A3 fittings weight table
Reinforcement is an integral part of the foundation, from which, as a rule, any construction of a structure begins. It is also used to make reinforced concrete slabs, lamp posts and other reinforced concrete structures. The weight of A3 reinforcement directly depends on the rod diameter and length. Class 3 reinforcement requires special steel to create it, which includes 25G2S. It is excellent for areas of high seismic activity and also has excellent welding properties.
A distinctive factor of this class of reinforcement is the corrugated surface, due to which the adhesion to concrete is stronger, in contrast to reinforcement with a smooth surface. This brand has excellent characteristics in terms of compression and rupture, which prevents cracking of concrete and ensures a longer service life of reinforced concrete structures.
Characteristics and production technology of A3
This type of reinforcement is manufactured using the following methods:
- reinforced by hood;
- hot rolled;
- thermally strengthened.
These rods are produced in unmeasured and measured sizes. The measured length consists of rods of 6 m and 11.7 m, and the unmeasured length is any piece of reinforcement up to 11.7 meters, but no more. The permissible percentage of unmeasured length in a batch is 10.
Today, the production of reinforcement is one of the main areas of modern metal rolling. This popularity is due to the fact that reinforcement is most often used in the construction industry. The weight of the A3 reinforcement also allows for framing work. The manufacturing process includes the following steps:
- reception and transportation of steel;
- editing;
- cleaning;
- cutting;
- flexible;
- welding meshes and frames, if necessary.
At large enterprises, production is fully automated, while small manufacturers work manually. Due to different labor costs, product costs may vary. Typically, the workshop has two lines where reinforcement is manufactured - for coils and rods. Finished products are stored on special racks in compliance with the required standards.
The table below shows the weight data per linear meter of A3 reinforcement.
The smallest diameter of class A3 rods is 6mm, and the largest is 40mm. Below is a table of the weight of A3 reinforcement.
Note: the numbers in brackets are the mass of the Bp-I rod.
If suddenly you don’t have a table at hand, the weight of the bar can be calculated as follows. First, let's find the volume: 1 m x (0.785 x D x D). In brackets, this is the geometric area of a circle with diameter D and the specific gravity of reinforcement A3, which is equal to 7850 kg/m3.
For example, let’s calculate the weight of class A3 20mm reinforcement. So, volume calculation: 1(m)*(0.785*0.02*0.02) =0.000314 m3. Then the weight: 0.000314*7850=2.4649, which is approximately equal to the value in the table.
History of the emergence of A3 fittings
Initially, since the advent of reinforced concrete structures, reinforcement was not carried out. This technology became possible thanks to the florist from France Joseph Monier, who lived in the period 1823-1906.
Beginning in 1861, he was busy looking for strengthening garden tubs. And already in 1867, on July 16, he received his first patent in this field, which gave a shift in the development of reinforced concrete structures. Over time, scientists and builders took up the baton of his experiments and developments, which significantly improved the characteristics of the frame in reinforced concrete. Today we have A3 reinforcement in the form in which it is presented.
Varieties and applications
Class 3 fittings are made of low- and high-carbon steel with a diameter of 6-40mm. Due to the different conditions of use of such fittings, they are divided into two types:
- tense;
- relaxed.
It is believed that A3 12mm is the most popular in construction. The weight of 1 meter of A3 12mm reinforcement according to the table is only 0.888 grams. It is easy and convenient to work with, but at the same time it is rigid enough for knitting the frame and mesh. It is used for reinforcing permanent formwork. When constructing private houses or summer cottages, a strip foundation is used, where reinforcement of this diameter is used.
For designers, in order to estimate the cost of construction, it is extremely important to know the weight of a meter of A3 reinforcement. However, this value will have to be calculated if it is necessary to prepare a project or if it is necessary to change the diameter of the reinforcement bar, in the absence of the necessary one.
We remind you that all interested parties can easily place an order and buy fittings in Moscow using our website or by visiting us at Moscow, st. Raspletina 5, having previously agreed on the time and date.
Source: https://metavto.ru/poleznaya-informaciya/tablica-vesov-armatury-a3/
Reinforcement 16 a3 weight 1 meter
- Aluminium, duralumin
- Copper, bronze, brass
- Tin
- Lead
- Zinc
This data will help you when calculating construction costs. First, let's look at the most common GOST fittings DSTU 3760–98. There are at least 3 main GOST standards for fittings.
