How much does 28 reinforcement weigh?

Reinforcement weight table per 1 meter

Why might the weight of 1 meter of 12 mm reinforcement be required? For example, when pouring the foundation for a private house, builders can tell you the amount of reinforcement in meters, but at metal warehouses, as a rule, reinforcement is sold and the price per ton is indicated. In this case, knowing the weight of one meter, you can calculate how much reinforcement you will need in tons.

For greater convenience, we have provided a second table, which indicates how many meters of reinforcement are contained in one ton for each diameter.

Here's an example of a calculation:

You need 750 meters of 12mm a500c reinforcement (read: decoding of a500c reinforcement).

We look at the line in the first table corresponding to 12 mm reinforcement; the weight of 1 meter is 0.888 kg.

In total we get 750 * 0.888 = 666 kg.

Weight of 1 meter reinforcement table

Reinforcement diameter (mm) Weight kg/meter

5,5	0,187
6	0,222
8	0,395
10	0,617
12	0,888
14	1,210
16	1,580
18	2,000
20	2,470
22	2,980
25	3,850
28	4,830
32	6,310
36	7,990
40	9,870
45	12,480
50	15,410

In industrial construction, a huge amount of reinforcement is used, which is most often supplied in tons. To perform the necessary calculations, you need to know the total length of the existing reinforcement; this can be easily done using the table below.

Calculation example:

You know that you have 25 tons of 10mm reinforcement.

Using the table, we find the number of meters in a ton corresponding to 10 mm reinforcement: 1620 meters.

Total total length of the reinforcement: 25 * 1620 = 40500 meters.

How many meters in 1 ton of reinforcement table

Diameter of reinforcement (mm) Meters per ton

5,5	5347
6	4504
8	2531
10	1620
12	1126
14	826
16	633
18	500
20	405
22	335
25	260
28	207
32	158

Source: http://stroitelnyj-portal.ru/materialy-instrumenty/ves-armaturyi-tablitsa-za-1-metr.html

Reinforcement weight. Weight per linear meter of reinforcement GOST 5781-82

Reinforcement is a set of interconnected elements that, when working together with concrete in reinforced concrete structures, perceive tensile stresses (although they can also be used to strengthen concrete in a compressed zone).

The main application of periodic profile reinforcing steel is in the construction of foundations and walls of buildings and structures made of monolithic concrete. When carrying out concrete work, a significant investment of time and money requires the installation of a reinforced frame to reinforce structures made from reinforcing mesh. To calculate the order volume, you need to know how many kg per meter of reinforcement and the number of linear meters of reinforcing steel.

The weight of a meter of reinforcement is presented in the table of the ratio of diameter and weight of 1 m. Knowing the weight of reinforcing steel according to GOST 5781-82, you can estimate the reinforcement coefficient of the structure (the ratio of the mass of the reinforcement to the volume of concrete) and determine how much material is needed for the foundation (per cube of concrete)

A linear meter of reinforcement is individual reinforcing bars of a smooth and periodic profile 1 meter long, the weight of which depends on the diameter of the reinforcing steel GOST 5781-82 (from a range of diameter sizes of periodic steel - 6, 8.10, 12, 14, 16, 18.20, 22, 25, 28, 32, 36, 40, 45, 50, 55, 60, 70, 80 mm - see RANGE OF FITTINGS).

How much does the reinforcing mesh weigh for screeding, performing plastering work, for making a reinforced concrete foundation frame (concrete + connected reinforcement bars), what is the weight of the reinforcing mesh for brickwork, depends on the size of the cards (length, width of the canvas), the size of the cell (square mm x mm ) and reinforcing wire diameter (mm).

Construction organizations use reinforcement produced in Ukraine, the weight of which meets the requirements of GOST, since domestic reinforcing steel is of sufficiently high quality and complies with all GOSTs and standards for rolled metal.

The weight of the reinforcement is selected depending on the types according to GOST, diameter sizes (see.

table - “Specific gravity of reinforcement in a linear meter”) and the scope of application of the periodic profile.

The weight of a linear meter of reinforcement depends on the shape of the surface of the periodic profile: corrugated or smooth on the outside. Protrusions in the form of ribs, corrugations on the surface of periodically profiled reinforcing steel bars or ribbed wire steel significantly improve adhesion to concrete and its characteristics.

The range of reinforcement, depending on the manufacturing technology of reinforcing steel for reinforced concrete structures, is divided into hot-rolled rod (A1 - A240, A2 - A300, A3 - A400, A500, A600, A800, A1000) and cold-drawn wire steel (VR-1).

The weight of 1 m of hot-rolled reinforcement does not depend on its basic mechanical characteristics, which are divided into six assortment classes depending on the strength of the metal and steel grade, with the symbol: AI, A-II, A-III, A-IV, AV, A- VI.

Reinforcing steel class	Profile diameter, mm	Reinforcement steel grade
AI (A240)	6-40	St3kp, St3ps, St3sp
A-II (A300)	10-40 40-80	St5sp, St5ps 18G2S
Ac-II (Ac300)	10-32 (36-40)	10GT
A-III (A400)	6-40 6-22	35GS, 25G2S 32G2Rps
A-IV (A600)	10-32 (6-8) (36-40)	80С 20ХГ2Ц
AV (A800)	(6-8) 10-32 (36-40)	23Х2Г2Т
A-VI (A1000)	10-22	22Kh2G2AYu, 22Kh2G2R,20Kh2G2SR

For example, A3 construction reinforcement is used to strengthen concrete structures of prefabricated buildings and is widely used by construction companies in Kyiv. The actual weight of construction reinforcement consists of the mass of the reinforcement frames of the elements (foundation, walls, concrete floors) of a monolithic building, welded mesh, which are then filled with concrete mortar over the formwork.

The production of reinforcing steel in Ukraine is carried out using technologies developed in Soviet times in the field of metal processing, and, as a rule, on equipment inherited from the USSR, and that is why domestic manufacturers sell reinforcing steel at a fairly affordable price with good quality and compliance with GOST requirements .

Reinforcement 8, 10, 12, 14, 16, 18, 20, 22, 25 are the most popular in terms of the diameter of the periodic profile, sold by Ukrainian manufacturers. Imported analogues have a higher price.

Before being sold from metal warehouses, fittings in Ukraine undergo step-by-step quality control during the production process, which guarantees high quality that meets state standards GOST.

What is the weight of the reinforcement along its length?

The weight of the reinforcing steel required for purchase is calculated by multiplying the total length of all the bars in the bundle by the weight of a linear meter of reinforcement (see the table of mass 1 m and how many meters are in a ton of reinforcement). Conversion from meters to tons is carried out by multiplying the specific weight of the reinforcement (weight of 1 meter) by the number of linear meters.

Below is a table of reinforcement sections, the specific weight of 1 linear meter A1 (A240), A2 (A300), A3 (A400), A4 (A800), A5 (A800), A6 (A1000), the number of meters per ton to convert weight to total the length of all the rods in the package or coil.

The reinforcement in coils allows you to cut rods of any required length to size, which will reduce the amount of waste and eliminate the need to splice individual rods of standard length (6 or 12 meters).

Table of weight of reinforcing steel. How much does 1m of reinforcement weigh?

