
| 10 mm | 8 mm |
| 12 mm | 8 mm |
| 14 mm | 10 mm |
| 16 mm | 12 mm |
| 18 mm | 14 mm |
| 20 mm | 16 mm |
| 22 mm | 18 mm |
| 25 mm | 20 mm |
This table shows the weight of plastic reinforcement and steel reinforcement:
| Reinforcement diameter | Weight of one linear meter of steel reinforcement (according to GOST 5781-82) | Weight of one linear meter of composite fiberglass reinforcement |
| 6 mm | 0.222 kg | 0.049 kg |
| 8 mm | 0.503 kg | 0.082 kg |
| 10 mm | 0.785 kg | 0.134 kg |
| 12 mm | 1.131 kg | 0.185 kg |
| 14 mm | 1.21 kg | 0.276 kg |
| 16 mm | 1.58 kg | 0.352 kg |
| 18 mm | 2.0 kg | 0.44 kg |
From the tables above it is clear that using plastic reinforcement is much more profitable than ordinary steel.
Return to list
Source: https://izh-reduktor.ru/about/art/article/tablica-vesov-plastikovoj-armatury.html
Weight of 1 linear meter of reinforcement
When using rebar to strengthen foundations or other structures, an important question arises: how much does the rebar weigh? This is necessary in order to calculate the required volume of materials, since reinforcing bars are usually sold by weight.
How to calculate the weight of reinforcement?
“Weight classes” are best described in relation to their diameter. For clarity, we present them in the table.
Knowing the weight of 1 meter of reinforcement, you can determine the required quantity. For example, when strengthening the foundation, the required amount of reinforcement per meter is calculated, comparing it with the corresponding diameter, you can calculate the required quantity to order.
In addition, having knowledge of the weight of a meter of reinforcement makes it possible to estimate:
- reinforcement coefficient (weight of reinforcement divided by volume of poured concrete);
- required material for 1 cubic meter of foundation concrete.
How much does the reinforcement weigh in linear meters?
Here the weight according to GOST depends directly on the diameter, since each 1 m rod of different diameter will have a different weight. For example, you use d 20 material, which requires 200 meters in length. The weight of fittings in this category is 2.47 kg per meter, so you need to order 200x2.47 = 494 (kg). In addition, the weight, based on linear meters, depends on the nature of the profile surface: will it be corrugated or smooth.
The weight of a meter of mesh reinforcement for the frame of a reinforced concrete foundation, screed or plastering work, brickwork will depend on the size of the fabric, the cell, as well as on the diameter of the wire itself.
How much does a meter of reinforcement weigh based on length? For purchase, the calculation is carried out taking into account the total length of the rods that are in the pack and the weight of a linear meter (according to the table). In order to convert from meters to tons, the specific gravity is multiplied by the number of linear meters.
—
Weight per linear meter of reinforcement, table
Weight of 1 linear meter of reinforcement
When it is planned to build a house or a country cottage, a project is drawn up, building materials are selected, and the cost of future construction is calculated. The cost item also includes the cost of reinforcing the future structure.
It is also important to calculate the weight, quantity and cost of reinforcement. The total weight of the required amount of reinforcement is calculated by multiplying the weight of 1 linear meter of reinforcement by the total length of all rods.
For construction, reinforcement with a diameter of 10 to 16 mm is most often used. The fittings are packaged in packs. This can be reinforcement of a certain length (11.7 m) or an unmeasured length from 2 meters to 11.7.
The required amount of reinforcement is often calculated in linear meters. When purchasing, reinforcement is calculated in tons, so to find out the cost of the required reinforcement, you will need such an indicator as its weight.
The thinner the reinforcement bars, the less weight. Let's consider the weight of 1 linear meter of reinforcement of different diameters.