The weight of reinforcement for the foundation calculated using this formula coincides with the nominal values of GOST. Below are tables of reinforcement weights. In order to calculate the mass of 1 m of reinforcement, it is not necessary to use the reinforcement table, since it simply may not be at hand at the right time.
Reinforcement weight table.
Reinforcement 16 a3 weight 1 meter
Table of the mass and number of meters per ton of reinforcement according to GOST “DSTU 3760–98” In the process of performing construction work, an accurate calculation of the weight of the reinforcement and the number of meters of reinforcement per ton of weight is necessary. Such fittings are manufactured in the following classes: A240C with a smooth profile, and A1000 with a periodic profile.
Among them, the most common is “GOST DSTU 3760–98”, and “GOST R 52544”, as well as “GOST 5781-82”. The mass of 1 meter of reinforcement is equal to the theoretical mass of a circle of the same diameter, and is calculated using a simple formula: m = D x D x Pi/4 x ro, where ro is the density of the material, in this case 7850 kg/m 3, D is the diameter.
To calculate the foundation, you can use the foundation calculator.
Armature 16 a3 weight
see also
- 1 METER OF REINFORCEMENT WEIGHS Now the reader knows how much one meter weighs. Class A3 fittings have transverse corrugation. When knitting frames, meshes, as well as during construction
- 1 LINEAR METER OF REINFORCEMENT HOW MUCH WEIGHTS On the website of the metal warehouse "Aksvil" you can buy reinforcement in Minsk wholesale and retail. Weight of corrugated steel reinforcement A3. Reinforcement weight calculation table
- A III 10 ARMATURE WEIGHT We return to the school geometry course. If you need to calculate the mass of not one meter, but a specific reinforcing bar, the area of the circle will need
- REINFORCEMENT 1 METER WEIGHTThe weight is obtained by multiplying the volume by the specific weight of the reinforcement which is 7850 kg/m3. In the absence of a table, the weight of a linear meter of reinforcement can be calculated
- REINFORCEMENT 18 MM WEIGHT Approximately equal to the value in the table. Volume - 1 m x (0.785 x 0.012 m x 0.012 m) = 0.00011304 m3, Weight - 0.00011304 m3 x 7850 kg/m3 = 0.887 kg. However,
Source: https://trastmetal.ru/blog/armatura-16-a3-ves-1-metra
Weight of 1 meter of reinforcement - formula and table
During the construction process, an important parameter is the weight of the steel reinforcement, which is taken into account when designing the building. To calculate the mass of a batch of reinforcing bars, you need to know their diameter, mass per linear meter and total length.
Calculation of the weight of smooth and corrugated reinforcement: options
The mass of a linear meter of reinforcing bar can be determined in three ways: using the GOST 5781-82 , which determines the range of this metal product, using a formula and using an online calculator.
Determining the mass of reinforcing steel from the table
The table shows values calculated using nominal diameters and an average steel density of 7850 kg/m3. The nominal diameter of a grooved rod is equal to the nominal diameter of a rod with a smooth surface of the same profile number. This means that the table shows the masses per linear meter of a certain profile number, suitable for both smooth and grooved reinforcement products.
Weight table, kg, 1 linear meter of reinforcement with smooth and corrugated surface of classes A1 and A3
| Profile number (nominal rod diameter) | Theoretical mass 1 m, kg | Profile number (nominal rod diameter) | Theoretical mass 1 m, kg | Profile number (nominal rod diameter) | Theoretical mass 1 m, kg |
| 6 | 0,222 | 20 | 2,47 | 45 | 12,48 |
| 8 | 0,395 | 22 | 2,98 | 50 | 15,41 |
| 10 | 0,617 | 25 | 3,85 | 55 | 18,65 |
| 12 | 0,888 | 28 | 4,83 | 60 | 22,19 |
| 14 | 1,21 | 32 | 6,31 | 70 | 30,21 |
| 16 | 1,58 | 36 | 7,99 | 80 | 39,46 |
| 18 | 2,00 | 40 | 9,87 |
To determine the mass of a batch of metal products, the mass of 1 linear meter is multiplied by the total footage.
Calculation by formula
M = π *( D 2 /4)* ρ , in which:
M – mass of 1 m, kg,
D – nominal diameter, m,
ρ – density equal to 7850 kg/m3.