Diameter of fittings, mm	Weight of 1 meter of reinforcement, kg	Linear meters per ton	Maximum weight deviations in %
d 6	0,222	4504,5	+9,0 -7,0
d 8	0,395	2531,65	+9,0 -7,0
d 10	0,617	1620,75	+5,0 -6,0
d 12	0,888	1126,13	+5,0 -6,0
d 14	1,21	826,45	+5,0 -6,0
d 16	1,58	632,91	+3,0 -5,0
d 18	2	500	+3,0 -5,0
d 20	2,47	404,86	+3,0 -5,0
d 22	2,98	335,57	+3,0 -5,0
d 25	3,85	259,74	+3,0 -5,0
d 28	4,83	207,04	+3,0 -5,0
d 32	6,31	158,48	+3,0 -4,0
d 36	7,99	125,16	+3,0 -4,0
d 40	9,87	101,32	-+3,0 -4,0
d 45	12,48	80,13	+3,0 -4,0
d 50	15,41	64,89	+2,0 -4,0
d 55	18,65	53,62	+2,0 -4,0
d 60	22,19	45,07	+2,0 -4,0
d 70	30,21	33,1	+2,0 -4,0
d 80	39,46	25,34	+2,0 -4,0

Calculation of the weight of reinforcement, welded mesh

If you don’t have a reinforcement calculation table or an online metal calculator at hand, then you can calculate the total weight of the reinforcing mesh yourself by determining the total length of the wire that makes up the welded mesh measuring 1 m2 and multiplying the number of meters by the specific weight of a linear meter of wire.

In the absence of a reference book, you can calculate the weight of a linear meter of reinforcement yourself, using a regular calculator. The volume of metal in 1 meter of a steel cylinder is 1 m x (3.14 x D x D/4) . In parentheses is the geometric area of ​​a circle with diameter D. The weight of the rod is obtained by multiplying the volume by the specific weight of the reinforcement, which is equal to 7850 kg/m3.

Using this method, you can calculate how many kg are in a meter of reinforcement, and convert tons into meters.

For example, using a calculator, we will calculate the weight of 1 m of reinforcement with a diameter of 12 mm: Volume of metal - 1 m x (3.14 x 0.012 m x 0.012 m/4) = 0.00011304 m3,

Specific gravity - 0.00011304 m3 x 7850 kg/m3 = 0.887 kg. Approximately equal to the value in the table of reinforcement with theoretic weight.

If the length of the reinforcement is 12 m, then we substitute the required value of the rolled steel length into the formula and calculate the weight of the rods. To determine the weight of the mesh, you need to multiply the resulting mass of 1 m2 of mesh by the number of square meters in the welded reinforcement frame.

One more example. Let's calculate the weight of a 100x100x4 mesh with an area of ​​1 m2. The welded mesh consists of 18 welded reinforcing bars 1 m long. The total length of the rods will be 18x1=18 meters. The specific gravity of 4mm reinforcing wire is 0.092 kg/m. Then the mass of a linear meter of mesh with a height of 1 m will be 18x0.092 = 1.66 kg/m2 + 1% of the mass of welding materials.

Source: https://sbk.ltd.ua/ru/sortament-ves-metalloprokata/136-ves-pogonnogo-metra-armatury-gost-5781-82.html

Fiberglass reinforcement

What is good and what is not so good. Metal reinforcement, as an obligatory component of virtually the entire range of reinforced concrete products, is perhaps the only building material that until recently had no alternative.

However, technological progress and the achievements of modern science in the field of construction have managed to break this stereotype.

In the seventies of the last century, the first tests of composite reinforcement took place and their results gave reason to assert that a worthy replacement exists and has a great future.

View from the outside

Externally, metal and fiberglass reinforcement are very similar. Meanwhile, there is a significant difference between them. For example, by color. So the silver and, often, rusty color was replaced by a material with a definitely more positive visual perception.

Let us note right away that yellow, beige, black, green, blue and other colors are in no way gradations of the material according to one or another indicator and depend only on the preferences of the manufacturer.

On a note

Today there is an opinion on the market that fiberglass reinforcement of certain colors is of higher quality or more durable. We dare to dissuade you of this. Such a wide palette is nothing more than a marketing ploy by trading organizations. In other words, the color of composite reinforcement does not have any influence, nor does it participate in the gradation of the qualities and properties of a given material.

Fiberglass reinforcement: quality and structure

The basis of the composite reinforcement material is fibers:

• Basalt;
• Carbon;
• Glass;
• Armid.

The binder for each type is complex polymers. It is their merit in the strength, ductility and other performance properties of fiberglass reinforcement.

In cross-section, fiberglass reinforcement can have either a circle or a circle with glass spiral winding. The standard winding pitch is 15 mm. The second option demonstrates greater adhesion to concrete and cement mortars and is therefore a priority for builders.

Fiberglass reinforcement: physical and performance qualities

Speaking about the advantages of composite reinforcement for foundations, let's start by listing them:

• It has a lower specific weight (as a clear example, we point out that one meter of steel reinforcement weighs the same as nine meters of carbon fiber reinforcement);
• Does not corrode and therefore does not destroy reinforced concrete structures;
• Does not conduct electric current (valuable both during installation and operation);
• Does not create radio interference;
• Not a heat conductor;
• Economical in financial terms;
• Has unlimited length (within reasonable limits, of course);
• Compact (if necessary, can be transported in coils;
• The manufacturer guarantees 80 years of trouble-free operation;
• Resistant to chemical influences;
• Has an attractive aesthetic appearance.

On a note

Since metal reinforcement in reinforced concrete products is replaced with composite reinforcement, in everyday life their names are also replaced with fiberglass reinforced concrete.

Composite reinforcement

Fiberglass reinforcement: application and installation

Installation of composite reinforcement during the construction of foundations is carried out similarly to metal reinforcement. When constructing a frame structure, the rods are fastened using wire twists or special staples (ties).

Let us add that when installing foundations, it is allowed to use carbon fiber mesh, individual rods and classic frames - all this refers to discrete reinforcement.

Dispersed allows for the direct addition of reinforcement scraps to concrete. Such reinforcement is used mainly in the construction of unloaded foundations.

The areas of application of alternative reinforcement extend to almost all areas of the construction of low-rise buildings and objects for various purposes, and especially to their foundations. The concrete poured into such foundations is called glass fiber concrete.

A separate branch of the use of non-metallic fittings can be called the arrangement of the adjacent space. This:

• Fences of flower beds, greenhouses and front gardens;
• Supports for individual flowers, shrubs and trees in the garden. Here, the color scheme of composite rods is of particular relevance;
• Composite rods are readily used in the construction of walls and partitions from gas and foam concrete blocks .

Fiberglass reinforcement screed

We choose, we calculate, we don’t make mistakes

State standard 31938-2012 regulates the main dimensions of non-metallic reinforcement, indicating both absolute values ​​and numbers of compliance with the classics - steel reinforcement.

One of the main differences between steel and plastic reinforcement bars is its geometry. If the metal one has a cross-section close to a circle, then the carbon fiber one has a cross-section close to an oval. In this case, the smaller size is called the “internal diameter”, and the larger one is called the “external diameter”. This is where difficulties begin in determining the required size. The generally accepted way out of this situation is to calculate average values.

On a note

Any options for one or another selling organization to convince you of a different payment procedure is a surefire reason to turn to their competitor.

As a clear example, we provide a comparison table for some ranges of fittings

Steel fittings GOST 5781-82	Composite reinforcement GOST 31938-2012
Diameter, mm	Sectional area, sq.mm	Tensile strength N/sq.mm	Inner diameter, mm	Sectional area, sq.mm	Tensile strength N/sq.mm
6	28,3	390	5,95	27,83	1100
8	50,3	390	7,15	40,1	1100
10	78,5	390	8,34	54,6	1100
12	113,1	390	9,53	71,26	1100
14	154	390	10,71	90,5	1100
16	201	390	11,92	111,33	1100

What is priority - fiberglass or steel?