If the diameter of the rod is 6 mm, then the weight of 1 meter of reinforcement will be equal to 0.222 kg. The mass of 1 linear meter with a diameter of 8 mm will be 0.395 kg. Fittings with a diameter of 10 mm weigh 0.617 kg, with a diameter of 12 mm - 0.888 kg. If the diameter is 14 mm, then the weight is 1.210 kg, a rod with a diameter of 16 mm will weigh 1.580 kg.
Stainless steel fittings
Where stainless steel fittings are used.
The cost of reinforcement for the foundation
You can find out how much foundation reinforcement costs here.
Calculation of the amount of reinforcement for the foundation
How to calculate how much reinforcement will be needed for a foundation can be found in this article.
Number of reinforcement per foundation
How much reinforcement is needed for the foundation is here.
Cost of fittings
About the cost of fittings here.
What reinforcement is needed for the foundation
What kind of reinforcement is best to use for building a foundation?
Reinforcement for columnar foundation
What kind of reinforcement is needed for the construction of a columnar foundation.
How to determine the diameter of reinforcement
Reinforcement definition table here.
Reinforcement density
Find out what the density of the reinforcement is here.
Weight of 1 linear meter of reinforcement
How much does one linear meter of reinforcement weigh, here.
Reinforcement meter weight
The weight of a linear meter of reinforcement may be different for different reinforcement. What determines the weight of a meter of reinforcement? The weight of one linear meter of reinforcement depends primarily on the DIAMETER OF THE REINFORCEMENT and for each of the possible options for the diameter of the reinforcement according to GOST, the value of the weight of one linear meter will be a constant value #8212; constant.
Why are we discussing the LINEAR meter of reinforcement?
The length of the reinforcement is measured in meters, and the length is indicated in linear meters.
When performing construction work and manufacturing metal structures, it is convenient to move from estimating the amount of reinforcement in tons to a more applied system #8212; estimate the amount of reinforcement in meters. And any materials whose main characteristic is the length of the rolled product are usually called MOLDING in construction.
The unit of measurement for any objects with length as their main characteristic (long objects, products and materials) is in mathematics the LINEAR METER. Likewise, with reinforcement, it is most convenient for us to estimate its quantity in linear meters.
And in most tables for calculating the weight of reinforcement, the information is provided precisely based on what you can directly measure with a tape measure #8212; how many linear meters of reinforcement do you have available?
How to measure the diameter of reinforcement?
But directly measuring the diameter of reinforcement or reinforcing bar is quite difficult. If we had a classic round rod, there would be no problems. But the fittings #8212; This is NOT a SMOOTH rod .
and a product that has its own specific shape and relief. By measuring the diameter of the reinforcement in different sections of the rod, we get quite different values.
In practice, the diameter of the reinforcement is not measured, but is taken from the accompanying documents, which indicate the NOMINAL or CONDITIONAL DIAMETER OF THE REINFORCEMENT .
What is the NOMINAL DIAMETER of the fittings?
Reinforcement diameter photo
What the nominal diameter of reinforcement is is explained in the reference book on rolled metal: the diameter of the reinforcement roughly corresponds to the diameter of a round rod with the same cross-section. DO NOT HESITATE TO OPEN IMAGE #8212; explanatory notes will be visible there.
How to use the table for calculating the weight of reinforcement?
Calculation of reinforcement weight photo
In fact, using the table for calculating the weight of reinforcement is very simple and convenient. There are quite detailed tables of the weight of linear meta reinforcement . taking into account different types of fittings according to GOST (out of three in fact). I'll show you with an example. So, for example, you want to buy 25 meters of reinforcement with a diameter of 16 mm. Perhaps you need to reinforce the foundation for a fence or solve some other construction problem.
When selling reinforcement, the seller usually sets the price of the reinforcement in tons; it is in tonnage that he buys it at the factory. He sells you reinforcement in meters, in linear meters, of which you need exactly 25 m. That is, the price of reinforcement per ton tells you absolutely nothing.