Calculation using an online calculator
Determining the weight of reinforcement (kg) by diameter and total length using an online calculator is the simplest and most convenient option.
Source: https://TreydMetall.ru/info/ves-1-metra-armatury-formula-i-tablica
Reinforcement: weight per linear meter, formulas and calculation examples
In the total cost of construction, a significant portion falls on the reinforcement of reinforced concrete structures. In retail sales, the price is per linear meter. However, when constructing a foundation, a large amount of reinforcement is required, so it is cheaper to purchase it at wholesale stores. And the wholesale price is indicated in rubles/ton of products. This means that linear meters must somehow be converted into tons.
State standards indicate the weight of one linear meter of reinforcement of a specific diameter. To calculate the required kilograms or tons, you need to multiply the weight of one meter by the total length of all rods of the same diameter. By weight, by the way, the percentage of reinforcement of a reinforced concrete structure is also determined (the ratio of the mass of metal and the volume of concrete).
How to use the table
The table shows:
- Reinforcement diameter
- Sectional area of the rod
- Weight of one linear meter
- Steel grade
First, in the “diameter of reinforcement” column, you find the product with which you are going to reinforce the structure, then, moving along the horizontal line of the table, you look for the weight of a linear meter.
Table - weight per linear meter of reinforcement
If you don't have a table at hand
Not everyone has the necessary GOST, but each of us studied at school. To independently calculate the weight of a linear meter, basic knowledge of mathematics and physics is sufficient. Everyone knows that mass is equal to the volume of a body multiplied by the specific gravity of the material. The volume is calculated using the formula:
V = F x L, where
- V – body volume, m3
- F – its cross-sectional area, m2
- L – body length, m
The cross section of the reinforcement is a circle. Its area is easy to calculate, knowing the diameter of the rod:
F = 3.14 x D2/ 4 = 0.785 x D2, where
- D – reinforcement diameter (in meters)
- 3.14 – the well-known constant value π (it is dimensionless)
As you can see, calculating the cross-sectional area and volume of the rod is not difficult. Now you can calculate the weight of a linear meter. This is also done simply, using the formula:
M = V xp, where
- p – specific gravity of steel. It is equal to 7850 kg/m3.
There is some inaccuracy in these calculations: the reinforcement is not a smooth rod, and we do not take into account the dimensions of the corrugations. But if you calculate the weight of a meter rod in this way and compare it with the tabular data, you will see that your result is not much different from them.
Calculation examples
As examples, let us consider calculating the weight of a linear meter of reinforcement with the most common diameters of 6 mm and 12 mm of class A III. This material has a periodic profile (longitudinal ribs and transverse protrusions are applied to its forming surface). Special steel is used to manufacture A3 reinforcement. Thanks to the complex surface, metal and concrete form a single monolith.
Reinforcement with a diameter of 6 and 12 mm is used in the construction of dachas, private houses - for reinforcing strip foundations.
- Let's calculate the weight of a linear meter of A3 reinforcement with a diameter of 6 mm:
- Sectional area F = 3.14 x 0.006 x 0.006/ 4 = 0.000028 m2
- Volume per linear meter V = 0.000028 m2 x 1m = 0.000028 m3
- Weight M = 0.000028 m3 x 7850 kg/m3 = 0.221 kg
- Let's calculate the weight of a linear meter of reinforcement with a diameter of 12 mm:
- Sectional area F = 3.14 x 0.012 x 0.012/ 4 = 0.000113 m2
- Volume per linear meter V = 0.000113 m2 x 1 m = 0.000113 m3
- Weight M = 0.000113 m3 x 7850 kg/m3 = 0.887 kg
According to the GOST table, weight is 1 linear. m of reinforcement 6 is 0.222 kg, reinforcement 12 is 0.888 kg. As you can see, the discrepancy in numbers is small. It must be admitted, however, that the data presented in the table also does not claim to be highly accurate. They were also calculated theoretically.
In fact, the actual weight of a linear meter may differ from the table by 0.2 - 3%, both plus and minus.
on how to calculate the weight of building reinforcement
The video shows examples of calculating the weight of reinforcement, and also shows the calculation process in an online calculator.