This question is not simple and the answer to it most likely needs to be sought in a comparison of the main parameters. We will try to achieve certainty on this issue. So,

• Metal rods have elasticity and plasticity, while composite products have only elasticity;
• In terms of tensile strength, non-metallic products are several times higher than steel ones: 1300 and 390 MPa;
• Thermal conductivity coefficient for fiberglass: 0.35 W/m*C0 – and 46 for steel;
• The density of steel reinforcement is 7850 kg/m3, composite reinforcement is 1900 kg/m3;
• Fiberglass products are not afraid of corrosion, while for a competitor made of steel this is a real scourge;
• Fiberglass reinforcement is neutral to electric current, does not magnetize, which means it is ideal for rooms with radio equipment, and cannot be replaced in the construction of laboratories and technical centers;
• Fiberglass reinforcement practically does not bend, which limits its use in reinforcing floor slabs and other concrete products;
• As a result of the supply of non-metallic reinforcement in rolls, cost overruns during purchase and waste during installation are practically guaranteed.

Thus, with all the unique characteristics and physical indicators of composite reinforcement, we recommend using it for foundations with a great degree of caution. The use of non-metallic reinforcement for heavily loaded structures and areas where there is a high probability of destruction is prohibited. As for all other construction sites, here composite reinforcement has already confirmed its effectiveness and is the undisputed favorite.

Noteworthy information : Blind area around the house , Installation of a strip foundation with your own hands .

[tab:]

Source: https://stroitelinfo.ru/fundament/kompozitnaya-armatura

Reinforcement weight: table of specific gravity of 1 linear meter depending on diameter

20.05.2017

Reinforced concrete today is the most common material used in the construction of multi-story buildings, roads, tunnels, bridges and any other objects. Reinforcement is an important component of such structures - non-reinforced concrete, although it can withstand significant compressive loads, practically does not work in bending and tension, collapsing under relatively small loads.

But the use of metal rods - regular or prestressed - eliminates this drawback. Often builders find themselves in situations where they need to know the weight of reinforcement in order to calculate the required amount of material for construction. A table of reinforcement weights will help them with this.

You will find it below in the article, in the reinforcement table, the value of the mass of metal rods of all diameters is presented.

What does the mass of rods depend on?

Of course, first of all, the mass of the rod depends on the thickness. The larger the diameter, the greater the weight. Today, in construction, metal rods with a diameter of 6 to 80 millimeters are most often used.

The weight of 1 m of reinforcement, the thinnest, weighs only 222 grams, while for the thickest this figure is 39.46 kilograms. As you can see, the difference is huge.

Therefore, knowing the weight of the reinforcement will also not be superfluous when calculating the pressure of the structure on the foundation - several unaccounted tons of load can have a detrimental effect on the reliability and durability of any building.

How much does the fittings weigh?

In order to find out the reinforcement weight, the easiest and most convenient way is to use the special table presented below.

Rebar weight table

Diameter, mmWeight of 1 meter of reinforcement, kgLinear meters in ton

6	0,222	4504,5
8	0,395	2531,65
10	0,617	1620,75
12	0,888	1126,13
14	1,21	826,45
16	1,58	632,91
18	2	500
20	2,47	404,86
22	2,98	335,57
25	3,85	259,74
28	4,83	207,04
32	6,31	158,48
36	7,99	125,16
40	9,87	101,32
45	12,48	80,13
50	15,41	64,89
55	18,65	53,62
60	22,19	45,07
70	30,21	33,1
80	39,46	25,34

All data indicated in this table fully comply with the current GOST. The error can be a maximum of a few percent - such errors will not cause significant trouble and will certainly not cause damage to the structure.

Having a table at hand, you can quickly calculate the weight of reinforcement, for example, with a diameter of 32 mm. Find the corresponding diameter in the first column and immediately find out that its mass is 6.32 kg per 1 m, and a ton includes 158.48 meters.

Why do you need to know the weight?

Professional builders often have a question: what is the weight of a linear meter of reinforcement. Why do they need this? The fact is that when purchasing rods for the construction of large structures, it is not purchased individually, as in individual construction, but in tons.

But it’s difficult to calculate how long a certain mass of material will last if you don’t know how much a meter of reinforcement weighs. Knowing the total mass and specific gravity of the reinforcement, 1 meter, you can make simple calculations in a matter of seconds, obtaining the total length of the metal rods.

  To do this, we take the entire mass of the necessary rods and divide them by the weight of 1 linear meter.

Calculation example

To reinforce the beams, 2.5 tons of 25-diameter rods are required. We take the value of the mass of 1 meter from the table, equal to 3.85 kg. Next, we convert tons to kilograms, multiply by 1000, it will be 2500 kg, and divide by 3.85, we get 649 meters of material.

The standard length of a metal rod is 11.7 m, to find out the required number of rods, divide 649 by 11.7, we get 55.5 pieces. In this way, you can count the number of rods with any cross-section.

This will help, especially in private construction, to check that the correct amount of material has been delivered to you.

The opposite situation may also occur. The specialist knows how much material he needs, and also knows the optimal diameter. Having found out the theoretical weight of a meter of reinforcement, he just needs to multiply this number by the total length of the required metal rods to determine how much material is needed for construction.

Source: https://VseoArmature.ru/raschet/ves-armatury

Reinforcement weight 12 mm per meter

Reinforcement in construction is an important component when installing foundations and other supporting foundations. At the design stage, engineers calculate the required quantity based on the magnitude of the influencing forces and loads. As a rule, this preliminary calculation is made in meters. Suppliers almost always supply products in kilograms. In this regard, there is a need to quickly and accurately determine the weight of 12 mm reinforcement per meter.

General information

The fittings are pieces of rod with a ribbed surface. Thanks to these ribs, it is able to withstand higher bending loads compared to conventional rods. In most cases, bars are made from steel designed specifically for reinforcement.  

To calculate weight per unit meter, use the following methods:

• Online calculator.
• Special tables.
• Formulas of geometry and physics.

Let us now examine each point in more detail.

Online calculator

This is the easiest way to find out the weight of any rolled product. Online calculators are specially written programs for calculating the weight of reinforcement per unit meter. To make the calculation, you only need to enter the diameter of the rod and its length, and the program will calculate the weight itself.

The advantage of an online calculator is accuracy and speed. The downside is the need for a computer or other digital device connected to the Internet.

Finding these programs on the World Wide Web is not difficult. They are usually free and built into the website of most rental suppliers (circles, channels, etc.).

Reinforcement weight determination table

The second method is to use tables to find the mass of a rod per 1 meter. They are freely available on the Internet or can be found in special reference books on a variety of building and other materials.  

The table shows the mass of one linear meter of reinforcement of a given diameter. To find this value, you simply need to correlate the readings indicated in the rows and columns. Next, this number is multiplied by the number of meters we need and that’s it. Weight found.

How to find weight using formulas

In situations where there is neither the Internet nor a table at hand, the use of special formulas based on simple physical laws can help calculate the weight of reinforcement. The dependence of weight on length is as follows:

Weight of reinforcement = density*3.14*(radius of reinforcement)2*length

Steel reinforcement has a density of 7850 kg/m3. The radius is equal to half its diameter. When calculating weight, you should pay attention to the dimension. For greater clarity, let's consider a specific example.

This gives reinforcement with a diameter of 12 millimeters and a length of 10 meters. First, let's determine the radius. To do this, we convert it to a unit of meter and divide by 2. We get a value equal to 0.006 m. Then we simply substitute everything known into the formula:

Weight of reinforcement = 7850*3.14*0.006*0.006*10=8.8 kg

As you can see, this method is not complicated.

It is also worth considering that the actual weight of the reinforcement is always slightly different from the theoretical one. On average this is plus or minus 5%. The reason for this is that the rod itself has a slight deviation in size due to non-ideal production.

Source: https://prompriem.ru/stati/ves-armatury-12mm.html

Weight table for plastic fittings

Today on the market you can find both outdated steel reinforcement with a diameter of 6 to 80 mm, and new modern composite reinforcement made from the following materials: basalt plastic and fiberglass.

Metal products are highly susceptible to corrosion, rust and other chemical processes; they are heavy and not always convenient to transport.