In order to somehow convert the number of linear meters of reinforcement you have into categories close to: price per ton, you need to calculate how much your 25 meters of reinforcement with a diameter of 16 mm weigh. We find line #8212 in the table for calculating the weight of reinforcement; the weight of a linear meter of reinforcement is 16 mm, on the opposite side in the second column the weight of the meter is indicated in kilograms #8212; 1,580 kg.
Now, knowing the weight of one meter, we must multiply it by the number of meters #8212; 1.580 x 25 = 39.5 kg. That is, your 25 linear meters weigh exactly 39.5 kg. This is the THEORETICAL WEIGHT OF A METER OF REINFORCEMENT.
Does the theoretical weight of the reinforcement coincide with the real one and is it necessary to weigh the reinforcement?
In fact, the theoretical weight of reinforcement #8212; this is a pretty accurate guideline. Weighing the reinforcement on a scale will show a slightly different weight than the theoretical #8212; This is fine. But if the weight value obtained after weighing is very different . you need to deal with the scales or with your calculations, checking both.
Profile number
(nominal diameter)
Source: https://armaturasila.ru/ves-armatury/ves-1-pog-m-armatury.html
Reinforcement weight table per 1 meter
Why might the weight of 1 meter of 12 mm reinforcement be required? For example, when pouring the foundation for a private house, builders can tell you the amount of reinforcement in meters, but at metal warehouses, as a rule, reinforcement is sold and the price per ton is indicated. In this case, knowing the weight of one meter, you can calculate how much reinforcement you will need in tons.
For greater convenience, we have provided a second table, which indicates how many meters of reinforcement are contained in one ton for each diameter.
Here's an example of a calculation:
You need 750 meters of 12mm a500c reinforcement (read: decoding of a500c reinforcement).
We look at the line in the first table corresponding to 12 mm reinforcement; the weight of 1 meter is 0.888 kg.
In total we get 750 * 0.888 = 666 kg.
Weight of 1 meter reinforcement table
Reinforcement diameter (mm) Weight kg/meter| 5,5 | 0,187 |
| 6 | 0,222 |
| 8 | 0,395 |
| 10 | 0,617 |
| 12 | 0,888 |
| 14 | 1,210 |
| 16 | 1,580 |
| 18 | 2,000 |
| 20 | 2,470 |
| 22 | 2,980 |
| 25 | 3,850 |
| 28 | 4,830 |
| 32 | 6,310 |
| 36 | 7,990 |
| 40 | 9,870 |
| 45 | 12,480 |
| 50 | 15,410 |
In industrial construction, a huge amount of reinforcement is used, which is most often supplied in tons. To perform the necessary calculations, you need to know the total length of the existing reinforcement; this can be easily done using the table below.
Calculation example:
You know that you have 25 tons of 10mm reinforcement.
Using the table, we find the number of meters in a ton corresponding to 10 mm reinforcement: 1620 meters.
Total total length of the reinforcement: 25 * 1620 = 40500 meters.
How many meters in 1 ton of reinforcement table
Diameter of reinforcement (mm) Meters per ton| 5,5 | 5347 |
| 6 | 4504 |
| 8 | 2531 |
| 10 | 1620 |
| 12 | 1126 |
| 14 | 826 |
| 16 | 633 |
| 18 | 500 |
| 20 | 405 |
| 22 | 335 |
| 25 | 260 |
| 28 | 207 |
| 32 | 158 |
Source: http://stroitelnyj-portal.ru/materialy-instrumenty/ves-armaturyi-tablitsa-za-1-metr.html
Reinforcement weight. Weight per linear meter of reinforcement GOST 5781-82
Reinforcement is a set of interconnected elements that, when working together with concrete in reinforced concrete structures, perceive tensile stresses (although they can also be used to strengthen concrete in a compressed zone).
The main application of periodic profile reinforcing steel is in the construction of foundations and walls of buildings and structures made of monolithic concrete. When carrying out concrete work, a significant investment of time and money requires the installation of a reinforced frame to reinforce structures made from reinforcing mesh. To calculate the order volume, you need to know how many kg per meter of reinforcement and the number of linear meters of reinforcing steel.