How to calculate the weight of reinforcement in the Masmat program. You can calculate the weight of a linear meter of reinforcement of 16 mm, 32 mm and any other diameter sizes.
Source: http://MegaBeaver.ru/materials/armatura/armatura-ves-pogonnogo-metra-formuly-i-primery-rascheta.html
Reinforcement weight, weight table (weight) per 1 meter of reinforcement
When carrying out construction and installation work, calculating the mass of metal products is extremely important, since it allows you to estimate the final parameters of the structures being built and determine the cost of the material (for this, the weight of the reinforcement is taken to be 10 mm per meter).
To carry out calculations, you can use special tables that indicate the parameters of the rods and their estimated weight, as well as popular online calculators, for the use of which you need to know the exact data on the technical characteristics of rolled metal.
Knowing the exact weight of rolled materials, you can save a lot by choosing the right vehicle to transport them. If you are not sure that you can make the calculations correctly, the Regional House of Metal company will help you find out the weight of 12 mm reinforcement per meter with extreme accuracy, since they will calculate it using a special formula. View available types of foundation reinforcement.
Rebar weight table
You can find out what mass the product has - reinforcement 12 weight 1 meter - from the tables that indicate:
- weight of one linear m of product;
- number of rolled meters in one ton;
- rolled diameter in millimeters;
- cross-sectional area of the rods in square centimeters;
- class of steel used in production.
| Assortment | Weight 1 meter | |
| Weight (theoretical), kg. | Limit deviations, % | |
| 6 | 0,222 | +9 / -7 |
| 8 | 0,395 | |
| 10 | 0,617 | +5 / -6 |
| 12 | 0,888 | |
| 14 | 1,21 | |
| 16 | 1,58 | +3 / -5 |
| 18 | 2,0 | |
| 20 | 2,470 | |
| 22 | 2,980 | |
| 25 | 3,850 | |
| 28 | 4,830 | |
| 32 | 6,310 | +3 / -4 |
| 36 | 7,990 | |
| 40 | 9,870 | |
| 45 | 12,480 | |
| 50 | 15,410 | +2 / -4 |
| 55 | 18,650 | |
| 60 | 22,190 | |
| 70 | 30,210 | |
| 80 | 39,460 |
In most cases, using a table, you will be able to find the desired value. If the table did not help determine the weight of 16 mm reinforcement per meter, you can resort to using an online size calculator to make calculations. To use it, you need to know the following parameters: rolled diameter, rod length and number.
The calculator will calculate the total mass for one rod, the total length of the rods, and the volume in cubic meters. There are also calculators that rely on reference data for calculations. To use them, you need to know the GOST according to which the rolled products are manufactured, the material of manufacture and the assortment (name of the rolled products).
There are also products for which this tool is not suitable, one of such products is masonry mesh, the page of which can be found here.
Weight of reinforcement
What to do if you don’t have an online calculator at hand, and you don’t really trust the data from tables on the Internet? It’s simple - you can determine the weight of 8 mm reinforcement per meter yourself using the most common calculator.
To find out the mass of a linear meter of rolled metal, you need to determine the total length of the rods, and then multiply the specific gravity of a linear meter of the product by the number of meters. The formula used for calculation is: 1 m x (3.14 x D x D/4). By performing the actions in brackets, we obtain the geometric area of a circle with a given diameter.
Did not you find what you were looking for? You may be interested in the page with pipeline valves, which can be found here: http://rdmetall.ru/truboprovodnaya-armatura/zatvory/.
Thus, we obtain the weight of a linear meter of reinforcement by multiplying the volume by the specific gravity of the product, equal to 7850 kilograms per cubic meter. An example of calculations for one m of a rod with a diameter of 8 millimeters.
Metal volume: 1 m x (3.14 x 0.008 m x 0.008 m/4) = 0.00005024. Specific gravity: 0.00005024 cubic meter x 7850 kilograms per cubic meter = 0.394384 kilograms.
You can substitute any value of D into the formula and obtain accurate data for any rolled metal, which will allow you to determine the cost of structures for construction.
Source: http://RDMetall.ru/armatura-dlya-fundamenta/ves-armatury/
Normal weight during pregnancy: how many kilograms should the expectant mother gain | Abortion in St. Petersburg
In modern obstetrics, weight during pregnancy is one of the main indicators. Weight gain during pregnancy depends on how much the expectant mother weighed before conception. Therefore, you need to take care of the correct weight when planning a pregnancy. This will help avoid health problems for both mother and child.