But composite reinforcement is not subject to either physical or chemical influences, it is quite durable and much less is required compared to steel reinforcement.

As a result, the cost of construction where non-metallic reinforcement is used is significantly reduced (you can compare the price of plastic reinforcement with the price of metal reinforcement here). Therefore, using ASC for the construction of concrete structures is reasonable and profitable.

Many people know that when calculating the required amount of material for reinforcing concrete buildings and structures, it is necessary to use the equality of loads applied to all reinforcing elements. Replacing conventional steel reinforcement with a new composite material involves selecting a profile of fiberglass or basalt-plastic reinforcement. The profile must be of such a diameter that its strength is equal to the strength of conventional steel reinforcement of a given diameter.

Table of correspondence between the diameters of plastic reinforcement and steel reinforcement of class A3 (A400C) when replacing:

Steel reinforcement A3 (A400C), diameter	Plastic fittings, diameter
6 mm	4 mm
8 mm	6 mm
10 mm	8 mm
12 mm	8 mm
14 mm	10 mm
16 mm	12 mm
18 mm	14 mm
20 mm	16 mm
22 mm	18 mm
25 mm	20 mm

This table shows the weight of plastic reinforcement and steel reinforcement:

Reinforcement diameter	Weight of one linear meter of steel reinforcement (according to GOST 5781-82)	Weight of one linear meter of composite fiberglass reinforcement
6 mm	0.222 kg	0.049 kg
8 mm	0.503 kg	0.082 kg
10 mm	0.785 kg	0.134 kg
12 mm	1.131 kg	0.185 kg
14 mm	1.21 kg	0.276 kg
16 mm	1.58 kg	0.352 kg
18 mm	2.0 kg	0.44 kg

From the tables above it is clear that using plastic reinforcement is much more profitable than ordinary steel.

Return to list

Source: https://izh-reduktor.ru/about/art/article/tablica-vesov-plastikovoj-armatury.html

A12 mm fittings: characteristics, distinctive features, how much a linear meter weighs

Reinforcement refers to metal rods, rods or ropes of various shapes and cross-sections intended for construction work to fasten specialized structures. Reinforcement is indispensable in the manufacture of any types of devices made of reinforced concrete in order to enhance its strength.

According to its characteristics, it is divided into strength classes and comes in different diameters, which affects the effectiveness of its use in reinforced concrete building structures. This article will help answer the questions “How many meters are there in a ton of reinforcement?” and “How much does a meter of reinforcement weigh?”

In terms of labor costs in production, the presented rolled metal can be:

• light (with a diameter of up to 12 mm);
• heavy (with a diameter of 12 - 40 mm).

With a steel rod diameter of 12 mm, it is usually called reinforcement 12 ( A12 ) - this is the most popular rolled metal product in domestic construction.

Characteristics of A12 fittings

During the manufacturing process of A12, GOST 5781–82 is strictly observed, and according to its purpose it is classified into prestressed and non-prestressed . Based on the choice of production technology, the following types of fittings 12 are distinguished:

• cold drawn;
• hot rolled

Cold-drawn reinforcement A12 is necessary for the production of reinforced mesh; it is supplied in coils (rolls) of 6-12 meters and is a reinforcing wire.

Hot-rolled A12, being a high-quality type of rolled metal, is produced from steel with a rounded cross-section, and is used in the reinforcement of stressed and ordinary structures, imparts sufficient strength to reinforced concrete structures and prevents damage due to mechanical deformations.

Distinctive features of A12 fittings

These rolled metal products can be made from steel of different grades, which depends on its application and the requirements for its characteristics. Most often, products made from low-alloy structural steel are required. This is due to the fact that such products are easily subjected to arc welding.

The main purpose of A12 is the strengthening of reinforced concrete structures , as well as the formation of frame devices to resist increased loads. A diameter of 12 mm is the minimum for the construction of a strip foundation and its grillages, if you knit a reinforcement frame of four rods. Rentals by class are:

• smooth profile (without corrugation) - class A1;
• periodic profile (with transverse corrugation at an angle to the axis of the rod) - class A3.

This construction metal product is presented from the manufacturer in rods or coils . The scope of its application is very wide.

For the construction of the foundation, it is recommended to use hot-rolled reinforcement in the form of rods with oblique corrugation, the presence of which ensures optimal adhesion to concrete. This interaction of materials ensures the strength and durability of a reinforced concrete building structure.

The transverse arrangement of reinforced rods in the foundation prevents concrete cracking and reduces the force load on the resulting structure, and also protects it from deformation.

Advantages of A12 reinforcement , which are manifested in construction:

• high degree of strength;
• relatively high ductility;
• minimal susceptibility to corrosion;
• high resistance to thermal, chemical and mechanical influences;
• the ability to create various structural configurations by welding and mechanical connections;
• Possibility of use in stressed structures made of reinforced concrete.

There is currently a fairly large selection of grade steel on the construction raw materials market. Recently, there has been a gradual transition, using the example of Europe, to products made from A500C steel instead of the previously popular A400.

This fact, quite logically, is explained by the fact that while fully maintaining the quality characteristics of rolled products, its production cost is reduced by up to 10% due to savings in raw materials during construction operations.

For construction calculations, this amount of expenses is simply colossal.

A special feature of the production of rolled products from this steel grade is the absence of oxidation and, as a consequence, the absence of rust. At the same time, mechanical, chemical and thermal qualities remain at a very high level.

Replacement of steel grade A400 by grade A500C in rolled products makes it possible to reduce its concentration during concreting and, as a consequence, the consumption of A12 reinforcement. The technical characteristics of the steel used do not allow the welds of the finished structure to collapse.

All this leads to increased strength of floors, columns and walls of buildings.

Weight per linear meter of reinforcement 12

For construction work, it is customary to calculate the amount of reinforcement in linear meters, but it is sold mainly by weight.

It turns out that in order to buy the required amount of rolled metal and know exactly its cost, it is necessary to convert the calculated need in meters into weight units, that is, kilograms, tons, etc.

To do this, you can use the table presented . An alternative to the tabular data presented is to independently calculate the data based on the diameter size.

Diameter, mm	Diameter, m	Weight of 1 meter, kg	Quantity m in 1t
6	0.06	222	4504.5
8	0.08	395	2531.65
10	0.1	617	1620.75
12	0.12	888	1126.13
14	0.14	1210	826.45
16	0.16	1580	632.91
18	0.18	2000	500
20	0.2	2470	404.86
22	0.22	2980	335.57
25	0.25	3850	259.74
28	0.28	4830	207.04
32	0.32	6310	158.48
36	0.36	7990	125.16
40	0.4	9870	101.32

The weight of one meter of reinforced steel is shown in the table as the ratio of the diameter to its weight . Having information about the weight of reinforcing steel, it is possible to determine the coefficient of reinforcement of the structure (the ratio of the weight of rolled metal to the volume of concrete).

In order to calculate the need for reinforcement, you will need data on how many linear meters one ton of rolled metal contains. The number of meters in a ton is a value that depends on several factors. From the presented table it is clearly seen that the footage largely depends on the class of reinforcement.

How many meters are there in a ton of reinforcement 12?

In accordance with building regulations, the amount of reinforcement in a strip foundation as a percentage of the reinforced concrete element in the cross-section must be at least 0.1%. In an example it looks like this.

If the cross-sectional area of ​​the strip foundation is 100*240=2400 square cm, then the estimated number of rolled rods for longitudinal reinforcement is found by multiplying the resulting volume of the foundation by 0.001, that is, 2400*0.001=2.4 square cm.

Next, you should resort to the reference data in the table from the manual on the reinforcement of reinforced concrete elements of monolithic buildings. Since we are interested in reinforcement with a diameter of 12, it is obvious that only 2 reinforced rods are needed for the calculated volume of the foundation. The calculation of the consumption of reinforced steel for a slab foundation is similar.