The weight of a meter of reinforcement is presented in the table of the ratio of diameter and weight of 1 m. Knowing the weight of reinforcing steel according to GOST 5781-82, you can estimate the reinforcement coefficient of the structure (the ratio of the mass of the reinforcement to the volume of concrete) and determine how much material is needed for the foundation (per cube of concrete)
A linear meter of reinforcement is individual reinforcing bars of a smooth and periodic profile 1 meter long, the weight of which depends on the diameter of the reinforcing steel GOST 5781-82 (from a range of diameter sizes of periodic steel - 6, 8.10, 12, 14, 16, 18.20, 22, 25, 28, 32, 36, 40, 45, 50, 55, 60, 70, 80 mm - see RANGE OF FITTINGS).
How much does the reinforcing mesh weigh for screeding, performing plastering work, for making a reinforced concrete foundation frame (concrete + connected reinforcement bars), what is the weight of the reinforcing mesh for brickwork, depends on the size of the cards (length, width of the canvas), the size of the cell (square mm x mm ) and reinforcing wire diameter (mm).
Construction organizations use reinforcement produced in Ukraine, the weight of which meets the requirements of GOST, since domestic reinforcing steel is of sufficiently high quality and complies with all GOSTs and standards for rolled metal.
The weight of the reinforcement is selected depending on the types according to GOST, diameter sizes (see.
table - “Specific gravity of reinforcement in a linear meter”) and the scope of application of the periodic profile.
The weight of a linear meter of reinforcement depends on the shape of the surface of the periodic profile: corrugated or smooth on the outside. Protrusions in the form of ribs, corrugations on the surface of periodically profiled reinforcing steel bars or ribbed wire steel significantly improve adhesion to concrete and its characteristics.
The range of reinforcement, depending on the manufacturing technology of reinforcing steel for reinforced concrete structures, is divided into hot-rolled rod (A1 - A240, A2 - A300, A3 - A400, A500, A600, A800, A1000) and cold-drawn wire steel (VR-1).
The weight of 1 m of hot-rolled reinforcement does not depend on its basic mechanical characteristics, which are divided into six assortment classes depending on the strength of the metal and steel grade, with the symbol: AI, A-II, A-III, A-IV, AV, A- VI.
| Reinforcing steel class | Profile diameter, mm | Reinforcement steel grade |
| AI (A240) | 6-40 | St3kp, St3ps, St3sp |
| A-II (A300) | 10-40 40-80 | St5sp, St5ps 18G2S |
| Ac-II (Ac300) | 10-32 (36-40) | 10GT |
| A-III (A400) | 6-40 6-22 | 35GS, 25G2S 32G2Rps |
| A-IV (A600) | 10-32 (6-8) (36-40) | 80С 20ХГ2Ц |
| AV (A800) | (6-8) 10-32 (36-40) | 23Х2Г2Т |
| A-VI (A1000) | 10-22 | 22Kh2G2AYu, 22Kh2G2R,20Kh2G2SR |
For example, A3 construction reinforcement is used to strengthen concrete structures of prefabricated buildings and is widely used by construction companies in Kyiv. The actual weight of construction reinforcement consists of the mass of the reinforcement frames of the elements (foundation, walls, concrete floors) of a monolithic building, welded mesh, which are then filled with concrete mortar over the formwork.
The production of reinforcing steel in Ukraine is carried out using technologies developed in Soviet times in the field of metal processing, and, as a rule, on equipment inherited from the USSR, and that is why domestic manufacturers sell reinforcing steel at a fairly affordable price with good quality and compliance with GOST requirements .
Reinforcement 8, 10, 12, 14, 16, 18, 20, 22, 25 are the most popular in terms of the diameter of the periodic profile, sold by Ukrainian manufacturers. Imported analogues have a higher price.