Does the mother's weight matter for the proper development of the fetus?
Experts emphasize that for optimal fetal development, both the correct weight of the mother before conception and adequate weight gain during pregnancy are of great importance.
If you are overweight, both before and during pregnancy, the woman and child are exposed to serious health problems, including the possible development of the following pathologies:
- diabetes in a child;
- maternal diabetes;
- hypertension in a pregnant woman;
- excessive weight of the newborn;
- maternal and child obesity;
- premature birth;
- varicose veins in the mother;
- hemorrhoids during pregnancy.
Maternal underweight and too little weight gain are also not an indicator of good health. In this situation, the child is susceptible to developmental problems, low birth weight, diabetes and hypertension later in life. And the mother is susceptible to anemia and hormonal problems, leading to premature birth.
How many kilograms can you gain during pregnancy?
During pregnancy, a woman's body undergoes a number of significant changes, the purpose of which is to provide the best conditions for the proper development of the child. One of the most noticeable changes is weight gain during pregnancy and a growing belly.
Weight gain
It is generally accepted that the increase in body weight of a pregnant woman during the entire pregnancy should be within 9-15 kg. But pregnancy weight is neither fat nor muscle.
At the end of pregnancy, the weight gained is distributed as follows:
- Baby - 3.5 kg;
- Uterus - 2 kg;
- Amniotic fluid - 3 kg;
- Placenta - 0.5-1.5 kg;
- Chest - 1-3 kg;
- Fat - 2-5 kg.
It should be noted that weight gain parameters for each woman may be different.
What determines weight during pregnancy?
The following factors influence a pregnant woman’s kilograms:
- Lifestyle;
- diet;
- medical history;
- genetics;
- woman's age;
- weight before pregnancy;
- tendency to obesity, edema.
Weight during pregnancy by trimester
Women who were thin before pregnancy can afford to gain a little more extra pounds.
Table: what weight should be during pregnancy in different trimesters
| Weight before pregnancy | Weight gain during pregnancy | Weight in individual trimesters of pregnancy |
| 40-50 kg | 14-18 kg | 1st trimester - approx. 4; 2nd trimester - approx. 6;3 trimester - approx. 4 |
| 50-60 kg | 13-15 kg | 1st trimester - approx. 3;2 trimester - approx. 6;3 trimester - approx. 4 |
| 60-80 kg | 11-12 kg | 1st trimester - approx. 2;2 trimester - approx. 5;3I trimester - approx. 4 |
| Over 90 kg | 9-11 kg | 1st trimester - approx. 2;2 trimester - approx. 4; III trimester - approx. 3 |
Often pregnant women believe in the myth that if you eat for two, the child will be born big and strong. In fact, the child's weight is not directly related to the mother's weight. It mainly depends on genetic factors and the woman's diet.
What are the dangers of underweight fetuses?
Low birth weight of a child contributes to:
- perinatal injuries;
- psychomotor development delays;
- epilepsy;
- hyperactivity and learning problems.
Why is high weight dangerous for the fetus?
High birth weight increases the risks of:
- perinatal injuries;
- disturbances in the absorption of fats and carbohydrates;
- obesity;
- diabetes mellitus;
- cardiovascular diseases.
How to calculate pregnancy weight
The most commonly used indicator of weight gain to assess whether an expectant mother is weighing enough is body mass index, which is calculated by dividing the weight in kilograms by the square of the height in meters.
Normal weight gain during pregnancy depends on pre-pregnancy BMI:
| BMI | Norm | Weight gain in a pregnant woman |
| 30 kg/m2 before pregnancy | obesity | + 5 – 9 kg throughout pregnancy |
Experts recommend that the expectant mother discuss with her gynecologist all issues related to weight gain during pregnancy, diet and physical activity.
It may be that due to health conditions, the recommended weight gain will differ from the above. For example, overweight or obese pregnant women with gestational diabetes experience weight gain much faster.
How to avoid getting fat during pregnancy
To maintain a normal weight during pregnancy, you need to lead a healthy lifestyle and move a lot. If there are no medical contraindications, the expectant mother should do gymnastics, swimming, and walk a lot. Exercising during pregnancy will help you avoid unnecessary weight and prepare your body for childbirth. Women who follow these recommendations get back into shape faster after childbirth.