Source: https://plita.guru/raboty/armirovanie/skolko-vesit-armatura-12-mm-i-ee-osobennosti.html

Weight of 1 meter of reinforcement - formula and table

During the construction process, an important parameter is the weight of the steel reinforcement, which is taken into account when designing the building. To calculate the mass of a batch of reinforcing bars, you need to know their diameter, mass per linear meter and total length.

Calculation of the weight of smooth and corrugated reinforcement: options

The mass of a linear meter of reinforcing bar can be determined in three ways: using the GOST 5781-82 , which determines the range of this metal product, using a formula and using an online calculator.

Determining the mass of reinforcing steel from the table

The table shows values ​​calculated using nominal diameters and an average steel density of 7850 kg/m3. The nominal diameter of a grooved rod is equal to the nominal diameter of a rod with a smooth surface of the same profile number. This means that the table shows the masses per linear meter of a certain profile number, suitable for both smooth and grooved reinforcement products.

Weight table, kg, 1 linear meter of reinforcement with smooth and corrugated surface of classes A1 and A3

Profile number (nominal rod diameter)	Theoretical mass 1 m, kg	Profile number (nominal rod diameter)	Theoretical mass 1 m, kg	Profile number (nominal rod diameter)	Theoretical mass 1 m, kg
6	0,222	20	2,47	45	12,48
8	0,395	22	2,98	50	15,41
10	0,617	25	3,85	55	18,65
12	0,888	28	4,83	60	22,19
14	1,21	32	6,31	70	30,21
16	1,58	36	7,99	80	39,46
18	2,00	40	9,87

To determine the mass of a batch of metal products, the mass of 1 linear meter is multiplied by the total footage.

Calculation by formula

M = π *( D 2 /4)* ρ , in which:

M – mass of 1 m, kg,

D – nominal diameter, m,

ρ – density equal to 7850 kg/m3.

Calculation using an online calculator

Determining the weight of reinforcement (kg) by diameter and total length using an online calculator is the simplest and most convenient option.

Source: https://TreydMetall.ru/info/ves-1-metra-armatury-formula-i-tablica

Reinforcement weight 12 mm per meter table

Appearance of fittings.

When knitting frames, meshes, as well as when constructing a foundation, the main element is reinforcement. As for private construction, one of the most in demand here is rolled metal with a diameter of 12 millimeters. The favorable ratio of strength and affordable price allows you to use 12 mm reinforcement in the construction of a private house.

Why do you need to know the weight of rolled metal? This value will be needed to estimate the cost of construction work at different stages. Usually the weight is already calculated in the project for each structure where rolled metal A12, A3 or any other grade is used.

If you plan to do the construction calculations yourself or just want to understand this point in detail, then this material will answer all your questions.

After studying the article, the reader will be able to independently carry out calculations and find out the weight of reinforcement 12 mm, A3 or another brand.

Weight calculation

The calculation is performed in linear meters - special quantities usually used in construction work. The table also shows the weight of one linear meter. At the same time, reinforcement is sold by weight, and not by length. The builder's task is quite simple: find out how many meters are required for all structures, and then convert them into units of mass. Below is a detailed and simple table that will help you find out the weight of one linear meter. Weight calculation

In this table you need to find the required diameter (D), in this case it is 12 mm. The second column shows D - this data is not particularly needed, and converting 12 mm is quite simple (you need to divide 12 mm by 100, the result is 0.12 m).

The third column of the table is the most important - the mass m per kg is indicated here. A meter of rolled metal equals 12 millimeters to 0.888 kilograms. Also, as an example, you can take 10 mm rods, the weight of which is 0.617 kg.

The last column shows how many meters there are in one ton.

Calculator

Self-calculation

Now the reader knows how much one meter weighs. But in order to better understand the work, you need to understand the scheme by which the calculation is carried out. Having understood the essence, the builder will be able to calculate the weight of one linear meter of rods with a diameter of 12 or 10 mm.

To perform the calculation, you must proceed according to the following scheme:

The volume of one linear meter can be obtained using the following formula: 1m x (0.785 x D x D). Here the letter "D" represents the diameter of the circle. The total mass is multiplied with the specific gravity of the rods; in all cases it will be 7850 kg/m3.

To find out how much a meter weighs, you need to know the volume.

For example, you can independently calculate the mass of one meter of 10 mm reinforcement. The first step is to obtain the volume - 1m x (0.785 x 0.010 x 0.010) = 0.00010124 m3. The mass of rods is 10 mm – 00010124 m3 x 7850 = 0.616 kg. If you look at the table, one meter of reinforcement 10 weighs 0.617 kg. How much a meter of rods 14 or 16 weighs can be found using the same scheme.

Number of meters in one ton

A more detailed table, where the steel class is also present.

Above is the calculation for 10 mm. The number of meters per ton can also be calculated without using specialized tables. Here it is worth referring to the building regulations, which state that the strip base must contain at least 0.1% of rods in relation to the reinforced concrete structure. This formulation looks quite complicated.

To understand how this works, it’s worth looking at an example:

1. A strip base is taken, the area of ​​which is 2400 square cm.
2. Next you will need a coefficient, for this formula it is 0.001.
3. The resulting volume is multiplied with a coefficient - 2400 x 0.001 = 2.4 cm2.
4. At the next stages, you won’t be able to do without reference information. Here you will need a manual that indicates the required number of rods.

   For reinforcement with a diameter of 10 and 12 mm, two rods are sufficient.

What you need to know about A12 fittings

Rods are made from steel, the grade of which depends on the requirements for strength, wear and other parameters. Typically, builders choose rods made of low-alloy metal. It cannot be said that this is the most reliable and durable steel, but it does have an important advantage - low-alloy metal can be processed using arc welding.

Grade A12, like reinforcement with a diameter of 10 mm, is usually used to add strength to a structure made of reinforced concrete. Also, these rods are the main element in the construction of frame structures. In addition to this parameter, you also need to pay attention to rental, it differs by class:

• Periodic profile – A3. Class A3 fittings have transverse corrugation.
• Smooth profile – A1. Unlike A3, class A1 fittings come without corrugation.

You can purchase reinforcement, regardless of diameter or class A3, in coils or rods.

Source: http://jsnip.ru/stroitelnye-materialy/ves-armatury-12-mm-za-metr.html

Reinforcement weight, weight table (weight) per 1 meter of reinforcement

When carrying out construction and installation work, calculating the mass of metal products is extremely important, since it allows you to estimate the final parameters of the structures being built and determine the cost of the material (for this, the weight of the reinforcement is taken to be 10 mm per meter).

To carry out calculations, you can use special tables that indicate the parameters of the rods and their estimated weight, as well as popular online calculators, for the use of which you need to know the exact data on the technical characteristics of rolled metal.

Knowing the exact weight of rolled materials, you can save a lot by choosing the right vehicle to transport them. If you are not sure that you can make the calculations correctly, the Regional House of Metal company will help you find out the weight of 12 mm reinforcement per meter with extreme accuracy, since they will calculate it using a special formula. View available types of foundation reinforcement.

Rebar weight table

You can find out what mass the product has - reinforcement 12 weight 1 meter - from the tables that indicate:

• weight of one linear m of product;
• number of rolled meters in one ton;
• rolled diameter in millimeters;
• cross-sectional area of ​​the rods in square centimeters;
• class of steel used in production.

Assortment	Weight 1 meter
Weight (theoretical), kg.	Limit deviations, %
6	0,222	+9 / -7
8	0,395
10	0,617	+5 / -6
12	0,888
14	1,21
16	1,58	+3 / -5
18	2,0
20	2,470
22	2,980
25	3,850
28	4,830
32	6,310	+3 / -4
36	7,990
40	9,870
45	12,480
50	15,410	+2 / -4
55	18,650
60	22,190
70	30,210
80	39,460

In most cases, using a table, you will be able to find the desired value. If the table did not help determine the weight of 16 mm reinforcement per meter, you can resort to using an online size calculator to make calculations. To use it, you need to know the following parameters: rolled diameter, rod length and number.