Before being sold from metal warehouses, fittings in Ukraine undergo step-by-step quality control during the production process, which guarantees high quality that meets state standards GOST.
Table of weight of reinforcing steel. How much does 1m of reinforcement weigh?
| Diameter of fittings, mm | Weight of 1 meter of reinforcement, kg | Linear meters per ton | Maximum weight deviations in % |
| d 6 | 0,222 | 4504,5 | +9,0 -7,0 |
| d 8 | 0,395 | 2531,65 | +9,0 -7,0 |
| d 10 | 0,617 | 1620,75 | +5,0 -6,0 |
| d 12 | 0,888 | 1126,13 | +5,0 -6,0 |
| d 14 | 1,21 | 826,45 | +5,0 -6,0 |
| d 16 | 1,58 | 632,91 | +3,0 -5,0 |
| d 18 | 2 | 500 | +3,0 -5,0 |
| d 20 | 2,47 | 404,86 | +3,0 -5,0 |
| d 22 | 2,98 | 335,57 | +3,0 -5,0 |
| d 25 | 3,85 | 259,74 | +3,0 -5,0 |
| d 28 | 4,83 | 207,04 | +3,0 -5,0 |
| d 32 | 6,31 | 158,48 | +3,0 -4,0 |
| d 36 | 7,99 | 125,16 | +3,0 -4,0 |
| d 40 | 9,87 | 101,32 | -+3,0 -4,0 |
| d 45 | 12,48 | 80,13 | +3,0 -4,0 |
| d 50 | 15,41 | 64,89 | +2,0 -4,0 |
| d 55 | 18,65 | 53,62 | +2,0 -4,0 |
| d 60 | 22,19 | 45,07 | +2,0 -4,0 |
| d 70 | 30,21 | 33,1 | +2,0 -4,0 |
| d 80 | 39,46 | 25,34 | +2,0 -4,0 |
Calculation of the weight of reinforcement, welded mesh
If you don’t have a reinforcement calculation table or an online metal calculator at hand, then you can calculate the total weight of the reinforcing mesh yourself by determining the total length of the wire that makes up the welded mesh measuring 1 m2 and multiplying the number of meters by the specific weight of a linear meter of wire.
In the absence of a reference book, you can calculate the weight of a linear meter of reinforcement yourself, using a regular calculator. The volume of metal in 1 meter of a steel cylinder is 1 m x (3.14 x D x D/4) . In parentheses is the geometric area of a circle with diameter D. The weight of the rod is obtained by multiplying the volume by the specific weight of the reinforcement, which is equal to 7850 kg/m3.
Using this method, you can calculate how many kg are in a meter of reinforcement, and convert tons into meters.
For example, using a calculator, we will calculate the weight of 1 m of reinforcement with a diameter of 12 mm: Volume of metal - 1 m x (3.14 x 0.012 m x 0.012 m/4) = 0.00011304 m3,
Specific gravity - 0.00011304 m3 x 7850 kg/m3 = 0.887 kg. Approximately equal to the value in the table of reinforcement with theoretic weight.
If the length of the reinforcement is 12 m, then we substitute the required value of the rolled steel length into the formula and calculate the weight of the rods. To determine the weight of the mesh, you need to multiply the resulting mass of 1 m2 of mesh by the number of square meters in the welded reinforcement frame.
One more example. Let's calculate the weight of a 100x100x4 mesh with an area of 1 m2. The welded mesh consists of 18 welded reinforcing bars 1 m long. The total length of the rods will be 18x1=18 meters. The specific gravity of 4mm reinforcing wire is 0.092 kg/m. Then the mass of a linear meter of mesh with a height of 1 m will be 18x0.092 = 1.66 kg/m2 + 1% of the mass of welding materials.
Source: https://sbk.ltd.ua/ru/sortament-ves-metalloprokata/136-ves-pogonnogo-metra-armatury-gost-5781-82.html