Source: https://abort-spb.ru/normalnyj-ves-pri-beremennosti/
Reinforcement weight 12 mm per meter table
Appearance of fittings.
When knitting frames, meshes, as well as when constructing a foundation, the main element is reinforcement. As for private construction, one of the most in demand here is rolled metal with a diameter of 12 millimeters. The favorable ratio of strength and affordable price allows you to use 12 mm reinforcement in the construction of a private house.
Why do you need to know the weight of rolled metal? This value will be needed to estimate the cost of construction work at different stages. Usually the weight is already calculated in the project for each structure where rolled metal A12, A3 or any other grade is used.
If you plan to do the construction calculations yourself or just want to understand this point in detail, then this material will answer all your questions.
After studying the article, the reader will be able to independently carry out calculations and find out the weight of reinforcement 12 mm, A3 or another brand.
Weight calculation
The calculation is performed in linear meters - special quantities usually used in construction work. The table also shows the weight of one linear meter. At the same time, reinforcement is sold by weight, and not by length. The builder's task is quite simple: find out how many meters are required for all structures, and then convert them into units of mass. Below is a detailed and simple table that will help you find out the weight of one linear meter. Weight calculation
In this table you need to find the required diameter (D), in this case it is 12 mm. The second column shows D - this data is not particularly needed, and converting 12 mm is quite simple (you need to divide 12 mm by 100, the result is 0.12 m).
The third column of the table is the most important - the mass m per kg is indicated here. A meter of rolled metal equals 12 millimeters to 0.888 kilograms. Also, as an example, you can take 10 mm rods, the weight of which is 0.617 kg.
The last column shows how many meters there are in one ton.
Calculator
Self-calculation
Now the reader knows how much one meter weighs. But in order to better understand the work, you need to understand the scheme by which the calculation is carried out. Having understood the essence, the builder will be able to calculate the weight of one linear meter of rods with a diameter of 12 or 10 mm.
To perform the calculation, you must proceed according to the following scheme:
The volume of one linear meter can be obtained using the following formula: 1m x (0.785 x D x D). Here the letter "D" represents the diameter of the circle. The total mass is multiplied with the specific gravity of the rods; in all cases it will be 7850 kg/m3.
To find out how much a meter weighs, you need to know the volume.
For example, you can independently calculate the mass of one meter of 10 mm reinforcement. The first step is to obtain the volume - 1m x (0.785 x 0.010 x 0.010) = 0.00010124 m3. The mass of rods is 10 mm – 00010124 m3 x 7850 = 0.616 kg. If you look at the table, one meter of reinforcement 10 weighs 0.617 kg. How much a meter of rods 14 or 16 weighs can be found using the same scheme.
Number of meters in one ton
A more detailed table, where the steel class is also present.
Above is the calculation for 10 mm. The number of meters per ton can also be calculated without using specialized tables. Here it is worth referring to the building regulations, which state that the strip base must contain at least 0.1% of rods in relation to the reinforced concrete structure. This formulation looks quite complicated.
To understand how this works, it’s worth looking at an example:
- A strip base is taken, the area of which is 2400 square cm.
- Next you will need a coefficient, for this formula it is 0.001.
- The resulting volume is multiplied with a coefficient - 2400 x 0.001 = 2.4 cm2.
- At the next stages, you won’t be able to do without reference information. Here you will need a manual that indicates the required number of rods.
For reinforcement with a diameter of 10 and 12 mm, two rods are sufficient.
What you need to know about A12 fittings
Rods are made from steel, the grade of which depends on the requirements for strength, wear and other parameters. Typically, builders choose rods made of low-alloy metal. It cannot be said that this is the most reliable and durable steel, but it does have an important advantage - low-alloy metal can be processed using arc welding.
Grade A12, like reinforcement with a diameter of 10 mm, is usually used to add strength to a structure made of reinforced concrete. Also, these rods are the main element in the construction of frame structures. In addition to this parameter, you also need to pay attention to rental, it differs by class:
- Periodic profile – A3. Class A3 fittings have transverse corrugation.
- Smooth profile – A1. Unlike A3, class A1 fittings come without corrugation.
You can purchase reinforcement, regardless of diameter or class A3, in coils or rods.