The calculator will calculate the total mass for one rod, the total length of the rods, and the volume in cubic meters. There are also calculators that rely on reference data for calculations. To use them, you need to know the GOST according to which the rolled products are manufactured, the material of manufacture and the assortment (name of the rolled products).

There are also products for which this tool is not suitable, one of such products is masonry mesh, the page of which can be found here.

Weight of reinforcement

What to do if you don’t have an online calculator at hand, and you don’t really trust the data from tables on the Internet? It’s simple - you can determine the weight of 8 mm reinforcement per meter yourself using the most common calculator.

To find out the mass of a linear meter of rolled metal, you need to determine the total length of the rods, and then multiply the specific gravity of a linear meter of the product by the number of meters. The formula used for calculation is: 1 m x (3.14 x D x D/4). By performing the actions in brackets, we obtain the geometric area of ​​a circle with a given diameter.

Did not you find what you were looking for? You may be interested in the page with pipeline valves, which can be found here: http://rdmetall.ru/truboprovodnaya-armatura/zatvory/.

Thus, we obtain the weight of a linear meter of reinforcement by multiplying the volume by the specific gravity of the product, equal to 7850 kilograms per cubic meter. An example of calculations for one m of a rod with a diameter of 8 millimeters.

Metal volume: 1 m x (3.14 x 0.008 m x 0.008 m/4) = 0.00005024. Specific gravity: 0.00005024 cubic meter x 7850 kilograms per cubic meter = 0.394384 kilograms.

You can substitute any value of D into the formula and obtain accurate data for any rolled metal, which will allow you to determine the cost of structures for construction.

Source: http://RDMetall.ru/armatura-dlya-fundamenta/ves-armatury/

Reinforcement length: standardized parameters and popular options

The construction of reinforced concrete structures is not complete without reinforcement. It ensures the creation of a strong frame that contributes to the elasticity of concrete. When creating a project, builders must calculate the volume of source material, including reinforcement. Its consumption depends on the length of the rod. What types of reinforcement exist, what length is considered standard and how to calculate the number of rods for the foundation.

Steel reinforcing bars

Types of rod reinforcement and their features

Rod reinforcement is divided into varieties in relation to the material used for the manufacture of elements. There is steel and composite. Steel reinforcement is classified into three categories based on production technology, purpose of use and alloy composition:

• Hot rolled - used for ordinary products, prestressed materials and reinforced concrete structures (GOST 5781-82);
• Thermo-mechanical - the manufactured rods are characterized by a high strength index and are used in reinforced concrete structures (GOST 10884-94);
• Weldable rods - suitable for reinforced concrete structures and products (GOST 52544-2006).

The composite type (GOST 31938-2006) is divided into two subtypes:

• Plastic AKS - made from glass roving compound obtained by polymerization of epoxy resin
• Basalt-plastic batteries - basalt-based polymers are used in production.

Basalt plastic materials are losing popularity in the market. Customers prefer to choose polymer plastic glass products.

Steel reinforcement, unlike fiberglass elements, is susceptible to corrosion, which reduces its service life. And also due to its greater weight, consumers prefer to refuse it.

Fiberglass ones are almost as expensive as steel products. Their lighter weight makes them easy to transport. Such fittings do not form corrosive compounds and do not react with alkalis, acids, or sea salt. But such elements are not subject to bending and eliminate the use of welding during installation. Steel types are stronger, but allow the rod to bend, which makes it easier to arrange a strip foundation.

Factors influencing the size of the reinforcement are:

• Standardized norms approved at the state level;
• Customer's wishes;
• Manufacturer's decision;
• Generally accepted dimensions of other products used in construction.

Primary steel reinforcement or composite materials are produced taking into account state standards. They, in turn, allow various errors when forming individual parties.

Length of rod reinforcement - all possible options regulated by GOSTs

Lengths of 12 m are more common on the market. But you can order longer rods with a length of 26 m. The length of the reinforcement varies in different ranges relative to the established GOST.

GOST 5781

The nominal value is 6-12 mm. The standards allow for deviations associated with the delivery of products in batches. There are 3 types known:

• The rods in the entire batch have a measured length;
• There are unmeasured segments in a measured batch;
• Party with unmeasured length.

If the batch is measured, then the length of the rod reinforcement is equal to a certain figure, which is included in the segment 6-12 mm. The customer or manufacturer chooses the desired length.

The fittings are delivered to the customer in this form.

In the presence of unmeasured segments (option 2), their length is at least 2 m. The total number of unmeasured segments does not exceed 15% of the mass of the entire batch.

Unmeasured batches are characterized by the presence of reinforcement with a length of 3-6 m. The percentage of rods is no more than 7%.

The standard does not exclude cases of supply of rods with a length of 5-25 m, when the customer and supplier previously agree on the dimensions of the products. GOST provides for maximum size deviations when cutting rods:

• Rods up to 6 m – deviation with normal accuracy +50 mm, and with increased accuracy +25 mm;
• Rods over 6 m - the length of the rods with normal accuracy deviates from the norm by 70 mm, and with increased accuracy by 35 mm upward.

Increased accuracy is observed in a situation where the customer requires production of the required length.

GOST 10884

The standard regulates the production of rods with a diameter of at least 10 mm. The length of the rod reinforcement ranges from 5.3-13.5 m. The standards provide for the production of products with a length of up to 26 m, when the delivery conditions are agreed with the consumer.

Weldable reinforcement belonging to class “C” is also produced in other length options. Lots may hold pieces of other lengths in accordance with the rules:

• Unmeasured rods in measured deliveries are produced with a length of more than 2 m and in an amount of 15% of the total mass of the batch;
• Unmeasured lots, in which the rods correspond to a length of 6-12 m, but it is possible to have segments of 3-6 m in a percentage of no more than 7% of the total weight of the lot.

GOST is characterized by deviations from standard values ​​with normal and increased accuracy. The errors correspond to the values ​​​​from GOST 5781 (described above).

GOST 52544-2006

The length of the fittings of this standard can vary between 6-12 m. The produced batches are divided into 2 types:

• Measuring – standard rods 6-12 m long, the length of which is agreed with the customer;
• Unmeasured - the length of the rods is selected by the manufacturer in the range of 6-12 m; the presence of shortened rods of 3-6 m is allowed in an amount of no more than 7% of the total mass of the batch.

The deviation error from standard dimensions cannot be more than 100 mm upward.

GOST 31938

The length of polymer-type fittings varies from 0.5 to 12 m. This is the standard size for measured batches. A dimensional step of 0.5 m has been approved, used in the manufacture of rods of other lengths. The standard does not exclude other variations, the length of which is greater than the established value.

Permissible deviations for the length of measuring rods:

• 0.5-6 m – 25 mm in the larger direction;
• 6-12 m – 35 mm more;
• More than 12 m - the error is +50 mm.

Since the plastic type is widely used in the construction of large objects in extreme conditions, manufacturers offer delivery in coils.

Sizes 12 fittings

A common option for constructing building structures made of reinforced concrete is reinforcement 12, which has a diameter of 12 mm.

Possible diameters of fiberglass reinforcement

It is made from various steel alloys. The diameter of this type meets the minimum requirements for the construction of buildings on a strip foundation when knitting a frame of 4 rods.

IMPORTANT! The most significant condition when constructing a foundation is considered to be the laying of reinforcement along a side of more than 3 m. The minimum diameter of the rods must be at least 12 mm.

Rolled products are grouped into classes regarding mechanical properties:

• A1 Smooth profile - has good ductility, which is required during elongation, providing stretching;
• A2 with a crescent pattern - thanks to the pattern, strength increases;
• A3 periodic profile - there is a cross section at an angle to the axis of the whip, which facilitates the welding of parts.