Source: http://jsnip.ru/stroitelnye-materialy/ves-armatury-12-mm-za-metr.html
Reinforcement weight: table of specific gravity of 1 linear meter depending on diameter
20.05.2017
Reinforced concrete today is the most common material used in the construction of multi-story buildings, roads, tunnels, bridges and any other objects. Reinforcement is an important component of such structures - non-reinforced concrete, although it can withstand significant compressive loads, practically does not work in bending and tension, collapsing under relatively small loads.
But the use of metal rods - regular or prestressed - eliminates this drawback. Often builders find themselves in situations where they need to know the weight of reinforcement in order to calculate the required amount of material for construction. A table of reinforcement weights will help them with this.
You will find it below in the article, in the reinforcement table, the value of the mass of metal rods of all diameters is presented.
What does the mass of rods depend on?
Of course, first of all, the mass of the rod depends on the thickness. The larger the diameter, the greater the weight. Today, in construction, metal rods with a diameter of 6 to 80 millimeters are most often used.
The weight of 1 m of reinforcement, the thinnest, weighs only 222 grams, while for the thickest this figure is 39.46 kilograms. As you can see, the difference is huge.
Therefore, knowing the weight of the reinforcement will also not be superfluous when calculating the pressure of the structure on the foundation - several unaccounted tons of load can have a detrimental effect on the reliability and durability of any building.
How much does the fittings weigh?
In order to find out the reinforcement weight, the easiest and most convenient way is to use the special table presented below.
Rebar weight table
Diameter, mmWeight of 1 meter of reinforcement, kgLinear meters in ton| 6 | 0,222 | 4504,5 |
| 8 | 0,395 | 2531,65 |
| 10 | 0,617 | 1620,75 |
| 12 | 0,888 | 1126,13 |
| 14 | 1,21 | 826,45 |
| 16 | 1,58 | 632,91 |
| 18 | 2 | 500 |
| 20 | 2,47 | 404,86 |
| 22 | 2,98 | 335,57 |
| 25 | 3,85 | 259,74 |
| 28 | 4,83 | 207,04 |
| 32 | 6,31 | 158,48 |
| 36 | 7,99 | 125,16 |
| 40 | 9,87 | 101,32 |
| 45 | 12,48 | 80,13 |
| 50 | 15,41 | 64,89 |
| 55 | 18,65 | 53,62 |
| 60 | 22,19 | 45,07 |
| 70 | 30,21 | 33,1 |
| 80 | 39,46 | 25,34 |
All data indicated in this table fully comply with the current GOST. The error can be a maximum of a few percent - such errors will not cause significant trouble and will certainly not cause damage to the structure.
Having a table at hand, you can quickly calculate the weight of reinforcement, for example, with a diameter of 32 mm. Find the corresponding diameter in the first column and immediately find out that its mass is 6.32 kg per 1 m, and a ton includes 158.48 meters.
Why do you need to know the weight?
Professional builders often have a question: what is the weight of a linear meter of reinforcement. Why do they need this? The fact is that when purchasing rods for the construction of large structures, it is not purchased individually, as in individual construction, but in tons.
But it’s difficult to calculate how long a certain mass of material will last if you don’t know how much a meter of reinforcement weighs. Knowing the total mass and specific gravity of the reinforcement, 1 meter, you can make simple calculations in a matter of seconds, obtaining the total length of the metal rods.
To do this, we take the entire mass of the necessary rods and divide them by the weight of 1 linear meter.
Calculation example
To reinforce the beams, 2.5 tons of 25-diameter rods are required. We take the value of the mass of 1 meter from the table, equal to 3.85 kg. Next, we convert tons to kilograms, multiply by 1000, it will be 2500 kg, and divide by 3.85, we get 649 meters of material.
The standard length of a metal rod is 11.7 m, to find out the required number of rods, divide 649 by 11.7, we get 55.5 pieces. In this way, you can count the number of rods with any cross-section.
This will help, especially in private construction, to check that the correct amount of material has been delivered to you.
The opposite situation may also occur. The specialist knows how much material he needs, and also knows the optimal diameter. Having found out the theoretical weight of a meter of reinforcement, he just needs to multiply this number by the total length of the required metal rods to determine how much material is needed for construction.
Source: https://VseoArmature.ru/raschet/ves-armatury