A3 fittings are popular. With a diameter of 12 mm, the weight of 1 m of profile is 0.888 kg. The cross-sectional area is 1.131 cm.

To determine the amount of reinforcement, the length in linear meters should be calculated. But on the market the material is supplied by weight. To calculate the required volume, it should be taken into account that a length of 1 m weighs 0.888 kg. Then 1 t contains 1126 m of reinforcement (12 mm in diameter). For other diameters, you can use special tables created taking into account the weight of 1 m of rolled stock for different parts. But an error may occur due to belonging to a different class.

Calculation of the amount of reinforcement

Manufacturers supply reinforcement with a length of 11.7 m. The value is justified by the waste of the part itself when laying overlapping. The useful length in this situation is 10 m. The remaining part will go to the ligament elements with the adjacent whip. The approximate volume of blanks for a strip foundation 50 m long is 20 pieces.

Important! The arrangement of a strip foundation involves the construction of 2 tiers of reinforcement. 2 tiers correspond to 4 rods.

If you need to calculate the total number of rods for the entire perimeter of the foundation, then you should add the amount of reinforcement for connections and lintels (vertical, horizontal). For example, in a building being constructed with 4 walls, 16 m of material will be required when laying 4 rods on one wall.

The use of reinforcement when constructing a foundation

The lintels are laid out at a distance of 0.5 m. The parameters of the reinforced frame lattice depend on the size of the foundation.

A foundation with a height of 600 mm and a width of 350 mm implies a distance between the bars in the lattice equal to 500 mm and 250 mm, respectively. So, with a foundation perimeter of 50 m, 100 ring-shaped transverse connections are obtained (50:0.5=100), having a perimeter of 1.5 m (0.5*2+0.25*2).

Then the total length of the rod will be 150 m (100 * 1.5). Taking into account waste, the total volume for lintels will be 157.5 m.

After calculating the volume of reinforcement, it is necessary to estimate the amount of wire for knitting elements in the strip foundation. The consumer can choose another knitting option - with a gun or welding.

The strength characteristics of reinforcing elements make it possible to build monolithic foundations, beams, arches and other important structures. The range of products is quite wide, which ensures a high-quality selection for individual objects. Knowing the parameters of the building or structure under construction, everyone can purchase fittings that are suitable in size and properties.

Source: https://viascio.ru/materialy/dlina-armatury-standartizirovannye-parametry

How much does reinforcement 28 weigh?

Promotion! Special offer when purchasing over 10 tons of products! Details of the promotion are here.

What is reinforcement 28 (see photo)? This is the most popular and frequently encountered rolled metal product, used to strengthen a variety of reinforced concrete and monolithic structures. The range of 28 mm reinforcement is represented by rods with smooth, mixed, crescent and ring profiles. This part provides strong adhesion to concrete, which increases the reliability of the structure.

Don’t know where to buy fittings 28 wholesale and retail from leading manufacturers and at the best prices? The Smolensk Metallurgical Plant company sells these metal products in Smolensk, the Smolensk region and neighboring regions. You can place an order for fittings 28 by calling qualified employees of the company.

Attention: The prices indicated in the price list are indicative only. Please check with the manager by calling or sending a request through the website. All the necessary information will be provided to you as soon as possible!

Please check with our managers for delivery costs to other regions.

Application

You can often see advertisements “I will buy fittings 28”. Due to their ability to reliably strengthen various structures, these metal products are widely used in construction, industry and other areas of the national economy. Most often these elements are used for:

• formation of walls, floors, foundations;
• monolithic construction;
• construction of reinforced concrete structures that can withstand heavy operating loads;
• creation of various welded structures;
• reinforcement of coastlines;
• construction of bridges and overpasses.

By making one call to our manager, you will find out how much 28 mm reinforcement costs, the parameters of the selected product, and you can cheaply buy 28 mm reinforcement at a price per ton.

Production of 28 mm fittings

For the manufacture of reinforcement 28, steel is used (low-carbon, unalloyed, etc.), the quality indicators of which allow it to be used to strengthen bridges, buildings, etc. The raw materials used to create rods also affect the cost of reinforcement 28.

The production of reinforcement 28 (GOST 5781-82) is carried out by hot and cold rolling from a round steel billet. As a result, cold-drawn wire or hot-rolled rod metal products are produced. They differ in their purpose (tensioned or non-tensioned) and profile (corrugated and smooth).

Technical characteristics of fittings with a diameter of 28 mm

The most commonly used grades of steel for the production of reinforcement are 28: a400s, a400, at800, a500s, 35gs.
Dimensions of fittings 28 mm:

• cross-section diameter – 28 mm;
• length – from 6 to 12 m.

The weight of reinforcement 28 mm (1 linear meter) depends on the metal chosen for its production, and on average is 4.8 kg. More detailed technical characteristics of 28 mm fittings can be clarified with the enterprise manager.

Peculiarities

The reliability of reinforced concrete objects largely depends on the quality of the reinforcing rods used in their creation. Therefore, such metal products have the following properties:

• significant fatigue strength and corrosion resistance;
• high rigidity of adhesion to building materials;
• minimum expansion in concrete;
• good weldability;
• high plasticity.

You can also purchase reinforcement 28 at a price per meter by simply filling out the online form.

Storage and transportation

Sale of fittings 28 in Smolensk, Smolensk region and its prompt delivery to the client will help to quickly complete the planned project. The order is delivered by rail and truck transport.

For better preservation of purchased rods, the Smolensk Metallurgical Plant recommends storing metal products in dry warehouses by placing elements of the same marking tied together on special racks capable of supporting a load weighing from 300 kg to 6 tons.

How to buy 28 mm fittings

Placing
an order Check the availability of 28 mm fittings and its price by calling 8 (4812) 548-604 or on the website (via the feedback form). Place an order, after which we will draw up a delivery agreement.

Payment Pay the cost of fittings f28 in one of the convenient ways: by bank transfer or in cash. For regular customers, deferred payment is possible.

Delivery or pickup Agree on the date of delivery/shipment from the warehouse. F28 fittings can be delivered by railway and road transport. Special equipment can be dispatched.

Acceptance
and unloading The order price includes 1 (one) hour for unloading by the buyer. After unloading, you will receive a complete set of documents.

About company

For more than 12 years, the Smolensk Metallurgical Plant LLC company has been actively working in the metal products market.

Professionalism of employees, passion, responsibility, thoughtfulness of actions, desire to offer you the best solutions to your problems - this is what characterizes the Smolensk Metallurgical Plant company as a worthy partner capable of satisfying the needs of the most demanding client.

• Smolensk Metallurgical Plant LLC - 12 years of experience in the market
• Attentive approach to your needs
• Flexible pricing system
• Additional services
• Prompt shipment and delivery
• Guarantee of quality and safety during transportation
• Pre-sale preparation
• Labeling, sorting, packaging

Our coordinates

Multichannel tel. 8 (4812) 548-604 Commercial department: [email protected]

Working hours: from 8:00 to 18:00

The weight of reinforcement with a diameter of 28 mm is given according to an extract from the assortment specified in GOST

If I understand correctly, then you are not interested in the weight of 25 mm reinforcement in general, but most likely the weight of one meter of reinforcement. This question could be asked in the Yandex PS a little differently: the weight of a meter of reinforcement is 28 mm, the weight of a linear meter of reinforcement is 28 mm, the conditional weight of reinforcement is 28 mm, the specific or theoretical weight of reinforcement is 28 mm, the calculated weight of reinforcement is 28 mm, and so on.

Despite the fact that these questions are formulated slightly differently, in general we are talking about the same thing. In fact, you want to calculate how much the 28 mm diameter reinforcement that you have in stock weighs, or the 28 mm reinforcement that you want to buy, but for some reason, it is not convenient for you to weigh the 28 mm reinforcement on a scale and it is more convenient to turn to reinforcement weight table. Such a table of reinforcement weights is in GOST for reinforcement.

From the reinforcement weight table, you need to find out the theoretical weight of one linear meter of reinforcement with a diameter of 28 mm.

Weight of reinforcement 6 mm diameter #8212; according to GOST

We did some not very complicated work for you, so that you do not need to download a free table of reinforcement weights or download the entire range of reinforcement, and we found the exact value of the mass of one linear meter of 28 mm reinforcement.

WEIGHT OF FITTINGS 28 mm #8212; is 4.83 kg per linear meter.

How to use the value you found now: the weight of reinforcement 6 mm in diameter?

In fact, using the table for calculating the weight of reinforcement is very simple and convenient, although it looks somewhat #171;intimidating#187; at first glance. There are quite detailed tables of the weight of linear meta reinforcement . taking into account different types of fittings according to GOST (there are actually three of them). I'll show you with an example. So, for example, you want to buy 25 meters of reinforcement with a diameter of 28 mm.

Perhaps you need to reinforce the foundation for a fence or solve some other construction problem. When selling 28 mm reinforcement, the seller usually sets the price of the reinforcement in tons; it is in tonnage that he buys it at the factory. He sells you 28 mm reinforcement in meters, in linear meters, of which you need exactly 25 m. That is, the price of 28 mm reinforcement per ton does not tell you anything at all.

In order to somehow convert the number of linear meters of 28 mm reinforcement you have into categories close to: price per ton of 28 mm reinforcement, you need to calculate how much your 25 meters of reinforcement with a diameter of 28 mm weigh. We find line #8212 in the table for calculating the weight of reinforcement; the weight of a linear meter of 28 mm reinforcement (we have already done this for you #8212; see above), opposite shows the weight value of a meter of 28 mm reinforcement in kilograms #8212; 4.83 kg.

Now, knowing the weight of one meter of reinforcement 28 mm, we must multiply it by the number of meters #8212; 4.83 x 25 = 120.75 kg. That is, your 25 linear meters weigh exactly 120.75 kg. This is the THEORETICAL WEIGHT OF A METER OF REINFORCEMENT 28 mm in diameter.

Source: https://armaturasila.ru/skolko-armatury/skolko-vesit-armatura-28.html

Reinforcement weight 28

Posted by admin on 07/11/2012

If I understand correctly, then you are not interested in the weight of 25 mm reinforcement in general, but most likely the weight of one meter of reinforcement. This question could be asked in the Yandex PS a little differently: the weight of a meter of reinforcement is 28 mm, the weight of a linear meter of reinforcement is 28 mm, the conditional weight of reinforcement is 28 mm, the specific or theoretical weight of reinforcement is 28 mm, the calculated weight of reinforcement is 28 mm, and so on.

Despite the fact that these questions are formulated slightly differently, in general we are talking about the same thing. In fact, you want to calculate how much the 28 mm diameter reinforcement that you have in stock weighs, or the 28 mm reinforcement that you want to buy, but for some reason, it is not convenient for you to weigh the 28 mm reinforcement on a scale and it is more convenient to turn to reinforcement weight table. Such a table of reinforcement weights is in GOST for reinforcement.

From the reinforcement weight table, you need to find out the theoretical weight of one linear meter of reinforcement with a diameter of 28 mm.

Weight of reinforcement 6 mm in diameter - according to GOST

We did some not very complicated work for you, so that you do not need to download a free table of reinforcement weights or download the entire range of reinforcement, and we found the exact value of the mass of one linear meter of 28 mm reinforcement.

WEIGHT OF FITTINGS 28 mm - is 4.83 kg per linear meter.

A3 fittings weight table

Reinforcement is an integral part of the foundation, from which, as a rule, any construction of a structure begins. It is also used to make reinforced concrete slabs, lamp posts and other reinforced concrete structures. The weight of A3 reinforcement directly depends on the rod diameter and length. Class 3 reinforcement requires special steel to create it, which includes 25G2S. It is excellent for areas of high seismic activity and also has excellent welding properties.

A distinctive factor of this class of reinforcement is the corrugated surface, due to which the adhesion to concrete is stronger, in contrast to reinforcement with a smooth surface. This brand has excellent characteristics in terms of compression and rupture, which prevents cracking of concrete and ensures a longer service life of reinforced concrete structures.

Characteristics and production technology of A3

This type of reinforcement is manufactured using the following methods:

1. reinforced by hood;
2. hot rolled;
3. thermally strengthened.

These rods are produced in unmeasured and measured sizes. The measured length consists of rods of 6 m and 11.7 m, and the unmeasured length is any piece of reinforcement up to 11.7 meters, but no more. The permissible percentage of unmeasured length in a batch is 10.

Today, the production of reinforcement is one of the main areas of modern metal rolling. This popularity is due to the fact that reinforcement is most often used in the construction industry. The weight of the A3 reinforcement also allows for framing work. The manufacturing process includes the following steps:

• reception and transportation of steel;
• editing;
• cleaning;
• cutting;
• flexible;
• welding meshes and frames, if necessary.

At large enterprises, production is fully automated, while small manufacturers work manually. Due to different labor costs, product costs may vary. Typically, the workshop has two lines where reinforcement is manufactured - for coils and rods. Finished products are stored on special racks in compliance with the required standards.

The table below shows the weight data per linear meter of A3 reinforcement.

The smallest diameter of class A3 rods is 6mm, and the largest is 40mm. Below is a table of the weight of A3 reinforcement.

Note: the numbers in brackets are the mass of the Bp-I rod.

If suddenly you don’t have a table at hand, the weight of the bar can be calculated as follows. First, let's find the volume: 1 m x (0.785 x D x D). In brackets, this is the geometric area of ​​a circle with diameter D and the specific gravity of reinforcement A3, which is equal to 7850 kg/m3.

For example, let’s calculate the weight of class A3 20mm reinforcement. So, volume calculation: 1(m)*(0.785*0.02*0.02) =0.000314 m3. Then the weight: 0.000314*7850=2.4649, which is approximately equal to the value in the table.

History of the emergence of A3 fittings

Initially, since the advent of reinforced concrete structures, reinforcement was not carried out. This technology became possible thanks to the florist from France Joseph Monier, who lived in the period 1823-1906.

Beginning in 1861, he was busy looking for strengthening garden tubs. And already in 1867, on July 16, he received his first patent in this field, which gave a shift in the development of reinforced concrete structures. Over time, scientists and builders took up the baton of his experiments and developments, which significantly improved the characteristics of the frame in reinforced concrete. Today we have A3 reinforcement in the form in which it is presented.

Varieties and applications

Class 3 fittings are made of low- and high-carbon steel with a diameter of 6-40mm. Due to the different conditions of use of such fittings, they are divided into two types:

• tense;
• relaxed.

It is believed that A3 12mm is the most popular in construction. The weight of 1 meter of A3 12mm reinforcement according to the table is only 0.888 grams. It is easy and convenient to work with, but at the same time it is rigid enough for knitting the frame and mesh. It is used for reinforcing permanent formwork. When constructing private houses or summer cottages, a strip foundation is used, where reinforcement of this diameter is used.

For designers, in order to estimate the cost of construction, it is extremely important to know the weight of a meter of A3 reinforcement. However, this value will have to be calculated if it is necessary to prepare a project or if it is necessary to change the diameter of the reinforcement bar, in the absence of the necessary one.

We remind you that all interested parties can easily place an order and buy fittings in Moscow using our website or by visiting us at Moscow, st. Raspletina 5, having previously agreed on the time and date.

Source: https://metavto.ru/poleznaya-informaciya/tablica-vesov-armatury-a3/